Exam 14: Parametric Equations and Conic Sections

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(x4)2+(y+3)2=16(x-4)^{2}+(y+3)^{2}=16 is a circle of radius 4 centered at (4,3)(-4,3)

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What is the upper focal point of the ellipse 16x2+4y264x24y+36=016 x^{2}+4 y^{2}-64 x-24 y+36=0 ? Where necessary, round to 2 decimal places.

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Graph (x1)24(y1)29=1\frac{(x-1)^{2}}{4}-\frac{(y-1)^{2}}{9}=1

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Write a parameterization of one branch of the following hyperbola using hyperbolic functions : 3(y+2)25(x4)2=1,y<23(y+2)^{2}-5(x-4)^{2}=1, y<-2 .

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The parameterization for the right half of the hyperbola (x5)29(y3)24=1\frac{(x-5)^{2}}{9}-\frac{(y-3)^{2}}{4}=1 using hyperbolic functions is x=a+bcosht,y=c+dsinht,<t<x=a+b \cosh t, y=c+d \sinh t,-\infty<t<\infty , where a =----------,b =--------,c =------,and d =----------.

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Find the center, vertices, and asymptotes for the following hyperbola: y24x2+8x=8y^{2}-4 x^{2}+8 x=8

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What happens to the graph of the hyperbola x2n2y2n2=1\frac{x^{2}}{n^{2}}-\frac{y^{2}}{n^{2}}=1 as nn decreases?

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Does the hyperbola 9x24y2+54x8y+41=09 x^{2}-4 y^{2}+54 x-8 y+41=0 open left-right or up-down?

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