Exam 11: Introduction to Trigonometry

arrow
  • Select Tags
search iconSearch Question
  • Select Tags

  -Use the drawings provided to prove the following theorem. The area of an acute triangle equals one-half the product of the lengths of two sides of a triangle and the sine of the included angle. Given: Acute   Prove:  -Use the drawings provided to prove the following theorem. "The area of an acute triangle equals one-half the product of the lengths of two sides of a triangle and the sine of the included angle." Given: Acute   -Use the drawings provided to prove the following theorem. The area of an acute triangle equals one-half the product of the lengths of two sides of a triangle and the sine of the included angle. Given: Acute   Prove:  Prove:   -Use the drawings provided to prove the following theorem. The area of an acute triangle equals one-half the product of the lengths of two sides of a triangle and the sine of the included angle. Given: Acute   Prove:

Free
(Essay)
4.8/5
(40)
Correct Answer:
Verified

The area of The area of   is given by   . Considering the auxiliary altitude   from vertex B to side   , we see that   is a right angle. Then   in right triangle   . From   , it follows that   . By substitution, the area formula   becomes   so we have   . is given by The area of   is given by   . Considering the auxiliary altitude   from vertex B to side   , we see that   is a right angle. Then   in right triangle   . From   , it follows that   . By substitution, the area formula   becomes   so we have   . . Considering the auxiliary altitude The area of   is given by   . Considering the auxiliary altitude   from vertex B to side   , we see that   is a right angle. Then   in right triangle   . From   , it follows that   . By substitution, the area formula   becomes   so we have   . from vertex B
to side The area of   is given by   . Considering the auxiliary altitude   from vertex B to side   , we see that   is a right angle. Then   in right triangle   . From   , it follows that   . By substitution, the area formula   becomes   so we have   . , we see that The area of   is given by   . Considering the auxiliary altitude   from vertex B to side   , we see that   is a right angle. Then   in right triangle   . From   , it follows that   . By substitution, the area formula   becomes   so we have   . is a right angle. Then The area of   is given by   . Considering the auxiliary altitude   from vertex B to side   , we see that   is a right angle. Then   in right triangle   . From   , it follows that   . By substitution, the area formula   becomes   so we have   . in right triangle The area of   is given by   . Considering the auxiliary altitude   from vertex B to side   , we see that   is a right angle. Then   in right triangle   . From   , it follows that   . By substitution, the area formula   becomes   so we have   . .
From The area of   is given by   . Considering the auxiliary altitude   from vertex B to side   , we see that   is a right angle. Then   in right triangle   . From   , it follows that   . By substitution, the area formula   becomes   so we have   . , it follows that The area of   is given by   . Considering the auxiliary altitude   from vertex B to side   , we see that   is a right angle. Then   in right triangle   . From   , it follows that   . By substitution, the area formula   becomes   so we have   . . By substitution, the area formula The area of   is given by   . Considering the auxiliary altitude   from vertex B to side   , we see that   is a right angle. Then   in right triangle   . From   , it follows that   . By substitution, the area formula   becomes   so we have   . becomes The area of   is given by   . Considering the auxiliary altitude   from vertex B to side   , we see that   is a right angle. Then   in right triangle   . From   , it follows that   . By substitution, the area formula   becomes   so we have   . so we have The area of   is given by   . Considering the auxiliary altitude   from vertex B to side   , we see that   is a right angle. Then   in right triangle   . From   , it follows that   . By substitution, the area formula   becomes   so we have   . .

  -For the right triangle   with right   , prove that   . -For the right triangle   -For the right triangle   with right   , prove that   . with right   -For the right triangle   with right   , prove that   . , prove that   -For the right triangle   with right   , prove that   . .

Free
(Essay)
4.8/5
(35)
Correct Answer:
Verified

By definition, By definition,   ,   , and   . Then   , which can also be written   . Then   . Thus,   . , By definition,   ,   , and   . Then   , which can also be written   . Then   . Thus,   . , and By definition,   ,   , and   . Then   , which can also be written   . Then   . Thus,   . . Then By definition,   ,   , and   . Then   , which can also be written   . Then   . Thus,   . , which can also be written By definition,   ,   , and   . Then   , which can also be written   . Then   . Thus,   . . Then By definition,   ,   , and   . Then   , which can also be written   . Then   . Thus,   . . Thus, By definition,   ,   , and   . Then   , which can also be written   . Then   . Thus,   . .

