Exam 5: Continuous Random Variables and Probability Distributions
Exam 1: Describing Data: Graphical247 Questions
Exam 2: Describing Data: Numerical326 Questions
Exam 3: Probability345 Questions
Exam 4: Discrete Random Variables and Probability Distributions257 Questions
Exam 5: Continuous Random Variables and Probability Distributions239 Questions
Exam 6: Sampling and Sampling Distributions147 Questions
Exam 7: Estimation: Single Population151 Questions
Exam 8: Estimation: Additional Topics109 Questions
Exam 9: Hypothesis Testing: Single Population164 Questions
Exam 10: Hypothesis Testing: Additional Topics103 Questions
Exam 11: Simple Regression217 Questions
Exam 12: Multiple Regression252 Questions
Exam 13: Additional Topics in Regression Analysis168 Questions
Exam 14: Analysis of Categorical Data241 Questions
Exam 15: Analysis of Variance192 Questions
Exam 16: Time-Series Analysis and Forecasting138 Questions
Exam 17: Additional Topics in Sampling110 Questions
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If Z is a standard normal random variable,then P(-1.25 ≤ Z ≤ -0.75)is:
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(Multiple Choice)
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Correct Answer:
D
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You are the webmaster for your firm's web-site.From your records,you know that the probability that a visitor will buy something from your firm is 0.23.In one day,the number of visitors is 952.
-What is the probability that less than 200 of them will buy something from your firm? Use the normal approximation to the binomial.
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(Multiple Choice)
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Correct Answer:
D
A normal random variable x has an unknown mean μ and standard deviation σ = 2.5.If the probability that x exceeds 7.5 is 0.8289,find μ.
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(Essay)
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Correct Answer:
It is given that x is normally distributed with σ = 2.5 but with unknown mean μ,and
that P (x > 7.5)= 0.8289.In terms of the standard normal random variable z,we can write
P(X > 7.5)= P[Z > (7.5 - μ)/2.5] = 0.8289,Z = -0.95
Since the area to the right of (7.5 - μ)/2.5 is greater than 0.5,then (7.5 - μ)/2.5 must be negative,and that P[(7.5 - μ)/2.5 < z < 0] = 0.3289.Hence,(7.5 - μ)/2.5 = -0.095.This implies μ = 9.875.
The normal probabilities are calculated using the table of standard normal distribution where the mean and standard deviations are,respectively:
(Multiple Choice)
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The amount of time you have to wait at a particular stoplight is uniformly distributed between zero and two minutes.
-Sixty percent of the time,the stoplight will change before you have to wait X seconds,what is the value of X?
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The continuous random variable X is uniformly distributed over the interval 4 to 10.
-What is the standard deviation of this distribution?
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Suppose x is normally distributed with a mean of 75 and a standard deviation of 4.
-Find the 5th percentile.
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In a recent survey of high school students,it was found that the average amount of money spent on entertainment each week was normally distributed with a mean of $52.30.Suppose you are told that there is an 80% probability that a randomly-selected student spends somewhere between $49.74 and $54.86.What is the standard deviation of the amount of money spent by high school students monthly?
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A professor sees students during regular office hours.Times spent with students follow an exponential distribution with mean of 12 minutes.
-Find the probability that a given student spends less than 15 minutes with the professor.
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Checkout times in a grocery store follow the exponential distribution with a mean time of 6.5 minutes.What is the probability that the checkout time (T)for the next customer will be less than 5 minutes?
(Multiple Choice)
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We can obtain probabilities for any normally distributed random variable by first converting the random variable to the standard normally distributed random variable.
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The profit for a production process is equal to $7,200 minus 2.8 times the number of units produced.The mean and variance for the number of units produced are 1,100 and 800,respectively.Find the mean and variance of the profit.
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The term used by fund managers to describe the relationships between two stock prices is:
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A catalog company administered a survey to determine how long customers were willing to wait on hold before ordering a product.The length of time was found to be a random variable best approximated by an exponential distribution with a mean equal to 3.5 minutes.What proportion of customers having to hold more than 5.0 minutes will hang up before placing an order?
(Multiple Choice)
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In the normal distribution,the curve approaches,but never intercepts the horizontal axis either to the left or right.
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Any set of normally distributed data can be transformed to a standardized form.
(True/False)
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You have recently joined a country club.The number of times you expect to play golf in a month is represented by a random variable with a mean of 10 and a standard deviation of 2.2.Assume you pay monthly membership fees of $500 per month and pay an additional $50 per round of golf.
-What is your average monthly bill from the country club?
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The number of orders that come into a mail-order sales office each month is normally distributed with a mean of 298 and a standard deviation of 15.4.
-What proportion of the total area under the normal curve is above the mean?
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The total area under the curve of the probability density function for a continuous random variable depends on the shape of the probability distribution of the random variable.
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