Exam 17: Confidence Intervals for Means

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Using the t-tables, software, or a calculator, estimate the critical value of t for the given confidence interval and degrees of freedom: 80% confidence interval with df = 11

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Based on a sample of size 49, a 95% confidence interval for the mean score of all students, μ, on an aptitude test is from 59.2 to 64.8.Find the margin of error.

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A sociologist develops a test to measure attitudes about public transportation, and 27 randomly selected subjects are given the test.Their mean score is 76.2 and their standard Deviation is 21.4.Construct the 95% confidence interval for the mean score of all such Subjects.

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A random sample of clients at a weight loss center were given a dietary supplement to see if it would promote weight loss. The center reported that the 100 clients lost an average of 48 pounds, and that a 95%95 \% confidence interval for the mean weight loss this supplement produced has a margin of error of ±7\pm 7 pounds.

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n=12,xˉ=28.0,s=5.7n = 12 , \bar { x } = 28.0 , s = 5.7 . Find a 99%99 \% confidence interval for the mean.

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n=10,xˉ=13.0,s=4.5n = 10 , \bar { x } = 13.0 , s = 4.5 . Find a 95%95 \% confidence interval for the mean.

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Based on a sample of 30 randomly selected years, a 90% confidence interval for the mean annual precipitation in one city is from 48.7 inches to 51.3 inches.Find the margin of error.

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A credit union took a random sample of 40 accounts and yielded the following 90%90 \% confidence interval for the mean checking account balance at the institution: $2183<μ\$ 2183 < \mu (balance) <$3828< \$ 3828 .

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Thirty randomly selected students took the calculus final.If the sample mean was 95 and the standard deviation was 6.4, construct a 99% confidence interval for the mean score of all Students.

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Data collected by child development scientists produced the following 90%90 \% confidence interval for the average age (in months) at which children say their first word: 10.6<μ(10.6 < \mu ( age )<13.7) < 13.7 .

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Use the t-tables, software, or a calculator to estimate the indicated P-value: P\mathrm { P } -value for t\mathrm { t } \geq 1.761.76 with 24 degrees of freedom.

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Using the t-tables, software, or a calculator, estimate the critical value of t for the given confidence interval and degrees of freedom: 90% confidence interval with df = 4.

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A certain population is strongly skewed to the right.We want to estimate its mean, so we will collect a sample.Which should be true if we use a large sample rather than a small one? I.The distribution of our sample data will be closer to normal. II.The sampling model of the sample means will be closer to normal. III.The variability of the sample means will be greater.

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Analysis of a random sample of 250 Illinois nurses produced a 95%95 \% confidence interval for the mean annual salary of $42,846<μ\$ 42,846 < \mu (Nurse Salary) <$49,686< \$ 49,686

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The amounts (in ounces) of juice in eight randomly selected juice bottles are: 15.015.915.815.715.415.215.215.315.0 \quad 15.915 .8 \quad 15.7 \quad 15.4 \quad 15.2 \quad 15.2 \quad 15.3 Construct a 98%98 \% confidence interval for the mean amount of juice in all such bottles.

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Use the tt -tables, software, or a calculator to estimate the indicated PP -value: PP -value for t1.76t \leq 1.76 with 24 degrees of freedom

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The principal randomly selected six students to take an aptitude test. Their scores were: 71.6 81.0 88.9 80.4 78.1 72.0 Determine a 90%90 \% confidence interval for the mean score for all students.

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