Exam 15: Numerical Solutions of Partial Differential Equations

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In the previous two problems, let c=1c = 1 . Thesolutionforu along the line t=0.25t = 0.25 at the mesh points is Select all that apply.

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A, B, D

The wave equation is

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E

Laplace's equation is

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C

In the previous two problems, using uiju _ { i j } to denote the value of uu at the i,ji , j point, the equations for the values of the unknown function at the interior points are Select all that apply.

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The five-point approximation of the Laplacian is

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In the previous problem, is the value of λ\lambda such that the scheme is stable?

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In the previous three problems, if g(x)=0g ( x ) = 0 then the values of ui,1u _ { i , - 1 } are

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The wave equation is

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The five point approximation of the Laplacian is

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Consider the problem 2ux2+2uy2=0,u(0,y)=0,u(x,0)=0,u(1,y)=yy2,u(x,1)=xx2\frac { \partial ^ { 2 } u } { \partial x ^ { 2 } } + \frac { \partial ^ { 2 } u } { \partial y ^ { 2 } } = 0 , u ( 0 , y ) = 0 , u ( x , 0 ) = 0 , u ( 1 , y ) = y - y ^ { 2 } , u ( x , 1 ) = x - x ^ { 2 } . A finite difference approximation of the solution is desired, using the approximation of the previous problem. Use a mesh size of h=1/3h = 1 / 3 The conditions satisfied by the mesh points on the boundary are Select all that apply.

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Consider the problem c22ux2=2ut2,u(0,t)=0,u(1,t)=0,u(x,0)=sin(πx),ut(x,0)=g(x)c ^ { 2 } \frac { \partial ^ { 2 } u } { \partial x ^ { 2 } } = \frac { \partial ^ { 2 } u } { \partial t ^ { 2 } } , u ( 0 , t ) = 0 , u ( 1 , t ) = 0 , u ( x , 0 ) = \sin ( \pi x ) , u _ { t } ( x , 0 ) = g ( x ) . Replace 2ux2\frac { \partial ^ { 2 } u } { \partial x ^ { 2 } } with a central difference approximation with h=1/4h = 1 / 4 and 2ut2\frac { \partial ^ { 2 } u } { \partial t ^ { 2 } } with a central difference approximation with k=1/3k = 1 / 3 The resulting equation is

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In the previous three problems, the solution at the interior points is Select all that apply.

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Consider the problem c22ux2=2ut2,u(0,t)=0,u(1,t)=0,u(x,0)={x if 0<x<1/21x if 1/2<x<1}c ^ { 2 } \frac { \partial ^ { 2 } u } { \partial x ^ { 2 } } = \frac { \partial ^ { 2 } u } { \partial t ^ { 2 } } , u ( 0 , t ) = 0 , u ( 1 , t ) = 0 , u ( x , 0 ) = \left\{ \begin{array} { c c c } x & \text { if } & 0 < x < 1 / 2 \\1 - x & \text { if } & 1 / 2 < x < 1\end{array} \right\} , ut(x,0)=g(x)u _ { t } ( x , 0 ) = g ( x ) . Replace 2ux2\frac { \partial ^ { 2 } u } { \partial x ^ { 2 } } with a central difference approximation with h=1/2h = 1 / 2 and 2ux2\frac { \partial ^ { 2 } u } { \partial x ^ { 2 } } with a central difference approximation with k=1/2k = 1 / 2 . The resulting equation is

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Consider the problem 2ux2+2uy2=0,u(0,y)=0,u(x,0)=0,u(1,y)=sin(πy),u(x,1)=sin(πx)\frac { \partial ^ { 2 } u } { \partial x ^ { 2 } } + \frac { \partial ^ { 2 } u } { \partial y ^ { 2 } } = 0 , u ( 0 , y ) = 0 , u ( x , 0 ) = 0 , u ( 1 , y ) = \sin ( \pi y ) , u ( x , 1 ) = \sin ( \pi x ) . A finite difference approximation of the solution is desired, using the approximation of the previous problem. Use a mesh size of h=1/3h = 1 / 3 The conditions satisfied by the mesh points on the boundary are Select all that apply.

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The central difference approximation for ux\frac { \partial u } { \partial x } with step size hh is

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A Dirichlet problem is a partial differential equation with conditions specifying

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In the previous problem, using the notation uij=u(x,t)u _ { i j } = u ( x , \mathrm { t } ) , and letting λ=ck/h2\lambda = c k / h ^ { 2 } , the equation becomes

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Laplace's equation is

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In the previous problem, using the notation uij=u(x,t)u _ { i j } = u ( x , \mathrm { t } ) , and letting λ=ck/h2\lambda = c k / h ^ { 2 } , the equation becomes

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In the previous three problems, the values of ui,1u _ { i , - 1 } are

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