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If U(x,s)=C{u(x,t)}, then L{ux}U ( x , s ) = \mathcal { C } \{ u ( x , t ) \} \text {, then } \mathcal { L } \left\{ \frac { \partial u } { \partial x } \right\}

Question 16

Multiple Choice

If U(x,s) =C{u(x,t) }, then L{ux}U ( x , s ) = \mathcal { C } \{ u ( x , t ) \} \text {, then } \mathcal { L } \left\{ \frac { \partial u } { \partial x } \right\} is


A) sU(x,s) u(x,0) s U ( x , s ) - u ( x , 0 )
B) sU(x,s) ux(x,0) s U ( x , s ) - u _ { x } ( x , 0 )
C) sU(x,s) su(x,0) s U ( x , s ) - s u ( x , 0 )
D) Ux(x,s) U _ { x } ( x , s )
E) Us(x,s) U _ { s } ( x , s )

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