  -For the right triangle   with right   , prove that   . -For the right triangle   -For the right triangle   with right   , prove that   . with right   -For the right triangle   with right   , prove that   . , prove that   -For the right triangle   with right   , prove that   . .

Free
(Essay)
4.8/5
(37)
Correct Answer:
Verified

In right triangle In right triangle   ,   . Because   is the reciprocal of   , we know that   . Now   , so   or   . Then   . Because   is a right triangle with right angle at vertex C,   . Then   ; that is,   . , In right triangle   ,   . Because   is the reciprocal of   , we know that   . Now   , so   or   . Then   . Because   is a right triangle with right angle at vertex C,   . Then   ; that is,   . . Because In right triangle   ,   . Because   is the reciprocal of   , we know that   . Now   , so   or   . Then   . Because   is a right triangle with right angle at vertex C,   . Then   ; that is,   . is the reciprocal of In right triangle   ,   . Because   is the reciprocal of   , we know that   . Now   , so   or   . Then   . Because   is a right triangle with right angle at vertex C,   . Then   ; that is,   . , we know that In right triangle   ,   . Because   is the reciprocal of   , we know that   . Now   , so   or   . Then   . Because   is a right triangle with right angle at vertex C,   . Then   ; that is,   . . Now In right triangle   ,   . Because   is the reciprocal of   , we know that   . Now   , so   or   . Then   . Because   is a right triangle with right angle at vertex C,   . Then   ; that is,   . , so In right triangle   ,   . Because   is the reciprocal of   , we know that   . Now   , so   or   . Then   . Because   is a right triangle with right angle at vertex C,   . Then   ; that is,   . or In right triangle   ,   . Because   is the reciprocal of   , we know that   . Now   , so   or   . Then   . Because   is a right triangle with right angle at vertex C,   . Then   ; that is,   . .
Then In right triangle   ,   . Because   is the reciprocal of   , we know that   . Now   , so   or   . Then   . Because   is a right triangle with right angle at vertex C,   . Then   ; that is,   . . Because In right triangle   ,   . Because   is the reciprocal of   , we know that   . Now   , so   or   . Then   . Because   is a right triangle with right angle at vertex C,   . Then   ; that is,   . is a right triangle with right angle at vertex C, In right triangle   ,   . Because   is the reciprocal of   , we know that   . Now   , so   or   . Then   . Because   is a right triangle with right angle at vertex C,   . Then   ; that is,   . . Then In right triangle   ,   . Because   is the reciprocal of   , we know that   . Now   , so   or   . Then   . Because   is a right triangle with right angle at vertex C,   . Then   ; that is,   . ; that is, In right triangle   ,   . Because   is the reciprocal of   , we know that   . Now   , so   or   . Then   . Because   is a right triangle with right angle at vertex C,   . Then   ; that is,   . .

  -For the right triangle   with right   , prove that   . Note that   and   are the same and that   as shown in   ; also,   and   have the same meaning. -For the right triangle   -For the right triangle   with right   , prove that   . Note that   and   are the same and that   as shown in   ; also,   and   have the same meaning. with right   -For the right triangle   with right   , prove that   . Note that   and   are the same and that   as shown in   ; also,   and   have the same meaning. , prove that   -For the right triangle   with right   , prove that   . Note that   and   are the same and that   as shown in   ; also,   and   have the same meaning. . Note that   -For the right triangle   with right   , prove that   . Note that   and   are the same and that   as shown in   ; also,   and   have the same meaning. and   -For the right triangle   with right   , prove that   . Note that   and   are the same and that   as shown in   ; also,   and   have the same meaning. are the same and that   -For the right triangle   with right   , prove that   . Note that   and   are the same and that   as shown in   ; also,   and   have the same meaning. as shown in   -For the right triangle   with right   , prove that   . Note that   and   are the same and that   as shown in   ; also,   and   have the same meaning. ; also,   -For the right triangle   with right   , prove that   . Note that   and   are the same and that   as shown in   ; also,   and   have the same meaning. and   -For the right triangle   with right   , prove that   . Note that   and   are the same and that   as shown in   ; also,   and   have the same meaning. have the same meaning.

(Essay)
4.8/5
(40)
close modal

Filters

  • Essay(0)
  • Multiple Choice(0)
  • Short Answer(0)
  • True False(0)
  • Matching(0)