Complete the table to compare z and t distributions. \[\begin{array} { | l | l | l | } \hline & \text { z distribution } & \text { t distribution } \\ \hline \text { Shape } & & \\ \hline \text { Mean value } & & \\ \hline \text { Standard deviation value } & & \\ \hline \text { Requirements } & & \\ \hline \end{array}\]

\[\begin{array} { | l | l | l | } \hlin

Exam 7: Estimates and Sample Sizes

Use the confidence level and sample data to find a confidence interval for estimating the population µ. -Test scores: $\mathrm { n } = 71 , \overline { \mathrm { x } } = 41.8 , \sigma = 7.2 ; 98$ percent

(Multiple Choice)

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Question 101

Solve the problem. -Of 86 adults selected randomly from one town, 63 have health insurance. Find a 90% confidence interval for the true proportion of all adults in the town who have health insurance.

(Multiple Choice)

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Question 102

Solve the problem. -A study involves 634 randomly selected deaths, with 32 of them caused by accidents. Construct a 98% confidence interval for the true percentage of all deaths that are caused by accidents.

(Multiple Choice)

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Question 103

Use the given degree of confidence and sample data to construct a confidence interval for the population proportion p -Margin of error: $0.05$ ; confidence level: $95 \% ; \hat { \mathrm { p } }$ and $\hat { q }$ unknown

(Multiple Choice)

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Question 104

Complete the table to compare z and t distributions. z distribution t distribution Shape Mean value Standard deviation value Requirements

(Essay)

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Question 105

Find the margin of error. -To be able to say with 95% confidence level that the standard deviation of a data set is within 20% of the population's standard deviation, the number of observations within the data set must be greater than or equal to what quantity?

(Multiple Choice)

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Question 106

Use the confidence level and sample data to find a confidence interval for estimating the population µ. -A random sample of 79 light bulbs had a mean life of $x = 400$ hours with a standard deviation of $\sigma = 28$ hours. Construct a 90 percent confidence interval for the mean life, $\mu$ , of all light bulbs of this type.

(Multiple Choice)

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Question 107

Provide an appropriate response. - $\text { Under what circumstances can you replace } \sigma \text { with } s \text { in the formula } E = z \alpha / 2 \cdot \frac { \sigma } { \sqrt { n } } \text {. }$

(Essay)

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Question 108

Use the given degree of confidence and sample data to construct a confidence interval for the population proportion p -Margin of error: $0.07$ ; confidence level: $90 \%$ ; from a prior study, $\hat{\mathrm { p }}$ is estimated by $0.19$ .

(Multiple Choice)

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Question 109

Solve the problem. -A survey of 865 voters in one state reveals that 408 favor approval of an issue before the legislature. Construct the 95% confidence interval for the true proportion of all voters in the state who favor approval.

(Multiple Choice)

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Question 110

Solve the problem. -Of 129 randomly selected adults, 32 were found to have high blood pressure. Construct a 95% confidence interval for the true percentage of all adults that have high blood pressure.

(Multiple Choice)

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Question 111

Use the given degree of confidence and sample data to construct a confidence interval for the population proportion p -Margin of error: $0.025$ ; confidence level: $96 \% ; \hat { \mathrm { p } }$ and $\hat { \mathrm { q } }$ are unknown

(Multiple Choice)

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Question 112

$\text { Find the critical value } \mathrm { z } _ { \alpha / 2 } \text { that corresponds to a degree of confidence of } 98 \% \text {. }$

(Multiple Choice)

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Question 113

Find the margin of error for the 95% confidence interval used to estimate the population proportion -n = 58, x = 28; 95 percent

(Multiple Choice)

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Question 114

Solve the problem. -In a certain population, body weights are normally distributed with a mean of 152 pounds and a standard deviation of 26 pounds. How many people must be surveyed if we want to estimate the percentage who weigh more than 180 pounds? Assume that we want 96% confidence that the error is no more than 2 percentage points.

(Multiple Choice)

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Question 115

Solve the problem. -50 people are selected randomly from a certain population and it is found that 20 people in the sample are over 6 feet tall. What is the point estimate of the true proportion of people in the population who are over 6 feet tall?

(Multiple Choice)

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Question 116

Solve the problem. -Of 357 randomly selected medical students, 30 said that they planned to work in a rural community. Find a 95% confidence interval for the true proportion of all medical students who plan to work in a rural community.

