Question 1

In the analysis of variance procedure (ANOVA), "factor" refers to

Accepted Answer

A)  the dependent variable. 
B)  the independent variable. 
C)  different levels of a treatment. 
D)  the critical value of F. 
A)  the dependent variable. 
B)  the independent variable. 
C)  different levels of a treatment. 
D)  the critical value of F.

Question 2

Consider the following information. ​   ​
The mean square due to treatments (MSTR) equals

Accepted Answer

A)  400. 
B)  500. 
C)  1687.5. 
D)  1350. 
A)  400. 
B)  500. 
C)  1687.5. 
D)  1350.

Question 3

In an analysis of variance problem involving 3 treatments and 10 observations per treatment, SSE = 399.6.The MSE for this situation is

Accepted Answer

A)  133.2. 
B)  33.32. 
C)  12.1. 
D)  11.1. 
A)  133.2. 
B)  33.32. 
C)  12.1. 
D)  11.1.

Question 4

The critical F value with 8 numerator and 29 denominator degrees of freedom at α = .05 is

Accepted Answer

A)  2.28. 
B)  3.20. 
C)  3.33. 
D)  3.64. 
A)  2.28. 
B)  3.20. 
C)  3.33. 
D)  3.64.

Question 5

An ANOVA procedure is used for data obtained from five populations.Five samples, each comprised of 25 observations, were taken from the five populations.The numerator and denominator (respectively) degrees of freedom for the critical value of F are

Accepted Answer

A)  5 and 25. 
B)  4 and 25. 
C)  4 and 124. 
D)  4 and 120. 
A)  5 and 25. 
B)  4 and 25. 
C)  4 and 124. 
D)  4 and 120.

Question 6

Part of an ANOVA table is shown below.   ​ The mean square due to treatments (MSTR) is

Accepted Answer

A)  20. 
B)  60. 
C)  18. 
D)  15. 
A)  20. 
B)  60. 
C)  18. 
D)  15.

Question 7

An ANOVA procedure is used for data obtained from four populations.Four samples, each comprised of 25 observations, were taken from the four populations.The numerator and denominator (respectively) degrees of freedom for the critical value of F are

Accepted Answer

A)  3 and 25. 
B)  4 and 25. 
C)  3 and 99. 
D)  3 and 96. 
A)  3 and 25. 
B)  4 and 25. 
C)  3 and 99. 
D)  3 and 96.

Question 8

A completely randomized design is useful when the experimental units are

Accepted Answer

A)  homogeneous. 
B)  heterogeneous. 
C)  ​clustered. 
D)  stratified. 
A)  homogeneous. 
B)  heterogeneous. 
C)  ​clustered. 
D)  stratified.

Question 9

The required condition for using an ANOVA procedure on data from several populations is that the

Accepted Answer

A)  selected samples are dependent on each other. 
B)  response variables from samples are all uniform. 
C)  sampled populations have equal variances. 
D)  sampled populations have equal means. 
A)  selected samples are dependent on each other. 
B)  response variables from samples are all uniform. 
C)  sampled populations have equal variances. 
D)  sampled populations have equal means.

Question 10

Consider the following ANOVA table. ​   ​
The null hypothesis is to be tested at the 1% level of significance.The null hypothesis should

Accepted Answer

A)  be rejected. 
B)  not be rejected. 
C)  be revised. 
D)  not be tested. 
A)  be rejected. 
B)  not be rejected. 
C)  be revised. 
D)  not be tested.

Question 11

To test whether or not there is a difference between treatments A, B, and C, a sample of 12 observations has been randomly assigned to the 3 treatments.You are given the results below. ​   ​
The null hypothesis is to be tested at the 1% level of significance.The null hypothesis

Accepted Answer

A)  should be rejected. 
B)  should not be rejected. 
C)  should be revised. 
D)  should not be tested. 
A)  should be rejected. 
B)  should not be rejected. 
C)  should be revised. 
D)  should not be tested.

Question 12

Part of an ANOVA table is shown below.   ​ At a 5% level of significance, if we want to determine whether or not the means of the populations are equal, the conclusion of the test is that

Accepted Answer

A)  all means are equal. 
B)  some means may be equal. 
C)  not all means are equal. 
D)  some means will never be equal. 
A)  all means are equal. 
B)  some means may be equal. 
C)  not all means are equal. 
D)  some means will never be equal.

