Question 1

Consider the following ANOVA table. ​   ​
The null hypothesis for this ANOVA problem is

Accepted Answer

A)  μ1 = μ2 = μ3 = μ4. 
B)  μ1 = μ2 = μ3 = μ4 = μ5. 
C)  μ1 = μ2 = μ3 = μ4 = μ5 = μ6. 
D)  μ1 = μ2 = ...= μ20. 
A)  μ1 = μ2 = μ3 = μ4. 
B)  μ1 = μ2 = μ3 = μ4 = μ5. 
C)  μ1 = μ2 = μ3 = μ4 = μ5 = μ6. 
D)  μ1 = μ2 = ...= μ20. B

Question 2

Consider the following information. ​   ​
The null hypothesis is to be tested at the 5% level of significance.The p-value is

Accepted Answer

A)  less than .01. 
B)  between .01 and .025. 
C)  between .025 and .05. 
D)  greater than .10. 
A)  less than .01. 
B)  between .01 and .025. 
C)  between .025 and .05. 
D)  greater than .10. B

Question 3

An experimental design where the experimental units are randomly assigned to the treatments is known as _____ design.

Accepted Answer

A)  factor block 
B)  random factor 
C)  completely randomized 
D)  randomized treatment 
A)  factor block 
B)  random factor 
C)  completely randomized 
D)  randomized treatment C

Question 4

In ANOVA, which of the following is not affected by whether or not the population means are equal?

Accepted Answer

A)    
B)  between-treatments estimate of σ2 
C)  within-treatments estimate of σ2 
D)  ratio of between- and within-treatments estimate of σ2 
A)    
B)  between-treatments estimate of σ2 
C)  within-treatments estimate of σ2 
D)  ratio of between- and within-treatments estimate of σ2

Question 5

In an analysis of variance problem if SST = 120 and SSTR = 90, then SSE is

Accepted Answer

A)  210. 
B)  30. 
C)  80. 
D)  120. 
A)  210. 
B)  30. 
C)  80. 
D)  120.

Question 6

An experimental design that permits simultaneous statistical conclusions about two or more factors is a

Accepted Answer

A)  randomized block design. 
B)  factorial design. 
C)  completely randomized design. 
D)  multiple block design. 
A)  randomized block design. 
B)  factorial design. 
C)  completely randomized design. 
D)  multiple block design.

Question 7

The process of using the same or similar experimental units for all treatments is called

Accepted Answer

A)  factoring. 
B)  blocking. 
C)  replicating. 
D)  partitioning. 
A)  factoring. 
B)  blocking. 
C)  replicating. 
D)  partitioning.

Question 8

In an analysis of variance, one estimate of σ2 is based upon the differences between the treatment means and the

Accepted Answer

A)  means of each sample. 
B)  overall sample mean. 
C)  sum of observations. 
D)  population means. 
A)  means of each sample. 
B)  overall sample mean. 
C)  sum of observations. 
D)  population means.

Question 9

In an analysis of variance where the total sample size for the experiment is nT and the number of populations is k, the mean square due to error is

Accepted Answer

A)  SSE/(nT - k). 
B)  SSTR/(nT - k). 
C)  SSE/(k - 1). 
D)  SSTR/k. 
A)  SSE/(nT - k). 
B)  SSTR/(nT - k). 
C)  SSE/(k - 1). 
D)  SSTR/k.

Question 10

A research organization wishes to determine whether four brands of batteries for transistor radios perform equally well.Three batteries of each type were randomly selected and installed in three test radios.The number of hours of use for each battery is given below.   ​ 
a.
Use the analysis of variance procedure for completely randomized designs to determine whether there is a significant difference in the mean useful life of the four types of batteries.(Ignore the fact that there are different test radios.) Use a .05 level of significance and be sure to construct the ANOVA table.
b.
b.
Now consider the three different test radios and carry out the analysis of variance procedure for a randomized block design at the .05 level of significance.Include the ANOVA table.
c.
Compare the results in Parts a and

Accepted Answer

The answer of A research organization wishes to determine whether...

Question 11

The number of times each experimental condition is observed in a factorial design is known as

Accepted Answer

A)  partition. 
B)  replication. 
C)  blocking. 
D)  factor. 
A)  partition. 
B)  replication. 
C)  blocking. 
D)  factor.

Question 12

The heating bills for a selected sample of houses in a city using various forms of heating are given below (values are in dollars).   ​
At α = .05, test to see if there is a significant difference among the average bills of all the homes (in a city) using three forms of heating.Use both the critical and p-value approaches.

Accepted Answer

@#IMG-DLM& ​
F = 6.77 > 3.89;

Question 13

The critical F value with 6 numerator and 40 denominator degrees of freedom at α = .05 is

Accepted Answer

A)  3.77. 
B)  2.25. 
C)  2.34. 
D)  1.96. 
A)  3.77. 
B)  2.25. 
C)  2.34. 
D)  1.96.

Question 14

In a completely randomized experimental design involving five treatments, 13 observations were recorded for each of the five treatments (a total of 65 observations).Also, the design provided the following information. ​
SSTR = 300 (Sum of Squares Due to Treatments)
SST = 800 (Total Sum of Squares)
​
The number of degrees of freedom corresponding to between-treatments is

Accepted Answer

A)  60. 
B)  59. 
C)  5. 
D)  4. 
A)  60. 
B)  59. 
C)  5. 
D)  4.

Question 15

When an analysis of variance is performed on samples drawn from k populations, the mean square due to treatments (MSTR) is

Accepted Answer

A)  SSTR/nT. 
B)  SSTR/(nT - 1). 
C)  SSTR/k. 
D)  SSTR/(k - 1). 
A)  SSTR/nT. 
B)  SSTR/(nT - 1). 
C)  SSTR/k. 
D)  SSTR/(k - 1).

