Exam 2: First-Order Differential Equations

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The differential equation xydx+(x2+y2)dy=0x y d x + \left( x ^ { 2 } + y ^ { 2 } \right) d y = 0 is

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E

The differential equation y=(2x+4y+5)2y ^ { \prime } = ( 2 x + 4 y + 5 ) ^ { 2 } has the solution

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E

The differential equation (x2+y2)y=xy\left( x ^ { 2 } + y ^ { 2 } \right) y ^ { \prime } = x y is

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B

The differential equation x2y=2xy+cosxx ^ { 2 } y ^ { \prime } = 2 x y + \cos x is

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An integrating factor for the linear differential equation y+y/x=xy ^ { \prime } + y / x = x is

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Solve the problem y=xy2,y(1)=1y ^ { \prime } = x y ^ { 2 } , y ( 1 ) = 1 numerically for y(1.2)y ( 1.2 ) using h=0.1h = 0.1 .

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The differential equation (x2y)dx+ydy=0( x - 2 y ) d x + y d y = 0 can be solved using the substitution

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Solve the problem y=xy,y(1)=2y ^ { \prime } = x y , y ( 1 ) = 2 numerically for y(1.2)y ( 1.2 ) using h=0.1h = 0.1 .

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The differential equation y+y=xy2y ^ { \prime } + y = x y ^ { 2 } is

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An integrating factor for the linear differential equation xy+y=xx y ^ { \prime } + y = x is

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The differential equation y=xey/yy ^ { \prime } = x e ^ { y } / y is

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The solution of the differential equation yy/x=y2y ^ { \prime } - y / x = y ^ { 2 } is

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Assume that a>0a > 0 , b>0b > 0 . The autonomous differential equation dPdt=P(a+bP)\frac { d P } { d t } = P ( a + b P ) has a solution that is

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An integrating factor for the linear differential equation yy/x=xy ^ { \prime } - y / x = x is

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The autonomous differential equation dxdt=x(x1)(x+1)\frac { d x } { d t } = x ( x - 1 ) ( x + 1 ) has a solution that is

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Solve the problem y=x2y2,y(0)=1y ^ { \prime } = x ^ { 2 } y ^ { 2 } , y ( 0 ) = 1 numerically for y(0.2)y ( 0.2 ) using h=0.1h = 0.1

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The differential equation y=2xy+1+2y ^ { \prime } = \sqrt { 2 x - y + 1 } + 2 has the solution

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In the autonomous differential equation dxdt=x(1x)\frac { d x } { d t } = x ( 1 - x ) , the critical point

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The solution of the differential equation y+y=xy ^ { \prime } + y = x is

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In the autonomous differential equation dxdt=x2(1x)\frac { d x } { d t } = x ^ { 2 } ( 1 - x ) , the critical point

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