Question 13

Three major automobile manufacturers have entered their cars in the Indianapolis 500 race.The speeds (in miles per hour) of the tested cars are given below.Please note the sample sizes are not equal.   ​
At α = .05, test to see if there is a significant difference in the average racing speeds of the cars of the three auto manufacturers.Use both the critical and p-value approaches.

Accepted Answer

@#IMG-DLM& ​
F = 1.56 < 4.26;

Question 14

If we are testing for the equality of three population means, we should use the​

Accepted Answer

A)  ​test statistic t. 
B)  ​test statistic z. 
C)  ​test statistic F. 
D)  ​test statistic χ2. 
A)  ​test statistic t. 
B)  ​test statistic z. 
C)  ​test statistic F. 
D)  ​test statistic χ2.

Question 15

Random samples were selected from three populations.The data obtained are shown below.Please note that the sample sizes are not equal.   ​ 
a.
Compute the overall mean   . 
b.
At α = .01 using the critical value and p-value approaches, test to see if there is a significant difference among the treatment means.

Accepted Answer

@#IMG-DLM& ​
The test statistic F = 8.71

Question 16

The test scores for selected samples of sociology students who took the course from three different instructors are shown below.   ​
At α = .05, test to see if there is a significant difference among the averages of the three groups.Use both the critical value and p-value approaches.

Accepted Answer

@#IMG-DLM& ​
F = 1.56 < 3.89;

Question 17

An ANOVA procedure is applied to data obtained from 6 samples where each sample contains 20 observations.The critical value of F occurs with

Accepted Answer

A)  6 numerator and 20 denominator degrees of freedom. 
B)  5 numerator and 20 denominator degrees of freedom. 
C)  5 numerator and 114 denominator degrees of freedom. 
D)  6 numerator and 114 denominator degrees of freedom. 
A)  6 numerator and 20 denominator degrees of freedom. 
B)  5 numerator and 20 denominator degrees of freedom. 
C)  5 numerator and 114 denominator degrees of freedom. 
D)  6 numerator and 114 denominator degrees of freedom.

Question 18

At α = .01, test to determine if the means of the three populations (from which the following samples are selected) are equal.Use both the critical and p-value approaches.

Accepted Answer

@#IMG-DLM& ​
F = 12.74 > 8.02;

Question 19

Consider the following ANOVA table. ​   ​
The null hypothesis is to be tested at the 1% level of significance.The p-value is

Accepted Answer

A)  greater than .10. 
B)  between .05 to .10. 
C)  between .025 to .05. 
D)  less than .01. 
A)  greater than .10. 
B)  between .05 to .10. 
C)  between .025 to .05. 
D)  less than .01.

Question 20

In a completely randomized experimental design involving five treatments, 13 observations were recorded for each of the five treatments (a total of 65 observations).The following information is provided. ​
SSTR = 300 (Sum of Squares Due to Treatments)
SST = 800 (Total Sum of Squares)
​
The test statistic is

Accepted Answer

A)  .11. 
B)  9.04. 
C)  3.75. 
D)  15. 
A)  .11. 
B)  9.04. 
C)  3.75. 
D)  15.

In the analysis of variance procedure (ANOVA), "factor" refers to

Consider the following information. The mean square due to treatments (MSTR) equals

In an analysis of variance problem involving 3 treatments and 10 observations per treatment, SSE = 399.6.The MSE for this situation is

The critical F value with 8 numerator and 29 denominator degrees of freedom at α = .05 is

An ANOVA procedure is used for data obtained from five populations.Five samples, each comprised of 25 observations, were taken from the five populations.The numerator and denominator (respectively) degrees of freedom for the critical value of F are

Part of an ANOVA table is shown below. The mean square due to treatments (MSTR) is

An ANOVA procedure is used for data obtained from four populations.Four samples, each comprised of 25 observations, were taken from the four populations.The numerator and denominator (respectively) degrees of freedom for the critical value of F are

A completely randomized design is useful when the experimental units are

The required condition for using an ANOVA procedure on data from several populations is that the

Consider the following ANOVA table. The null hypothesis is to be tested at the 1% level of significance.The null hypothesis should

To test whether or not there is a difference between treatments A, B, and C, a sample of 12 observations has been randomly assigned to the 3 treatments.You are given the results below. The null hypothesis is to be tested at the 1% level of significance.The null hypothesis

Part of an ANOVA table is shown below. At a 5% level of significance, if we want to determine whether or not the means of the populations are equal, the conclusion of the test is that

If we are testing for the equality of three population means, we should use the

The test scores for selected samples of sociology students who took the course from three different instructors are shown below. At α = .05, test to see if there is a significant difference among the averages of the three groups.Use both the critical value and p-value approaches.

