Exam 12: Further Topics in Algebra

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Solve the problem. -What are the odds in favor of drawing a 3 from these cards? Solve the problem. -What are the odds in favor of drawing a 3 from these cards?

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Solve the problem. -What are the odds in favor of spinning a D on this spinner? Solve the problem. -What are the odds in favor of spinning a D on this spinner?

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Find the probability. -A lottery game contains 22 balls numbered 1 through 22 . What is the probability of choosing a ball numbered 23?

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Find all natural number values for n for which the given statement is false. - n!>10nn ! > 10 \mathrm { n }

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Use mathematical induction to prove that the statement is true for every positive integer n. - 35+46+57++(n+3)(n+5)=n(2n2+27n+115)63 \cdot 5 + 4 \cdot 6 + 5 \cdot 7 + \ldots + ( n + 3 ) ( n + 5 ) = \frac { n \left( 2 n ^ { 2 } + 27 n + 115 \right) } { 6 }

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Find the common ratio r for the given infinite geometric sequence. -A small start-up consulting company hopes to have 7 times the clientele it had the previous year for the next 2 years. If the company just meets its targets each of the 2 years and it had 7 clients to Begin with, how many clients does it have at the end of 2 years?

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Use the sequence feature of a graphing calculator to evaluate the sum of the first 10 terms of the arithmetic sequence. Round to the nearest thousandth, if necessary. -The beginning population of a town was 36,000. If the population decreased by 250 people per year, how many people lived in the town 15 years later?

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Write out the first five terms of the sequence. - an=n26n2+6a _ { n } = \frac { n ^ { 2 } - 6 } { n ^ { 2 } + 6 }

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Solve the problem. -What are the odds in favor of spinning an A on this spinner? Solve the problem. -What are the odds in favor of spinning an A on this spinner?

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Solve the problem. -How many 4-digit numbers can be formed using the digits 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, if repetitions of digits are allowed?

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Use a graphing calculator to evaluate the sum. Round to the nearest thousandth. - k=510(0.53)k\sum _ { \mathrm { k } = 5 } ^ { 10 } ( 0.53 ) \mathrm { k }

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Evaluate the sum. - i=11500i\sum _ { i = 1 } ^ { 1500 } i

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Write the first n terms of the given arithmetic sequence (the value of n is indicated in the question). - a1=6,d=1,n=6a _ { 1 } = 6 , d = 1 , n = 6

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Find a general term an for the geometric sequence. - a1=17,r=6a _ { 1 } = - \frac { 1 } { 7 } , r = - 6

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Evaluate the sum using the given information. - x1=4,x2=0,x3=3,x4=4x _ { 1 } = 4 , x _ { 2 } = 0 , x _ { 3 } = 3 , x _ { 4 } = - 4 , and x5=2x _ { 5 } = 2 i=15(2xi+3)\sum _ { i = 1 } ^ { 5 } \left( - 2 x _ { i } + 3 \right)

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Use mathematical induction to prove that the statement is true for every positive integer n. -The series of sketches below starts with an equilateral triangle having sides of length 1 (one). In the following steps, equilateral triangles are constructed by joining the midpoints of the sides of the preceding triangle. Develop a formula for the area of the nth new triangle. Use math induction to prove your answer. Use mathematical induction to prove that the statement is true for every positive integer n. -The series of sketches below starts with an equilateral triangle having sides of length 1  (one). In the following steps, equilateral triangles are constructed by joining the midpoints of the sides of the preceding triangle. Develop a formula for the area of the nth new triangle. Use math induction to prove your answer.

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Solve the problem. -Solve the problem. -

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Evaluate the sum. Round to two decimal places, if necessary. - i=255i\sum _ { i = 2 } ^ { 5 } \frac { - 5 } { i }

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Use the summation properties to evaluate the series. The following rules may be needed: i=1ni=n(n+1)2;i=1ni2=n(n+1)(2n+1)6;i=1ni3=n2(n+1)24.\sum _ { i = 1 } ^ { n } i = \frac { n ( n + 1 ) } { 2 } ; \quad \sum _ { i = 1 } ^ { n } i ^ { 2 } = \frac { n ( n + 1 ) ( 2 n + 1 ) } { 6 } ; \quad \sum _ { i = 1 } ^ { n } i ^ { 3 } = \frac { n ^ { 2 } ( n + 1 ) ^ { 2 } } { 4 } . - i=15(4i2i3)\sum _ { i = 1 } ^ { 5 } \left( - 4 i ^ { 2 } - i ^ { 3 } \right)

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Evaluate the expression. - (41)\left( \begin{array} { l } 4 \\1\end{array} \right)

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