Question 1

The middle 0.95 portion of the chi-squared distribution with 9 degrees of freedom has table values of 3.32511 and 16.9190, respectively.

Accepted Answer

A) True 
 B)False

Question 2

A simple random sample of 150 people was taken to investigate whether there is a link between smoking status and having had a tertiary education. Test at the 5% level of significance. $$\begin{array} { | l | l | l | } 
\hline & \text { Non-smoker } & \text { Smoker } \
\hline \text { None-tertiary educated } & 42 & 28 \
\hline \text { Tertiary educated } & 23 & 57 \
\hline
\end{array}$$

Accepted Answer

Ho: Smoking status and tertiary educatio

Question 3

The number of degrees of freedom associated with the chi-squared test for normality is the number of intervals used minus the number of parameters estimated from the data.

Accepted Answer

A) True 
 B)False

Question 4

A chi-squared test for independence with 6 degrees of freedom results in a test statistic of 13.25. Using the chi-squared table, the most accurate statement that can be made about the p-value for this test is that 0.025 < p-value < 0.05.

Accepted Answer

A) True 
 B)False

Question 5

Which statistical technique is appropriate when we compare two or more populations of nominal data with two or more categories? A. The $z$-test of the difference between two proportions.
B. The chi-squared test of a multinomial experiment.
C. The chi-squared test of a contingency table.
D. The $z$-test of the difference between two proportions and the chi-squared test of a multinomial experiment.
E. The chi-squared test of a multinomial experiment and the chi-squared test of a contingency table.

Accepted Answer

The answer of Which statistical technique is appropriate when we...

Question 6

Whenever the expected frequency of a cell is less than 5, one possible remedy for this condition is to combine it with one or more other cells.

Accepted Answer

A) True 
 B)False

Question 7

Which statistical technique is appropriate when we describe a single population of nominal data with two or more categories? $\begin{array}{|l|l|}
\hline \text { A. } & \text { Z-test of the difference between two proportions. } \
\hline \text { B. } & \text { Chi-squared test of a multinomial experiment. } \
\hline \text { C. } & \text { Chi-squared test of a contingency table. } \
\hline \text { D. } & \text { Z test for one proportion. } \
\hline \text { E. } & \text { None of these choices are correct } \
\hline
\end{array}$

Accepted Answer

The answer of Which statistical technique is appropriate when we...

Question 8

Consider a multinomial experiment with 100 trials, and the outcome of each trial can be classified into one of 4 categories. The number of degrees of freedom associated with the chi-squared goodness-of-fit test is: $$\begin{array} { | l | l | } 
\hline \text { A. } & 99 . \
\hline \text { B. } & 104 . \
\hline \text { C. } & 96 . \
\hline \text { D. } & 3 . \
\hline
\end{array}$$

Accepted Answer

The answer of Consider a multinomial experiment with 100 trials,...

Question 9

Consumer panel preferences for three proposed fast food restaurants are as follows: $$\begin{array} { | c | c | c | } 
\hline \text { Restaurant } A & \text { Restaurant B } & \text { Restaurant C } \
\hline 48 & 62 & 40 \
\hline
\end{array}$$ Using the 0.05 level of significance, test to see if there is a preference among the three restaurants.

Accepted Answer

@#IMG-DLM& . @#IMG-DLM& At least two proportions d

Question 10

A salesperson makes five calls per day. A sample of 200 days gives the frequencies of sales volumes listed below: $$\begin{array} { | c | c | } 
\hline \text { Number of sales } & \text { Observed frequency (days) } \
\hline 0 & 10 \
\hline 1 & 38 \
\hline 2 & 69 \
\hline 3 & 63 \
\hline 4 & 18 \
\hline 5 & 2 \
\hline
\end{array}$$ Assume that the population is binomially distributed with a probability of purchase p = 0.50.
Compute the expected frequencies for x = 0, 1, 2, 3, 4 and 5 by using the binomial probability function or the binomial tables. Combine categories if necessary to satisfy the rule of five.

Accepted Answer

The answer of A salesperson makes five calls per day....

Question 11

A right-tailed area in the chi-squared distribution equals 0.01. For 4 degrees of freedom, the table value equals 13.2767.

