An ice cream vendor sells three flavours: chocolate, strawberry and vanilla. 45% of the sales are chocolate, 30% are strawberry and the rest are vanilla. Sales are by the cone or the cup. The percentages of cones sales for chocolate, strawberry and vanilla are 75%, 60% and 40%, respectively. For a randomly selected sale, define the following events: AS1U1B11S1U1B0 = chocolate chosen. AS1U1B12S1U1B0 = strawberry chosen. AS1U1B13S1U1B0 = vanilla chosen. B = ice cream in a cone. $\bar { B }$ = ice cream in a cup. Use this information to answer the following question(s). -Find the probability that the ice cream was sold on a cone and the flavour was: a. chocolate. b. strawberry. c. vanilla.

a. P(B @#LAT-DLM& @#LAT-DLM& ) = P(B | @#LAT-DLM& ) *P( @#LAT-DLM& ) =

If P(A) = 0.65, P(B) =0.76 and P(A$\cap$ B) =0.80, then P(A $\cup$ B) is: $\begin{array}{|l|l|} \hline\text { A. } & 0.65 \\ \hline \text { B. } & 0.61 . \\ \hline \text { C. } & 0.80 \\ \hline \text { D. } & 0.02 \\ \hline \end{array}$

The answer of If P(A) = 0.65, P(B) =0.76 and...

If A and B are mutually exclusive events, with P(A) = 0.30 and P(B) = 0.40, then P(A $\cup$ B) is: $\begin{array}{|l|l|} \hline \text { A. } & 0.10 \\ \hline \text { B. } & 0.12 . \\ \hline \text { C. } & 0.70\\ \hline D.&\text { None of these choices are correct. }\\ \hline \end{array}$

The answer of If A and B are mutually exclusive...

The collection of all possible outcomes of an experiment is called: $\begin{array}{|l|l|} \hline A&\text {a simple event. }\\ \hline B&\text { a sample space.}\\ \hline C&\text { a sample.}\\ \hline D&\text {a population. }\\ \hline \end{array}$

The answer of The collection of all possible outcomes of...

Exam 6: Probability

An ice cream vendor sells three flavours: chocolate, strawberry and vanilla. 45% of the sales are chocolate, 30% are strawberry and the rest are vanilla. Sales are by the cone or the cup. The percentages of cones sales for chocolate, strawberry and vanilla are 75%, 60% and 40%, respectively. For a randomly selected sale, define the following events: A₁ = chocolate chosen. A₂ = strawberry chosen. A₃ = vanilla chosen. B = ice cream in a cone. $\bar { B }$ = ice cream in a cup. Use this information to answer the following question(s). -Find the probability that the ice cream was strawberry-flavoured, given that it was sold on a cone.

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Question 1

Correct Answer:

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P( $A _ { 2 }$ | B) = P( $A _ { 2 }$ $\cap$ B) / P(B) = 0.18 / 0.6175 = 0.2915.

Suppose P(A) = 0.25. The probability of complement of A is: A. 0.25 B. 0.50 C. -0.25 D. 0.75

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Question 2

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If events A and B have nonzero probabilities, then they can be both independent and mutually exclusive.

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Question 3

Correct Answer:

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False

If we wished to determine the probability that one or more of several events will occur in an experiment, we would use addition rules.

(True/False)

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Question 4

Suppose P(A) = 0.10, P(B) = 0.70, and P(B/A) = 0.80. a. Find P(A $\cap$ B). b. Find P(A $\cup$ B). c. Find P(A | B).

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Question 5

Marginal probability is the probability that a given event will occur, with no other events taken into consideration.

(True/False)

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Question 6

If event A does not occur, then its complement $\bar A$ must occur.

(True/False)

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Question 7

At the beginning of each year, an investment newsletter predicts whether or not the stock market will rise over the coming year. Historical evidence reveals that there is a 75% chance that the stock market will rise in any given year. The newsletter has predicted a rise for 80% of the years when the market actually rose, and has predicted a rise for 40% of the years when the market fell. Find the probability that the newsletter's prediction for next year will be correct.

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Question 8

An ice cream vendor sells three flavours: chocolate, strawberry and vanilla. 45% of the sales are chocolate, 30% are strawberry and the rest are vanilla. Sales are by the cone or the cup. The percentages of cones sales for chocolate, strawberry and vanilla are 75%, 60% and 40%, respectively. For a randomly selected sale, define the following events: A₁ = chocolate chosen. A₂ = strawberry chosen. A₃ = vanilla chosen. B = ice cream in a cone. $\bar { B }$ = ice cream in a cup. Use this information to answer the following question(s). -Find the probability that the ice cream was sold on a cone and the flavour was: a. chocolate. b. strawberry. c. vanilla.