(Multiple Choice)

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Question 117

$\text { Find the critical value } \mathrm { z } \alpha / 2 \text { that corresponds to a degree of confidence of } 91 \% \text {. }$

(Multiple Choice)

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Question 118

Use the confidence level and sample data to find a confidence interval for estimating the population µ. -A random sample of 144 full-grown lobsters had a mean weight of 18 ounces and a standard deviation of $2.9$ ounces. Construct a 98 percent confidence interval for the population mean $\mu$ .

(Multiple Choice)

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Question 119

Solve the problem. -Find the critical value $\chi _ { R } ^ { 2 }$ corresponding to a sample size of 11 and a confidence level of 90 percent.

(Multiple Choice)

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Question 120

Use the confidence level and sample data to find a confidence interval for estimating the population µ. -Test scores: $\mathrm { n } = 71 , \overline { \mathrm { x } } = 41.8 , \sigma = 7.2 ; 98$ percent

Solve the problem. -Of 86 adults selected randomly from one town, 63 have health insurance. Find a 90% confidence interval for the true proportion of all adults in the town who have health insurance.

Solve the problem. -A study involves 634 randomly selected deaths, with 32 of them caused by accidents. Construct a 98% confidence interval for the true percentage of all deaths that are caused by accidents.

Use the given degree of confidence and sample data to construct a confidence interval for the population proportion p -Margin of error: $0.05$ ; confidence level: $95 \% ; \hat { \mathrm { p } }$ and $\hat { q }$ unknown

Complete the table to compare z and t distributions. z distribution t distribution Shape Mean value Standard deviation value Requirements

Find the margin of error. -To be able to say with 95% confidence level that the standard deviation of a data set is within 20% of the population's standard deviation, the number of observations within the data set must be greater than or equal to what quantity?

Provide an appropriate response. - $\text { Under what circumstances can you replace } \sigma \text { with } s \text { in the formula } E = z \alpha / 2 \cdot \frac { \sigma } { \sqrt { n } } \text {. }$

Use the given degree of confidence and sample data to construct a confidence interval for the population proportion p -Margin of error: $0.07$ ; confidence level: $90 \%$ ; from a prior study, $\hat{\mathrm { p }}$ is estimated by $0.19$ .

Solve the problem. -A survey of 865 voters in one state reveals that 408 favor approval of an issue before the legislature. Construct the 95% confidence interval for the true proportion of all voters in the state who favor approval.

Solve the problem. -Of 129 randomly selected adults, 32 were found to have high blood pressure. Construct a 95% confidence interval for the true percentage of all adults that have high blood pressure.

Use the given degree of confidence and sample data to construct a confidence interval for the population proportion p -Margin of error: $0.025$ ; confidence level: $96 \% ; \hat { \mathrm { p } }$ and $\hat { \mathrm { q } }$ are unknown

$\text { Find the critical value } \mathrm { z } _ { \alpha / 2 } \text { that corresponds to a degree of confidence of } 98 \% \text {. }$

Find the margin of error for the 95% confidence interval used to estimate the population proportion -n = 58, x = 28; 95 percent

Solve the problem. -50 people are selected randomly from a certain population and it is found that 20 people in the sample are over 6 feet tall. What is the point estimate of the true proportion of people in the population who are over 6 feet tall?

Solve the problem. -Of 357 randomly selected medical students, 30 said that they planned to work in a rural community. Find a 95% confidence interval for the true proportion of all medical students who plan to work in a rural community.

$\text { Find the critical value } \mathrm { z } \alpha / 2 \text { that corresponds to a degree of confidence of } 91 \% \text {. }$

Use the confidence level and sample data to find a confidence interval for estimating the population µ. -A random sample of 144 full-grown lobsters had a mean weight of 18 ounces and a standard deviation of $2.9$ ounces. Construct a 98 percent confidence interval for the population mean $\mu$ .

Solve the problem. -Find the critical value $\chi _ { R } ^ { 2 }$ corresponding to a sample size of 11 and a confidence level of 90 percent.

Introduction to Statistics

Summarizing and Graphing Data

Statistics for Describing, Exploring, and Comparing Data

Probability

Probability Distributions

Normal Probability Distributions

Hypothesis Testing

Inferences From Two Samples

Correlation and Regression

Multinomial Experiments and Contingency Tables

Analysis of Variance

Nonparametric Statistics

Statistical Process Control

Filters

Exam 7: Estimates and Sample Sizes

Use the confidence level and sample data to find a confidence interval for estimating the population µ. -Test scores: n=71,x‾=41.8,σ=7.2;98\mathrm { n } = 71 , \overline { \mathrm { x } } = 41.8 , \sigma = 7.2 ; 98n=71,x=41.8,σ=7.2;98 percent

Solve the problem. -Of 86 adults selected randomly from one town, 63 have health insurance. Find a 90% confidence interval for the true proportion of all adults in the town who have health insurance.

