Exam 9: Topics in Analytic Geometry

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Use the Quadratic Formula to solve for y in the following equation. 49x242xy+9y290x10y=049 x ^ { 2 } - 42 x y + 9 y ^ { 2 } - 90 x - 10 y = 0

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Use a graphing utility to graph the rotated conic. r=133sin(θ2π/3)r = \frac { 1 } { 3 - 3 \sin ( \theta - 2 \pi / 3 ) } Use either grid below for your graph, whichever is more convenient.  Use a graphing utility to graph the rotated conic.  r = \frac { 1 } { 3 - 3 \sin ( \theta - 2 \pi / 3 ) }  Use either grid below for your graph, whichever is more convenient.

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A projectile is launched from ground level at an angle of θ\theta with the horizontal. The initial velocity is v0v _ { 0 } feet per second and the path of the projectile is modeled by the parametric equations x=(v0cosθ)t and y=(v0sinθ)t16t2x = \left( v _ { 0 } \cos \theta \right) t \text { and } y = \left( v _ { 0 } \sin \theta \right) t - 16 t ^ { 2 } \text {. } Use a graphing utility to graph the paths of a projectile launched from ground level with the values given for θ\theta and v0v _ { 0 } . Use the graph to approximate the maximum height and range of the projectile to the nearest foot. θ=50,v0=104 feet per second \theta = 50 ^ { \circ } , \quad v _ { 0 } = 104 \text { feet per second }

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Solve the following system of quadratic equations algebraically by the method of substitution. {4x23y2+48=04x2y=0\left\{ \begin{array} { l } - 4 x ^ { 2 } - 3 y ^ { 2 } + 48 = 0 \\- 4 x - 2 y = 0\end{array} \right.

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Find the yy -intercepts of the graph of the circle below. (x3)2+(y+2)2=36( x - 3 ) ^ { 2 } + ( y + 2 ) ^ { 2 } = 36

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Use the discriminant to classify the graph; then use the quadratic formula to solve for y. 3x223xy+y2+103x6y24=03 x ^ { 2 } - 2 \sqrt { 3 } x y + y ^ { 2 } + 10 \sqrt { 3 } x - 6 y - 24 = 0

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Find the graph of the following polar equation. r=3+2cos(θ)r = 3 + 2 \cos ( \theta )

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Find a polar equation of the conic with the given characteristics and with one focus at the pole. Conic Eccentricity Directrix Hyperbola e=5 x=2

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Rotate the axes to eliminate the xyx y -term in the equation. Then write the equation in standard form. 41x2+18xy+41y2800=041 x ^ { 2 } + 18 x y + 41 y ^ { 2 } - 800 = 0

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Classify the graph of the equation below as a circle, a parabola, an ellipse, or a hyperbola. 36x2+16y2+144x+20y335=036 x ^ { 2 } + 16 y ^ { 2 } + 144 x + 20 y - 335 = 0

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Which answer is a polar form of the given rectangular equation? 16xy=14416 x y = 144

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Find the standard form of the equation of the ellipse centered at the origin having vertices at (4,0)( - 4,0 ) and (4,0)( 4,0 ) and foci at (1,0)( - 1,0 ) and (1,0)( 1,0 ) .

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Find the standard form of the parabola with the given characteristics. directrix: x=1x = - 1 vertex: (7,1)( 7 , - 1 )

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Match the graph with its equation. Match the graph with its equation.

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Identify the center and radius of the circle below. (x+1)2+(y8)2=9( x + 1 ) ^ { 2 } + ( y - 8 ) ^ { 2 } = 9

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Find the standard form of the equation of the ellipse with the following characteristics. foci: (±8,0)( \pm 8,0 ) \quad major axis of length: 22

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Which answer is a polar form of the given rectangular equation? 9xy=1449 x y = 144

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Classify the graph of the equation below as a circle, a parabola, an ellipse, or a hyperbola. 2x2+5y2+8x2y=02 x ^ { 2 } + 5 y ^ { 2 } + 8 x - 2 y = 0

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Find a polar equation of the conic with the given characteristics and with one focus at the pole. Conic Eccentricity Directrix Parabola e=1 x=-4

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Convert the point from polar coordinates to rectangular coordinates. Round answer to three decimal places, if necessary. (3,3π2)\left( 3 , - \frac { 3 \pi } { 2 } \right)

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