Exam 14: Additional Topics in Algebra

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Find the common difference d for the following arithmetic sequence. 12, 7, 2, - 3, ...

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Find the sum of the first 50 terms in an arithmetic series that has first term - 18 and 50th term 129.

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D

Find the right part of the equality. 12+23+34++n(n+1)=1 \cdot 2 + 2 \cdot 3 + 3 \cdot 4 + \ldots + n ( n + 1 ) = ________

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B

Find the third term in the expansion of (a - b) 27 .

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Find limx5[g(x)f(x)]\lim _ { x \rightarrow 5 } [ g ( x ) - f ( x ) ] for f(x)=4x3f ( x ) = 4 x ^ { 3 } and g(x)=x2+53x2g ( x ) = \frac { \sqrt { x ^ { 2 } + 5 } } { 3 x ^ { 2 } } .

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For what natural numbers is the following inequality true? (1.15)n>n( 1.15 ) ^ { n } > n

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Evaluate the sum. n=20110(2n1)\sum _ { n = 20 } ^ { 110 } ( 2 n - 1 )

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Find limx6x+5x2\lim _ { x \rightarrow 6 } \frac { \sqrt { x + 5 } } { x - 2 } by direct substitution.

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Carry out the expansion. (2a + b) 9

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Use the graph to determine limx0x23xx\lim _ { x \rightarrow 0 } \frac { x ^ { 2 } - 3 x } { x } (if it exists).  Use the graph to determine  \lim _ { x \rightarrow 0 } \frac { x ^ { 2 } - 3 x } { x }  (if it exists).

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Find the right part of the equality. 4+5+6++(n+3)=4 + 5 + 6 + \cdots + ( n + 3 ) =

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Find the indicated term. 11,20,29,38,,a1211,20,29,38 , \ldots , a _ { 12 }

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Use the graph to find limx34x236x3\lim _ { x \rightarrow 3 } \frac { 4 x ^ { 2 } - 36 } { x - 3 }  Use the graph to find  \lim _ { x \rightarrow 3 } \frac { 4 x ^ { 2 } - 36 } { x - 3 }

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Find the indicated term. 5,2,1,4,,a205,2 , - 1 , - 4 , \ldots , a _ { 20 }

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Find the right part of the equality. 12+22+32++n2=1 ^ { 2 } + 2 ^ { 2 } + 3 ^ { 2 } + \ldots + n ^ { 2 } = ________

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The sum of three consecutive terms in an arithmetic sequence is 30, and their product is 750. Find the three terms. (Suggestion: Let x denote the middle term and d the common difference.)

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Evaluate and simplify. (40)\left( \begin{array} { l } 4 \\0\end{array} \right)

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Express as a fraction. 0.710 . \overline { 71 }

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Use the position function s(t)=16t2+120s ( t ) = - 16 t ^ { 2 } + 120 to find the velocity in feet/second at time t=2t = 2 seconds. The velocity at time t=ct = c seconds is given by limtc[s(c)s(t)](ct)\lim _ { t \rightarrow c } \frac { [ s ( c ) - s ( t ) ] } { ( c - t ) }

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Find limy013+y13y\lim _ { y \rightarrow 0 } \frac { \sqrt { 13 + y } - \sqrt { 13 } } { y } .

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