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Question 9

The annual estimate of the number of deaths of infants is an example of the classical approach to probability.

(True/False)

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Question 10

Based on past exam results in principles of accounting you estimate that there is an 83% chance of passing the exam. This is an example of the subjective approach to probability.

(True/False)

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Question 11

Given that events A and B are independent, and that P(A) = 0.9 and P(B | A) = 0.5, then P(A $\cap$ B) = 0.45.

(True/False)

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Question 12

An insurance company has collected the following data on the gender and marital status of 300 customers. Marital Status Gender Single Married Divorced Male 25 125 30 Female 50 50 20 Suppose that a customer is selected at random. Find the probability that the customer selected is: a. a married female. b. not single. c. married, if the customer is male. d. female or divorced. e. Are gender and marital status mutually exclusive? Explain using probabilities. f. Is marital status independent of gender? Explain using probabilities.

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Question 13

A woman is expecting her second child. Her doctor has told her that she has a 50-50 chance of having another girl. If she has another girl, there is a 90% chance that she will be taller than the first. If she has a boy, however, there is only a 25% chance that he will be taller than the first child. Find the probability that the woman's second child will be taller than the first.

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Question 14

A law firm has submitted bids on two separate state contracts, A and B. The company feels that it has a 40% chance of winning contract A, and a 60% chance of winning contract B. Furthermore, the company believes that it has a 75% chance of winning contract B, given that it wins contract A. What is the probability that the firm will win at most one of the two contracts

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Question 15

A table of joint probabilities is shown below. 0.15 0.25 0.20 0.10 0.15 0.15 Calculate P( $A _ { 1 }$ | $B _ { 2 }$ ).

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Question 16

If P(A) = 0.65, P(B) =0.76 and P(A $\cap$ B) =0.80, then P(A $\cup$ B) is: A. 0.65 B. 0.61. C. 0.80 D. 0.02

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Question 17

If A and B are mutually exclusive events, with P(A) = 0.30 and P(B) = 0.40, then P(A $\cup$ B) is: A. 0.10 B. 0.12. C. 0.70 D. None of these choices are correct.

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Question 18

The collection of all possible outcomes of an experiment is called: A a simple event. B a sample space. C a sample. D a population.

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Question 19

The classical approach to assigning probability can be applied for experiments that have equally likely outcomes.

(True/False)

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Question 20

Showing 1 - 20 of 112

Suppose P(A) = 0.25. The probability of complement of A is: A. 0.25 B. 0.50 C. -0.25 D. 0.75

If events A and B have nonzero probabilities, then they can be both independent and mutually exclusive.

If we wished to determine the probability that one or more of several events will occur in an experiment, we would use addition rules.

Suppose P(A) = 0.10, P(B) = 0.70, and P(B/A) = 0.80. a. Find P(A $\cap$ B). b. Find P(A $\cup$ B). c. Find P(A | B).

Marginal probability is the probability that a given event will occur, with no other events taken into consideration.

If event A does not occur, then its complement $\bar A$ must occur.

The annual estimate of the number of deaths of infants is an example of the classical approach to probability.

Based on past exam results in principles of accounting you estimate that there is an 83% chance of passing the exam. This is an example of the subjective approach to probability.

Given that events A and B are independent, and that P(A) = 0.9 and P(B | A) = 0.5, then P(A $\cap$ B) = 0.45.

A table of joint probabilities is shown below. 0.15 0.25 0.20 0.10 0.15 0.15 Calculate P( $A _ { 1 }$ | $B _ { 2 }$ ).

If P(A) = 0.65, P(B) =0.76 and P(A $\cap$ B) =0.80, then P(A $\cup$ B) is: A. 0.65 B. 0.61. C. 0.80 D. 0.02

If A and B are mutually exclusive events, with P(A) = 0.30 and P(B) = 0.40, then P(A $\cup$ B) is: A. 0.10 B. 0.12. C. 0.70 D. None of these choices are correct.

The collection of all possible outcomes of an experiment is called: A a simple event. B a sample space. C a sample. D a population.

The classical approach to assigning probability can be applied for experiments that have equally likely outcomes.