Question 16

The mean square is the sum of squares divided by

Accepted Answer

A)  the total number of observations. 
B)  its corresponding degrees of freedom. 
C)  its corresponding degrees of freedom minus one. 
D)  the total number of replications. 
A)  the total number of observations. 
B)  its corresponding degrees of freedom. 
C)  its corresponding degrees of freedom minus one. 
D)  the total number of replications.

Question 17

Consider the following ANOVA table. ​   ​
The mean square due to treatments equals

Accepted Answer

A)  288. 
B)  518.4. 
C)  1200. 
D)  8294.4. 
A)  288. 
B)  518.4. 
C)  1200. 
D)  8294.4.

Question 18

In a completely randomized experimental design involving five treatments, 13 observations were recorded for each of the five treatments (a total of 65 observations).Also, the design provided the following information. ​
SSTR = 300 (Sum of Squares Due to Treatments)
SST = 800 (Total Sum of Squares)
​
If, at a 5% level of significance, we want to determine whether or not the means of the five populations are equal, the critical value of F is

Accepted Answer

A)  2.53. 
B)  19.48. 
C)  4.98. 
D)  5.69. 
A)  2.53. 
B)  19.48. 
C)  4.98. 
D)  5.69.

Question 19

In testing for the equality of k population means, the number of treatments is​

Accepted Answer

A)  ​k. 
B)  ​k - 1. 
C)  ​nT. 
D)  ​nT - k. 
A)  ​k. 
B)  ​k - 1. 
C)  ​nT. 
D)  ​nT - k.

Question 20

The process of allocating the total sum of squares and degrees of freedom to the various components is called

Accepted Answer

A)  factoring. 
B)  blocking. 
C)  replicating. 
D)  partitioning. 
A)  factoring. 
B)  blocking. 
C)  replicating. 
D)  partitioning.

Consider the following ANOVA table. The null hypothesis for this ANOVA problem is

Consider the following information. The null hypothesis is to be tested at the 5% level of significance.The p-value is

An experimental design where the experimental units are randomly assigned to the treatments is known as _____ design.

In ANOVA, which of the following is not affected by whether or not the population means are equal?

In an analysis of variance problem if SST = 120 and SSTR = 90, then SSE is

An experimental design that permits simultaneous statistical conclusions about two or more factors is a

The process of using the same or similar experimental units for all treatments is called

In an analysis of variance, one estimate of σ² is based upon the differences between the treatment means and the

In an analysis of variance where the total sample size for the experiment is n_T and the number of populations is k, the mean square due to error is

The number of times each experimental condition is observed in a factorial design is known as

The critical F value with 6 numerator and 40 denominator degrees of freedom at α = .05 is

When an analysis of variance is performed on samples drawn from k populations, the mean square due to treatments (MSTR) is

The mean square is the sum of squares divided by

Consider the following ANOVA table. The mean square due to treatments equals

In testing for the equality of k population means, the number of treatments is

The process of allocating the total sum of squares and degrees of freedom to the various components is called

Data and Statistics

Descriptive Statistics: Tabular and Graphical Displays

Descriptive Statistics: Numerical Measures

Introduction to Probability

Discrete Probability Distributions

Continuous Probability Distributions

Sampling and Sampling Distributions

Interval Estimation

Hypothesis Tests

Inference About Means and Proportions With Two Populations

Inferences About Population Variances

Comparing Multiple Proportions, Tests of Independence and Goodness of Fit

Simple Linear Regression

Multiple Regression

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Exam 13: Experimental Design and Analysis of Variance

Consider the following ANOVA table. ​ ​ The null hypothesis for this ANOVA problem is

Consider the following information. ​ ​ The null hypothesis is to be tested at the 5% level of significance.The p-value is

An experimental design where the experimental units are randomly assigned to the treatments is known as _____ design.

In ANOVA, which of the following is not affected by whether or not the population means are equal?

In an analysis of variance problem if SST = 120 and SSTR = 90, then SSE is

An experimental design that permits simultaneous statistical conclusions about two or more factors is a

The process of using the same or similar experimental units for all treatments is called

In an analysis of variance, one estimate of σ2 is based upon the differences between the treatment means and the

In an analysis of variance where the total sample size for the experiment is nT and the number of populations is k, the mean square due to error is

The number of times each experimental condition is observed in a factorial design is known as

The critical F value with 6 numerator and 40 denominator degrees of freedom at α = .05 is

When an analysis of variance is performed on samples drawn from k populations, the mean square due to treatments (MSTR) is

The mean square is the sum of squares divided by

Consider the following ANOVA table. ​ ​ The mean square due to treatments equals

In testing for the equality of k population means, the number of treatments is​

The process of allocating the total sum of squares and degrees of freedom to the various components is called

Data and Statistics

Descriptive Statistics: Tabular and Graphical Displays

Descriptive Statistics: Numerical Measures

Introduction to Probability

Discrete Probability Distributions

Continuous Probability Distributions

Sampling and Sampling Distributions

Interval Estimation

Hypothesis Tests

Inference About Means and Proportions With Two Populations

Inferences About Population Variances

Comparing Multiple Proportions, Tests of Independence and Goodness of Fit

Simple Linear Regression

Multiple Regression

Filters

Consider the following ANOVA table. The null hypothesis for this ANOVA problem is

Consider the following information. The null hypothesis is to be tested at the 5% level of significance.The p-value is

In an analysis of variance, one estimate of σ² is based upon the differences between the treatment means and the

In an analysis of variance where the total sample size for the experiment is n_T and the number of populations is k, the mean square due to error is

Consider the following ANOVA table. The mean square due to treatments equals

In testing for the equality of k population means, the number of treatments is