Exam 10: Hypothesis Tests Involving a Sample Mean or Proportion

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What is a one-tail test?

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A one-tail test is one in which a null hypothesis can be rejected by an extreme result in one direction only.

What is a power curve and how is it applicable to hypothesis testing?

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The power of a test is the probability that the test will respond correctly by rejecting a false null hypothesis.By calculating the power of the test (1 - β\beta )for several assumed values for the population mean and plotting the power (on the vertical axis)versus the population mean (on the horizontal axis),we arrive at the power curve.By looking at the power curve,we can get an idea of how powerful the hypothesis test is for different possible values of the population mean.

Golf A round of golf on your typical course requires at least 4.5 hours.A particular golf club claims that the average length of time to complete a round of golf on their course is less than 4.5 hours.To test this claim,the club sampled 15 golfers and recorded their time to finish their round.The sample average was 4.4 hours with a standard deviation of 0.8 hours.Assume the time to complete a round of golf is normally distributed and use α\alpha = 0.01. -State your conclusions.

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Since t = -0.484,we fail to reject the null hypothesis.There does not appear to be a basis for the claim that the average round of golf can be completed in less than 4.5 hours.

Political candidate A political candidate needs more then 50% of the votes to win the next election.In an effort to convince contributors to his campaign,he samples 800 potential voters of which 432 indicated they would vote for him.Use α\alpha = 0.05. -What is the p-value? What are your conclusions?

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Determine the power for the following test of hypothesis,H0: μ\mu = 950 vs.H1: μ\mu \neq 950,given that μ\mu = 1000, α\alpha = 0.10,  σ \text { σ } = 200,and n = 25.

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What standard error will be associated with this test?

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What is a two-tail test?

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Adult drink A particular study claims that the average U.S.adult drinks 1.7 cups of coffee per day.To test this claim,a sample of 35 adults were asked about their coffee consumption.The sample average was 1.95 cups per day.Assume the population standard deviation is 0.5 cups per day and set α\alpha = 0.10. -What is your conclusion?

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Use the given information to calculate the p-value and interpret the result: H0: μ\mu = 15,H1: μ\mu \neq 15  σ \text { σ } = 5,n = 10, xˉ\bar { x } = 18.1, α\alpha = 0.03 p-value = ____________________ Interpretation: ____________________

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The Admissions officer for the graduate programs at Michigan State University (MSU)believes that the average score on the GRE exam at his university is significantly higher than the national average of 1300.Assume that the population standard deviation is 125 and a random sample of 25 scores had an average of 1375. A)State the appropriate null and alternative hypotheses. H0: ____________________ H1: ____________________ B)Calculate the value of the test statistic. C)What is your conclusion?

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The ____________________ will bound rejection and non-rejection regions for the null hypothesis.

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General Manager The general manager of a large discount chain was considering location of a new store in a small mid-western city.The decision was dependent upon the per capita retail sales for the city being significantly greater than $4500.A sample of 500 residents was taken,and showed a mean of $4780.A population standard deviation of $2500 was known. -What is your conclusion?

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Tobacco Industry The tobacco industry advertised that the per capita number of cigarettes sold per year was 3700.An anti-smoking organization argued strongly that per capita consumption had declined. -State the null and alternative hypotheses.

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General Manager The general manager of a large discount chain was considering location of a new store in a small mid-western city.The decision was dependent upon the per capita retail sales for the city being significantly greater than $4500.A sample of 500 residents was taken,and showed a mean of $4780.A population standard deviation of $2500 was known. -State the decision rule for α\alpha = 0.01.

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Bank A bank holds the mortgage on a motel which the motel owner says has an average daily revenue of at least $2048.In the event the average is not at least $2048,the bank will ask the motel owner for additional collateral for the loan as protection against loan default.A loan officer is aware that the daily average revenue is normally distributed and randomly selects 20 days during the last six months.The sample has a mean of $2003 and standard deviation of $144.00.At the 0.01 level,is the bank loan financially sound (should the bank ask for additional collateral)? -What is the decision rule?

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Local Restaurant A local restaurant claimed in an advertisement that at least 80% of their customers rate their establishment as "Excellent".An independent survey company asked 200 customers their opinion and from this random sample,168 customers rated the establishment "Excellent".Use α\alpha = 0.05. -State the decision rule in terms of the critical value.

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General Manager The general manager of a large discount chain was considering location of a new store in a small mid-western city.The decision was dependent upon the per capita retail sales for the city being significantly greater than $4500.A sample of 500 residents was taken,and showed a mean of $4780.A population standard deviation of $2500 was known. -State the null and alternative hypotheses. H0: ____________________ H1: ____________________

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Tail graph Tail graph   -Using the above graph,choose the answers that indicate a right-tail test: Area 1: ____________________ Area 2: ____________________ Area 3: ____________________ -Using the above graph,choose the answers that indicate a right-tail test: Area 1: ____________________ Area 2: ____________________ Area 3: ____________________

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Golf A round of golf on your typical course requires at least 4.5 hours.A particular golf club claims that the average length of time to complete a round of golf on their course is less than 4.5 hours.To test this claim,the club sampled 15 golfers and recorded their time to finish their round.The sample average was 4.4 hours with a standard deviation of 0.8 hours.Assume the time to complete a round of golf is normally distributed and use α\alpha = 0.01. -Use the following information to test at a 0.01 level of significance.n = 400; p = 0.03; H0: π\pi \geq 0.05,H1: π\pi < 0.05. Compute the test statistic. Appropriate test: ____________________ Test statistic = ____________________

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A portfolio manager was analyzing the price-earnings ratio for this year's performance.His boss said that the average price-earnings ratio was 20 for the many stocks,which his firm had traded,but he felt that figure was too high.The portfolio manager randomly selected a sample of 50 P/E ratios and found a mean of 18.17 and standard deviation of 4.60.Assume that the population is normally distributed and test at the 0.01 level of significance. The decision rule is: Reject H0 if the calculated z > 2.33.

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