Solve the problem. -A study involves 634 randomly selected deaths, with 32 of them caused by accidents. Construct a 98% confidence interval for the true percentage of all deaths that are caused by accidents.

Use the given degree of confidence and sample data to construct a confidence interval for the population proportion p -Margin of error: 0.050.050.05 ; confidence level: 95%;p^95 \% ; \hat { \mathrm { p } }95%;p^​ and q^\hat { q }q^​ unknown

Complete the table to compare z and t distributions. z distribution t distribution Shape Mean value Standard deviation value Requirements

Find the margin of error. -To be able to say with 95% confidence level that the standard deviation of a data set is within 20% of the population's standard deviation, the number of observations within the data set must be greater than or equal to what quantity?

Use the given degree of confidence and sample data to construct a confidence interval for the population proportion p -Margin of error: 0.070.070.07 ; confidence level: 90%90 \%90% ; from a prior study, p^\hat{\mathrm { p }}p^​ is estimated by 0.190.190.19 .

Solve the problem. -A survey of 865 voters in one state reveals that 408 favor approval of an issue before the legislature. Construct the 95% confidence interval for the true proportion of all voters in the state who favor approval.

Solve the problem. -Of 129 randomly selected adults, 32 were found to have high blood pressure. Construct a 95% confidence interval for the true percentage of all adults that have high blood pressure.

Use the given degree of confidence and sample data to construct a confidence interval for the population proportion p -Margin of error: 0.0250.0250.025 ; confidence level: 96%;p^96 \% ; \hat { \mathrm { p } }96%;p^​ and q^\hat { \mathrm { q } }q^​ are unknown

Find the margin of error for the 95% confidence interval used to estimate the population proportion -n = 58, x = 28; 95 percent

Solve the problem. -50 people are selected randomly from a certain population and it is found that 20 people in the sample are over 6 feet tall. What is the point estimate of the true proportion of people in the population who are over 6 feet tall?

Solve the problem. -Of 357 randomly selected medical students, 30 said that they planned to work in a rural community. Find a 95% confidence interval for the true proportion of all medical students who plan to work in a rural community.

Find the critical value zα/2 that corresponds to a degree of confidence of 91%. \text { Find the critical value } \mathrm { z } \alpha / 2 \text { that corresponds to a degree of confidence of } 91 \% \text {. } Find the critical value zα/2 that corresponds to a degree of confidence of 91%.

Solve the problem. -Find the critical value χR2\chi _ { R } ^ { 2 }χR2​ corresponding to a sample size of 11 and a confidence level of 90 percent.

Introduction to Statistics

Summarizing and Graphing Data

Statistics for Describing, Exploring, and Comparing Data

Probability

Probability Distributions

Normal Probability Distributions

Hypothesis Testing

Inferences From Two Samples

Correlation and Regression

Multinomial Experiments and Contingency Tables

Analysis of Variance

Nonparametric Statistics

Statistical Process Control

Filters

Use the confidence level and sample data to find a confidence interval for estimating the population µ. -Test scores: $\mathrm { n } = 71 , \overline { \mathrm { x } } = 41.8 , \sigma = 7.2 ; 98$ percent

Use the given degree of confidence and sample data to construct a confidence interval for the population proportion p -Margin of error: $0.05$ ; confidence level: $95 \% ; \hat { \mathrm { p } }$ and $\hat { q }$ unknown

Use the given degree of confidence and sample data to construct a confidence interval for the population proportion p -Margin of error: $0.07$ ; confidence level: $90 \%$ ; from a prior study, $\hat{\mathrm { p }}$ is estimated by $0.19$ .

Use the given degree of confidence and sample data to construct a confidence interval for the population proportion p -Margin of error: $0.025$ ; confidence level: $96 \% ; \hat { \mathrm { p } }$ and $\hat { \mathrm { q } }$ are unknown

$\text { Find the critical value } \mathrm { z } \alpha / 2 \text { that corresponds to a degree of confidence of } 91 \% \text {. }$

Solve the problem. -Find the critical value $\chi _ { R } ^ { 2 }$ corresponding to a sample size of 11 and a confidence level of 90 percent.