Exam 12: Further Topics in Algebra

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Find the nth term of the geometric sequence. - a1=1792,r=14,n=2\mathrm { a } _ { 1 } = 1792 , \mathrm { r } = \frac { 1 } { 4 } , \mathrm { n } = 2

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Provide an appropriate response. -Consider the selections of particular thirteen card bridge hands. Is this a combination, a permutation, or neither?

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Use the summation properties to evaluate the series. The following rules may be needed: i=1ni=n(n+1)2;i=1ni2=n(n+1)(2n+1)6;i=1ni3=n2(n+1)24.\sum _ { i = 1 } ^ { n } i = \frac { n ( n + 1 ) } { 2 } ; \quad \sum _ { i = 1 } ^ { n } i ^ { 2 } = \frac { n ( n + 1 ) ( 2 n + 1 ) } { 6 } ; \quad \sum _ { i = 1 } ^ { n } i ^ { 3 } = \frac { n ^ { 2 } ( n + 1 ) ^ { 2 } } { 4 } . - i=13(3i2+4i5)\sum _ { i = 1 } ^ { 3 } \left( - 3 i ^ { 2 } + 4 i - 5 \right)

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Provide an appropriate response. -Explain how to use the binomial theorem to expand ( (9a7b)n( 9 a - 7 b ) ^ { n }

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Evaluate the expression. -P(7, 0)

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Write the first n terms of the given arithmetic sequence (the value of n is indicated in the question). - a1=86,d=7a _ { 1 } = 86 , d = 7

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Provide an appropriate response. -What is true of both the first term and the last term in a binomial expansion?

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Find the common ratio r for the given infinite geometric sequence. -A town has a population of 1000 people and is increasing by 9% every year. What will the population be at the end of 8 years?

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Use the summation properties to evaluate the series. The following rules may be needed: i=1ni=n(n+1)2;i=1ni2=n(n+1)(2n+1)6;i=1ni3=n2(n+1)24.\sum _ { i = 1 } ^ { n } i = \frac { n ( n + 1 ) } { 2 } ; \quad \sum _ { i = 1 } ^ { n } i ^ { 2 } = \frac { n ( n + 1 ) ( 2 n + 1 ) } { 6 } ; \quad \sum _ { i = 1 } ^ { n } i ^ { 3 } = \frac { n ^ { 2 } ( n + 1 ) ^ { 2 } } { 4 } . - i=13(42i3)\sum _ { i = 1 } ^ { 3 } \left( - 4 - 2 i ^ { 3 } \right)

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Decide whether the given sequence is finite or infinite. - a1=6; for 2n50,an=7an1a _ { 1 } = 6 \text {; for } 2 \leq n \leq 50 , a _ { n } = 7 \cdot a _ { n - 1 }

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Find the first term and the common difference for the arithmetic sequence. Round approximations to the nearest hundredth. - a15=62,a35=162a _ { 15 } = 62 , a _ { 35 } = 162

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Find a general term an for the geometric sequence. - a1=4,r=45a _ { 1 } = 4 , r = \frac { 4 } { 5 }

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Solve the problem. -Suppose that a family has 5 children and that the probability of having a girl is 12\frac { 1 } { 2 } . What is the probability of having at least four girls?

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Solve the problem. -How many 10-digit telephone numbers (area code + number) are possible if the first digit cannot be zero, the first three digits cannot be 800 or 900, and the number must end in 0000?

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Use the formula for Sn\mathrm { S } _ { \mathbf { n } } to find the sum of the first five terms of the geometric sequence. - 43,163,643,2563,\frac { 4 } { 3 } , \frac { 16 } { 3 } , \frac { 64 } { 3 } , \frac { 256 } { 3 } , \ldots

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Solve the problem. -A die is rolled 11 times. Find the probability of rolling exactly 11 ones.

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Use the sequence feature of a graphing calculator to evaluate the sum of the first 10 terms of the arithmetic sequence. Round to the nearest thousandth, if necessary. -Martin saves $3 on the first day of a 40-day period, $6 on the second day, and so on. For the next 40 days, he increases the amount saved by $6 each day (instead of $3 each day). How much will he Have saved after 80 days?

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Find the first term and the common ratio for the geometric sequence. Round approximations to the nearest hundredth. - a2=14.4,a4=46.66a _ { 2 } = - 14.4 , a _ { 4 } = - 46.66

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Evaluate the expression. - (103)\left( \begin{array} { c } 10 \\3\end{array} \right)

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Use the sequence feature of a graphing calculator to evaluate the sum of the first 10 terms of the arithmetic sequence. Round to the nearest thousandth, if necessary. - an=3.9n+8.96a _ { n } = 3.9 n + 8.96

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