Solved

Determine the Directrices for the Ellipse and Hyperbola 64x2+81y2=5,184,64x281y2=5,18464 x ^ { 2 } + 81 y ^ { 2 } = 5,184,64 x ^ { 2 } - 81 y ^ { 2 } = 5,184

Question 22

Multiple Choice

Determine the directrices for the ellipse and hyperbola. 64x2+81y2=5,184,64x281y2=5,18464 x ^ { 2 } + 81 y ^ { 2 } = 5,184,64 x ^ { 2 } - 81 y ^ { 2 } = 5,184


A)  ellipse directrices: x=±917; hyperbola directrices: x=±9145\text { ellipse directrices: } x = \pm 9 \sqrt { 17 } \text {; hyperbola directrices: } x = \pm 9 \sqrt { 145 }
B)  ellipse directrices: x=±811717; hyperbola directrices: x=±81145145\text { ellipse directrices: } x = \pm \frac { 81 \sqrt { 17 } } { 17 } ; \text { hyperbola directrices: } x = \pm \frac { 81 \sqrt { 145 } } { 145 }
C)  ellipse directrices: x=±8114517; hyperbola directrices: x=±8117145\text { ellipse directrices: } x = \pm \frac { 81 \sqrt { 145 } } { 17 } ; \text { hyperbola directrices: } x = \pm \frac { 81 \sqrt { 17 } } { 145 }
D)  ellipse directrices: x=917; hyperbola directrices: x=9145\text { ellipse directrices: } x = - 9 \sqrt { 17 } \text {; hyperbola directrices: } x = 9 \sqrt { 145 }
E)  ellipse directrices: x=91717; hyperbola directrices: x=81145145\text { ellipse directrices: } x = \frac { 9 \sqrt { 17 } } { 17 } ; \text { hyperbola directrices: } x = - \frac { 81 \sqrt { 145 } } { 145 }

Correct Answer:

verifed

Verified

Unlock this answer now
Get Access to more Verified Answers free of charge

Related Questions