Accepted Answer

A) True 
 B)False

Question 12

Which of the following best describes the number of degrees of freedom used in a Chi-squared test of independence if there is a contingency table with 5 rows and 3 columns? $\begin{array}{|l|l|}
\hline \text { A. } & 7 \
\hline \text { B. } & 8 \
\hline \text { C. } & 15 \
\hline \text { D. } & 10 \
\hline
\end{array}$

Accepted Answer

The answer of Which of the following best describes the...

Question 13

In a goodness-of-fit test, the null hypothesis states that the data came from a normally distributed population. The researcher estimated the population mean and population standard deviation from a sample of 500 observations. In addition, the researcher used 6 standardised intervals to test for normality. Using a 5% level of significance, the critical value for this test is: $$\begin{array} { | l | l | } 
\hline \text { A. } & 11.1433 . \
\hline \text { B. } & 9.3484 . \
\hline \text { C. } & 7.8147 . \
\hline \text { D. } & 9.4877 . \
\hline
\end{array}$$

Accepted Answer

The answer of In a goodness-of-fit test, the null hypothesis...

Question 14

A particular insurance company wants to investigate whether the gender and age of a client are related. A random sample of 350 clients of this insurance company was taken. $$\begin{array} { | l | c | c | c | } 
\hline && { \text { Age group } } \
\hline & 25 \text { and under } & \begin{array} { c } 
\text { Over } 25 \text { and } \
\text { under } 50
\end{array} & 50 \text { and over } \
\hline \text { Male } & 35 & 60 & 68 \
\hline \text { Female } & 65 & 80 & 42 \
\hline
\end{array}$$ Conduct a test to determine whether gender and age group are independent, using α of 0.01.

Accepted Answer

Ho: Gender and age group are independent

Question 15

A chi-squared test for independence with 10 degrees of freedom results in a test statistic of 17.894. Using the chi-squared table, the most accurate statement that can be made about the p-value for this test is that 0.05 < p-value < 0.10.

Accepted Answer

A) True 
 B)False

Question 16

Which of the following is the correct decision in a goodness-of-fit test, if the calculated value of the test statistic is 20.08 and there are 10 categories, testing at α of 1%? $\begin{array}{|l|l|}
\hline  A&\text {We reject Ho because $ p $-value $ <0.01 $. }\
\hline  B&\text {We retain Ho because $ \mathrm{p} $-value $ <0.01 $. }\
\hline  C&\text { We reject Ho because $ 0.01< p $-value $ <0.025 $.}\
\hline  D&\text {We retain Ho because 0.01< p-value <0.025  }\
\hline 
\end{array}$

Accepted Answer

The answer of Which of the following is the correct...

The middle 0.95 portion of the chi-squared distribution with 9 degrees of freedom has table values of 3.32511 and 16.9190, respectively.

A simple random sample of 150 people was taken to investigate whether there is a link between smoking status and having had a tertiary education. Test at the 5% level of significance. Non-smoker Smoker None-tertiary educated 42 28 Tertiary educated 23 57

The number of degrees of freedom associated with the chi-squared test for normality is the number of intervals used minus the number of parameters estimated from the data.

A chi-squared test for independence with 6 degrees of freedom results in a test statistic of 13.25. Using the chi-squared table, the most accurate statement that can be made about the p-value for this test is that 0.025 < p-value < 0.05.

Whenever the expected frequency of a cell is less than 5, one possible remedy for this condition is to combine it with one or more other cells.

Consider a multinomial experiment with 100 trials, and the outcome of each trial can be classified into one of 4 categories. The number of degrees of freedom associated with the chi-squared goodness-of-fit test is: A. 99. B. 104. C. 96. D. 3.

Consumer panel preferences for three proposed fast food restaurants are as follows: Restaurant A Restaurant B Restaurant C 48 62 40 Using the 0.05 level of significance, test to see if there is a preference among the three restaurants.

A right-tailed area in the chi-squared distribution equals 0.01. For 4 degrees of freedom, the table value equals 13.2767.