An ANOVA procedure is applied to data obtained from 6 samples where each sample contains 20 observations.The critical value of F occurs with

At α = .01, test to determine if the means of the three populations (from which the following samples are selected) are equal.Use both the critical and p-value approaches.

Consider the following ANOVA table. The null hypothesis is to be tested at the 1% level of significance.The p-value is

Data and Statistics

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Descriptive Statistics: Numerical Measures

Introduction to Probability

Discrete Probability Distributions

Continuous Probability Distributions

Sampling and Sampling Distributions

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Inferences About Population Variances

Comparing Multiple Proportions, Tests of Independence and Goodness of Fit

Simple Linear Regression

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Exam 13: Experimental Design and Analysis of Variance

In the analysis of variance procedure (ANOVA), "factor" refers to

Consider the following information. ​ ​ The mean square due to treatments (MSTR) equals

In an analysis of variance problem involving 3 treatments and 10 observations per treatment, SSE = 399.6.The MSE for this situation is

The critical F value with 8 numerator and 29 denominator degrees of freedom at α = .05 is

An ANOVA procedure is used for data obtained from five populations.Five samples, each comprised of 25 observations, were taken from the five populations.The numerator and denominator (respectively) degrees of freedom for the critical value of F are

Part of an ANOVA table is shown below. ​ The mean square due to treatments (MSTR) is

An ANOVA procedure is used for data obtained from four populations.Four samples, each comprised of 25 observations, were taken from the four populations.The numerator and denominator (respectively) degrees of freedom for the critical value of F are

A completely randomized design is useful when the experimental units are

The required condition for using an ANOVA procedure on data from several populations is that the

Consider the following ANOVA table. ​ ​ The null hypothesis is to be tested at the 1% level of significance.The null hypothesis should

To test whether or not there is a difference between treatments A, B, and C, a sample of 12 observations has been randomly assigned to the 3 treatments.You are given the results below. ​ ​ The null hypothesis is to be tested at the 1% level of significance.The null hypothesis

Part of an ANOVA table is shown below. ​ At a 5% level of significance, if we want to determine whether or not the means of the populations are equal, the conclusion of the test is that

If we are testing for the equality of three population means, we should use the​

The test scores for selected samples of sociology students who took the course from three different instructors are shown below. ​ At α = .05, test to see if there is a significant difference among the averages of the three groups.Use both the critical value and p-value approaches.

An ANOVA procedure is applied to data obtained from 6 samples where each sample contains 20 observations.The critical value of F occurs with

At α = .01, test to determine if the means of the three populations (from which the following samples are selected) are equal.Use both the critical and p-value approaches.

Consider the following ANOVA table. ​ ​ The null hypothesis is to be tested at the 1% level of significance.The p-value is

Data and Statistics

Descriptive Statistics: Tabular and Graphical Displays

Descriptive Statistics: Numerical Measures

Introduction to Probability

Discrete Probability Distributions

Continuous Probability Distributions

Sampling and Sampling Distributions

Interval Estimation

Hypothesis Tests

Inference About Means and Proportions With Two Populations

Inferences About Population Variances

Comparing Multiple Proportions, Tests of Independence and Goodness of Fit

Simple Linear Regression

Multiple Regression

Filters

Consider the following information. The mean square due to treatments (MSTR) equals

Part of an ANOVA table is shown below. The mean square due to treatments (MSTR) is

Consider the following ANOVA table. The null hypothesis is to be tested at the 1% level of significance.The null hypothesis should

To test whether or not there is a difference between treatments A, B, and C, a sample of 12 observations has been randomly assigned to the 3 treatments.You are given the results below. The null hypothesis is to be tested at the 1% level of significance.The null hypothesis

Part of an ANOVA table is shown below. At a 5% level of significance, if we want to determine whether or not the means of the populations are equal, the conclusion of the test is that

If we are testing for the equality of three population means, we should use the

The test scores for selected samples of sociology students who took the course from three different instructors are shown below. At α = .05, test to see if there is a significant difference among the averages of the three groups.Use both the critical value and p-value approaches.

Consider the following ANOVA table. The null hypothesis is to be tested at the 1% level of significance.The p-value is