Exam 10: Additional Topics in Trigonometry

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Determine the graph that reflects the polar equation. r=2+4sinθr = - 2 + 4 \sin \theta

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Assume that the vectors a\mathbf { a } , b\mathbf { b } ,  C \text { C } and  d \text { d } are defined as follows: a=1,2\mathbf { a } = \langle 1,2 \rangle b=5,4\mathbf { b } = \langle 5,4 \rangle c=5,2\mathbf { c } = \langle 5 , - 2 \rangle d=2,0\mathbf { d } = \langle - 2,0 \rangle Compute 13b4d(3b4c)\frac { 1 } { | 3 b - 4 d | } ( 3 b - 4 c )

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Convert the given rectangular coordinates to polar coordinates. Express the answer in such a way that r is nonnegative and 0θ<2π0 \leq \theta < 2 \pi . (7,0)( 7,0 )

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The accompanying figure shows two ships at points PP and QQ , which are in the same vertical plane as an airplane at point RR . When the height of the airplane is 4,000 ft, the angle of depression to PP is 38° and that to ee is 15°. Find the distance between the two ships.  The accompanying figure shows two ships at points  P  and  Q  , which are in the same vertical plane as an airplane at point  R  . When the height of the airplane is 4,000 ft, the angle of depression to  P  is 38° and that to  e  is 15°. Find the distance between the two ships.

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Convert to rectangular form. r=3tanθr = 3 \tan \theta

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Use the equation to determine polar coordinates of the point B. r=3232sinθr = - \frac { 3 } { 2 } - \frac { 3 } { 2 } \sin \theta  Use the equation to determine polar coordinates of the point B.  r = - \frac { 3 } { 2 } - \frac { 3 } { 2 } \sin \theta

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The initial point for the vector is the origin, and θ\theta denotes the angle (measured counterclockwise) from the XX -axis to the vector. The magnitude of V\mathrm { V } is 3030 cm/sec, and θ=120\theta = 120 ^ { \circ } Compute the horizontal and vertical components of the given vector. (Round your answers to two decimal places.)

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Determine the graph of the equation. r=2+3sinθr = 2 + 3 \sin \theta

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An airplane crashes in a lake and is spotted by observers at lighthouses A and B along the coast. Lighthouse B is 1.10 miles due east of lighthouse A. The bearing of the airplane from lighthouse A is S20E\mathrm { S } 20 ^ { \circ } \mathrm { E } ; the bearing of the plane from lighthouse B is S40W\mathrm { S } 40 ^ { \circ } \mathrm { W } . Find the distance from each lighthouse to the crash site.

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Convert the given rectangular coordinates to polar coordinates. Express the answer in such a way that r is nonnegative and 0θ<2π0 \leq \theta < 2 \pi . (5,5)( - 5 , - 5 )

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Convert from rectangular to trigonometric form. (Choose an argument θ\theta such that 0θ<2π0 \leq \theta < 2 \pi .) 12+123i- \frac { 1 } { 2 } + \frac { 1 } { 2 } \sqrt { 3 } i

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Determine the graph that reflects the polar equation. r=2cos5θr = 2 \cos 5 \theta (five-leafed rose)

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Two points P and Q are on opposite sides of a river (see the sketch). From P to another point R on the same side is 340 ft. Angles PRQP R Q and RPQR P Q are found to be 2323 ^ { \circ } and 120120 ^ { \circ } , respectively. Compute the distance from P to Q, across the river. (Round your answer to the nearest foot.)  Two points P and Q are on opposite sides of a river (see the sketch). From P to another point R on the same side is 340 ft. Angles  P R Q  and  R P Q  are found to be  23 ^ { \circ }  and  120 ^ { \circ }  , respectively. Compute the distance from P to Q, across the river. (Round your answer to the nearest foot.)

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Assume that the vectors a\mathbf { a } , b\mathbf { b } ,  C \text { C } and  d \text { d } are defined as follows: a=1,1\mathbf { a } = \langle 1,1 \rangle b=5,4\mathbf { b } = \langle 5,4 \rangle c=6,8c = \langle 6 , - 8 \rangle d=5,3\mathbf { d } = \langle - 5,3 \rangle Compute c+dc + d .

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Refer to the figure. If B=45\angle B = 45 ^ { \circ } and AC=40 cmA C = 40 \mathrm {~cm} , find ABA B .  Refer to the figure. If  \angle B = 45 ^ { \circ }  and  A C = 40 \mathrm {~cm}  , find  A B  .

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Convert from rectangular to trigonometric form. (Choose an argument θ\theta such that 0θ<2π0 \leq \theta < 2 \pi .) 6

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Use the given information to find the cosines of angles in ABCA B C . a=13a = 13 cm, b=12b = 12 cm, c=5c = 5 cm

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Simplify. 3(cosπ3+isinπ3)5(cosπ6+isinπ6)\frac { 3 \left( \cos \frac { \pi } { 3 } + i \sin \frac { \pi } { 3 } \right) } { 5 \left( \cos \frac { \pi } { 6 } + i \sin \frac { \pi } { 6 } \right) }

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On a sheet of paper, graph the parametric equation after eliminating the parameter tt (0t2π( 0 \leq t \leq 2 \pi ). Specify the approximate direction on the curve corresponding to increasing values of tt . x=6sin2t,y=5cos2tx = 6 \sin 2 t , y = 5 \cos 2 t

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Determine the graph that reflects the polar equation. r=55cosθr = - 5 - 5 \cos \theta

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