Which of the following best describes the number of degrees of freedom used in a Chi-squared test of independence if there is a contingency table with 5 rows and 3 columns? A. 7 B. 8 C. 15 D. 10

A chi-squared test for independence with 10 degrees of freedom results in a test statistic of 17.894. Using the chi-squared table, the most accurate statement that can be made about the p-value for this test is that 0.05 < p-value < 0.10.

Which of the following is the correct decision in a goodness-of-fit test, if the calculated value of the test statistic is 20.08 and there are 10 categories, testing at α of 1%? A We reject Ho because p -value <0.01 . B We retain Ho because -value <0.01 . C We reject Ho because 0.01

What Is Statistics

Types of Data, Data Collection and Sampling

Graphical Descriptive Methods Nominal Data

Graphical Descriptive Techniques Numerical Data

Numerical Descriptive Measures

Probability

Random Variables and Discrete Probability Distributions

Continuous Probability Distributions

Statistical Inference: Introduction

Sampling Distributions

Estimation: Describing a Single Population

Estimation: Comparing Two Populations

Hypothesis Testing: Describing a Single Population

Hypothesis Testing: Comparing Two Populations

Inference About Population Variances

Analysis of Variance

Simple Linear Regression and Correlation

Multiple Regression

Model Building

Nonparametric Techniques

Statistical Inference: Conclusion

Time-Series Analysis and Forecasting

Index Numbers

Decision Analysis

Filters

Exam 17: Additional Tests for Nominal Data: Chi-Squared Tests

The middle 0.95 portion of the chi-squared distribution with 9 degrees of freedom has table values of 3.32511 and 16.9190, respectively.

A simple random sample of 150 people was taken to investigate whether there is a link between smoking status and having had a tertiary education. Test at the 5% level of significance. Non-smoker Smoker None-tertiary educated 42 28 Tertiary educated 23 57

The number of degrees of freedom associated with the chi-squared test for normality is the number of intervals used minus the number of parameters estimated from the data.

A chi-squared test for independence with 6 degrees of freedom results in a test statistic of 13.25. Using the chi-squared table, the most accurate statement that can be made about the p-value for this test is that 0.025 < p-value < 0.05.

Whenever the expected frequency of a cell is less than 5, one possible remedy for this condition is to combine it with one or more other cells.

Consider a multinomial experiment with 100 trials, and the outcome of each trial can be classified into one of 4 categories. The number of degrees of freedom associated with the chi-squared goodness-of-fit test is: A. 99. B. 104. C. 96. D. 3.

Consumer panel preferences for three proposed fast food restaurants are as follows: Restaurant A Restaurant B Restaurant C 48 62 40 Using the 0.05 level of significance, test to see if there is a preference among the three restaurants.

A right-tailed area in the chi-squared distribution equals 0.01. For 4 degrees of freedom, the table value equals 13.2767.

Which of the following best describes the number of degrees of freedom used in a Chi-squared test of independence if there is a contingency table with 5 rows and 3 columns? A. 7 B. 8 C. 15 D. 10

A chi-squared test for independence with 10 degrees of freedom results in a test statistic of 17.894. Using the chi-squared table, the most accurate statement that can be made about the p-value for this test is that 0.05 < p-value < 0.10.

Which of the following is the correct decision in a goodness-of-fit test, if the calculated value of the test statistic is 20.08 and there are 10 categories, testing at α of 1%? A We reject Ho because p -value <0.01 . B We retain Ho because -value <0.01 . C We reject Ho because 0.01

What Is Statistics

Types of Data, Data Collection and Sampling

Graphical Descriptive Methods Nominal Data

Graphical Descriptive Techniques Numerical Data

Numerical Descriptive Measures

Probability

Random Variables and Discrete Probability Distributions

Continuous Probability Distributions

Statistical Inference: Introduction

Sampling Distributions

Estimation: Describing a Single Population

Estimation: Comparing Two Populations

Hypothesis Testing: Describing a Single Population

Hypothesis Testing: Comparing Two Populations

Inference About Population Variances

Analysis of Variance

Simple Linear Regression and Correlation

Multiple Regression

Model Building

Nonparametric Techniques

Statistical Inference: Conclusion

Time-Series Analysis and Forecasting

Index Numbers

Decision Analysis

Filters