Exam 12: Probability and Calculus

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A hardware store will cut lumber any length between 5 and 20 feet. Say X is the length of lumber requested by a customer. Then X is a uniform random variable with probability density function f(x)=115f ( x ) = \frac { 1 } { 15 } Find E(X) and Var(X). Enter just two reduced fractions (unlabeled) in the order E(X), Var(X) separated by a comma.

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The probability density function for a random variable X is f(x) = 3x43 x ^ { - 4 } , x ≥ 1. Find Pr(2X)\operatorname { Pr } ( 2 \leq X ) . Enter just a reduced fraction.

(Short Answer)
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The table below is the probability table for a random variable X. Find E(X). Outcome -1 0 1 2 Probability Enter just a reduced fraction of form ab\frac { a } { b } .

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It is estimated that the time between arrivals of visitors to a public library is an exponential random variable with expected value of 13 minutes. Find the probability that 30 minutes elapses without any arrivals. Enter your answer as just ea/b\mathrm { e } ^ { \mathrm { a } / \mathrm { b } } , where ab\frac { a } { b } is a reduced fraction.

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A new car dealer observes that the number X of warranty claims for repairs on each new car sold is Poisson distributed, with an average of six claims per car. Compute the probability that a new car sold by the dealer will have no more than three warranty claims. Enter your answer in the form a eb\mathrm { e } ^ { \mathrm { b } } .

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Let X be a continuous random variable A ≤ X ≤ B and let f (x) be its probability density function and F (x) its cumulative distribution function. Indicate whether the following statements are true or false. - FF ^ { \prime } (x) = f(x)

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A random variable X has probability density function f(x) = kekxk e ^ { - k x } (x ≥ 1) for some constant k. Suppose that Pr(1X2)=14\operatorname { Pr } ( 1 \leq X \leq 2 ) = \frac { 1 } { 4 } , what is the value of k?

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Find the expected value and variance for the random variable whose probability density function is f(x)=2(x1)f ( x ) = 2 ( x - 1 ) 1 ≤ x ≤ 2. Enter just two reduced fractions (unlabeled) in the order E(X), Var(X) separated by a comma.

(Short Answer)
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The table below is the probability table for a random variable X. Find Var(X). Outcome -1 0 1 2 Probability Enter just a reduced fraction of form ab\frac { a } { b } .

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Find the expected value and variance for the random variable whose probability density function is f(x)=4x1f ( x ) = 4 x - 1 12\frac { 1 } { 2 } ≤ x ≤ 1. Enter just two reduced fractions (unlabeled) in the order E(X), Var(X) separated by a comma.

(Short Answer)
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Find (by inspection) the expected value and the variance of the random variables with the following density function: f(x) = 142π\frac { 1 } { 4 \sqrt { 2 \pi } } e(1/2)[(x1)/4]2\mathrm { e } ^ { - ( 1 / 2 ) [ ( \mathrm { x } - 1 ) / 4 ] ^ { 2 } } , -∞ < x < ∞ Enter your answer as just two integers separated by a comma, the first representing E(X) and the second representing Var(X).

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A random variable X has a cumulative distribution function F(x) = 1 - 1(x+1)2\frac { 1 } { ( x + 1 ) ^ { 2 } } for x0x \geq 0 . Find Pr(1X4)\operatorname { Pr } ( 1 \leq X \leq 4 ) . Enter just a reduced fraction.

(Short Answer)
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