What Is Statistics

Types of Data, Data Collection and Sampling

Graphical Descriptive Methods Nominal Data

Graphical Descriptive Techniques Numerical Data

Numerical Descriptive Measures

Random Variables and Discrete Probability Distributions

Continuous Probability Distributions

Statistical Inference: Introduction

Sampling Distributions

Estimation: Describing a Single Population

Estimation: Comparing Two Populations

Hypothesis Testing: Describing a Single Population

Hypothesis Testing: Comparing Two Populations

Inference About Population Variances

Analysis of Variance

Additional Tests for Nominal Data: Chi-Squared Tests

Simple Linear Regression and Correlation

Multiple Regression

Model Building

Nonparametric Techniques

Statistical Inference: Conclusion

Time-Series Analysis and Forecasting

Index Numbers

Decision Analysis

Filters

Exam 6: Probability

Suppose P(A) = 0.25. The probability of complement of A is: A. 0.25 B. 0.50 C. -0.25 D. 0.75

If events A and B have nonzero probabilities, then they can be both independent and mutually exclusive.

If we wished to determine the probability that one or more of several events will occur in an experiment, we would use addition rules.

Suppose P(A) = 0.10, P(B) = 0.70, and P(B/A) = 0.80. a. Find P(A ∩\cap∩ B). b. Find P(A ∪\cup∪ B). c. Find P(A | B).

Marginal probability is the probability that a given event will occur, with no other events taken into consideration.

If event A does not occur, then its complement Aˉ\bar AAˉ must occur.

The annual estimate of the number of deaths of infants is an example of the classical approach to probability.

Based on past exam results in principles of accounting you estimate that there is an 83% chance of passing the exam. This is an example of the subjective approach to probability.

Given that events A and B are independent, and that P(A) = 0.9 and P(B | A) = 0.5, then P(A ∩\cap∩ B) = 0.45.

A table of joint probabilities is shown below. 0.15 0.25 0.20 0.10 0.15 0.15 Calculate P( A1A _ { 1 }A1​ | B2B _ { 2 }B2​ ).

If P(A) = 0.65, P(B) =0.76 and P(A ∩\cap∩ B) =0.80, then P(A ∪\cup∪ B) is: A. 0.65 B. 0.61. C. 0.80 D. 0.02

If A and B are mutually exclusive events, with P(A) = 0.30 and P(B) = 0.40, then P(A ∪\cup∪ B) is: A. 0.10 B. 0.12. C. 0.70 D. None of these choices are correct.

The collection of all possible outcomes of an experiment is called: A a simple event. B a sample space. C a sample. D a population.

The classical approach to assigning probability can be applied for experiments that have equally likely outcomes.

What Is Statistics

Types of Data, Data Collection and Sampling

Graphical Descriptive Methods Nominal Data

Graphical Descriptive Techniques Numerical Data

Numerical Descriptive Measures

Random Variables and Discrete Probability Distributions

Continuous Probability Distributions

Statistical Inference: Introduction

Sampling Distributions

Estimation: Describing a Single Population

Estimation: Comparing Two Populations

Hypothesis Testing: Describing a Single Population

Hypothesis Testing: Comparing Two Populations

Inference About Population Variances

Analysis of Variance

Additional Tests for Nominal Data: Chi-Squared Tests

Simple Linear Regression and Correlation

Multiple Regression

Model Building

Nonparametric Techniques

Statistical Inference: Conclusion

Time-Series Analysis and Forecasting

Index Numbers

Decision Analysis

Filters

Suppose P(A) = 0.10, P(B) = 0.70, and P(B/A) = 0.80. a. Find P(A $\cap$ B). b. Find P(A $\cup$ B). c. Find P(A | B).

If event A does not occur, then its complement $\bar A$ must occur.

Given that events A and B are independent, and that P(A) = 0.9 and P(B | A) = 0.5, then P(A $\cap$ B) = 0.45.

A table of joint probabilities is shown below. 0.15 0.25 0.20 0.10 0.15 0.15 Calculate P( $A _ { 1 }$ | $B _ { 2 }$ ).

If P(A) = 0.65, P(B) =0.76 and P(A $\cap$ B) =0.80, then P(A $\cup$ B) is: A. 0.65 B. 0.61. C. 0.80 D. 0.02

If A and B are mutually exclusive events, with P(A) = 0.30 and P(B) = 0.40, then P(A $\cup$ B) is: A. 0.10 B. 0.12. C. 0.70 D. None of these choices are correct.