Exam 22: Linear Programming: The Simplex Method

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An infeasible solution is indicated when all the Cj - Zj row entries are of the proper sign to imply optimality, but an artificial variable remains in the solution.

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In LP problems with more than two variables, the area of feasible solutions is known as an n-dimensional

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The constraint 5X1 + 6X2 ≥ 30, when converted to an = constraint for use in the simplex algorithm, will be 5 X1 + 6 X2 - S = 30.

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In applying the simplex solution procedure to a minimization problem to determine which variable enters the solution mix

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Table M7-3 Table M7-3   -According to Table M7-3, which is the final simplex tableau for a problem with two variables and two constraints, what is the maximum possible profit (objective function value)for this problem? -According to Table M7-3, which is the final simplex tableau for a problem with two variables and two constraints, what is the maximum possible profit (objective function value)for this problem?

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A minimization problem with two decision variables and three ≥ constraints can have two non-basic surplus variables.

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The simplex method begins with an initial feasible solution in which all real variables are set equal to 0.

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In a maximization problem, if a variable is to enter the solution, it must have a positive coefficient in the Cj - Zj row.

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Shadow prices are the positives of the numbers in the Cj - Zj row's slack variable columns.

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Convert the following linear program into a simplex model form. Maximize 8X + 10Y Subject to: 5X + 3Y ≤ 34 2X + 3Y = 22 X ≥ 3 X, Y ≥ 0

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Table M7-3 Table M7-3   -According to Table M7-3, which is the final simplex tableau for a linear programming problem (maximization), what would happen to profits if the X<sub>1</sub> column were selected as the pivot column and another iteration of the simplex algorithm were performed? -According to Table M7-3, which is the final simplex tableau for a linear programming problem (maximization), what would happen to profits if the X1 column were selected as the pivot column and another iteration of the simplex algorithm were performed?

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Consider the following linear programming problem: Maximize 40 X1 + 30 X2 + 60X3 Subject to: X1 + X2 + X3 ≥ 90 12 X1 + 8 X2 + 10 X3 ≤ 1500 X1 = 20 X3 ≤ 100 X1 , X2 , X3 ≥ 0 How many slack, surplus, and artificial variables would be necessary if the simplex algorithm were used to solve this problem?

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The substitution rates

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Table M7-1 Table M7-1   -According to Table M7-1, it is currently profitable to produce some units of X<sub>1</sub> and the current profit per unit of X<sub>1</sub> is $20.What is the lowest value that this could be to allow this variable to remain in the basis? -According to Table M7-1, it is currently profitable to produce some units of X1 and the current profit per unit of X1 is $20.What is the lowest value that this could be to allow this variable to remain in the basis?

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The number -2 in the X2 column and X1 row of a simplex tableau implies that

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In a maximization problem, if a variable is to enter the solution, it must have a negative coefficient in the Cj - Zj row.

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Karmarkar's algorithm reaches a solution quickly by compressing the edges of the feasible region.

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The dual problem formulation can be solved using the same simplex process used for the primal formulation.

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