Exam 9: Vectors in Two and Three Dimensions

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Sketch a graph of the polar equation. r=3cosθr = \sqrt { 3 } - \cos \theta

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Find a rectangular-coordinate equation for the curve by eliminating the parameter. x=t+3,y=tt+3x = t + 3 , y = \frac { t } { t + 3 }

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Convert the point whose polar coordinates are (8,5π/4)( 8,5 \pi / 4 ) to rectangular coordinates.

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Convert the equation to polar form. x2y2=9x ^ { 2 } - y ^ { 2 } = 9

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Test the polar equation for symmetry with respect to the polar axis, the pole, and the line θ=π/2\theta = \pi / 2 . r=5secθr = 5 \sec \theta

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Convert the polar equation to rectangular coordinates. r+cosθ=3r + \cos \theta = 3

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Find a rectangular-coordinate equation for the curve by eliminating the parameter. x=16t2,y=4+tx = 16 - t ^ { 2 } , y = 4 + t

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Convert the rectangular coordinates to polar coordinates with r>0 and 0θ<2πr > 0 \text { and } 0 \leq \theta < 2 \pi (0,5)( 0 , - \sqrt { 5 } )

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Find parametric equations for the line with the given properties.Passing through (12,8)( 12,8 ) and the origin

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Convert the point whose polar coordinates are (3,π/6)( \sqrt { 3 } , \pi / 6 ) to rectangular coordinates.

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Use DeMoivre's Theorem to find the indicated power. (33i)3( \sqrt { 3 } - 3 i ) ^ { 3 }

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Use DeMoivre's Theorem to find the indicated power. (13i)5( 1 - \sqrt { 3 } i ) ^ { 5 }

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Convert the rectangular coordinates to polar coordinates with r>0 and 0θ<2πr > 0 \text { and } 0 \leq \theta < 2 \pi (0,2)( 0 , - \sqrt { 2 } )

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Sketch a graph of the rectangular equation. [Hint: First convert the equation to polar coordinates.] (x2+y2+3y)2=9(x2+y2)\left( x ^ { 2 } + y ^ { 2 } + 3 y \right) ^ { 2 } = 9 \left( x ^ { 2 } + y ^ { 2 } \right)

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Find two polar coordinate representations for the point (3,π/3)( 3 , \pi / 3 ) , one with r>0r > 0 , and the other with r<0r < 0

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Test the polar equation for symmetry with respect to the polar axis, the pole, and the line θ=π/2\theta = \pi / 2 . r2=9cos2θr ^ { 2 } = 9 \cos 2 \theta I  symmetric about the polar axis \text { symmetric about the polar axis } II  symmetric about the pole \text { symmetric about the pole } III  symmetric about the line θ=π/2\text { symmetric about the line } \theta = \pi / 2

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Convert the polar equation to rectangular coordinates. y3=cscθ\frac { y } { 3 } = \csc \theta

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Find the modulus and the argument for the complex number. z=10iz = - 10 i

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If a projectile is fired with an initial speed of v0v _ { 0 } ft/s at an angle α\alpha above the horizontal, then its position after t seconds is given by the parametric equations x=(v0cosα)t and y=(v0sinα)t16t2x = \left( v _ { 0 } \cos \alpha \right) t \text { and } y = \left( v _ { 0 } \sin \alpha \right) t - 16 t ^ { 2 } where x and y are measured in feet.Suppose a gun fires a bullet into the air with an initial speed of 1024 ft/s at an angle of 3030 ^ { \circ } to the horizontal. What is the maximum height attained by the bullet?

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Write the complex number in polar form. z=13iz = - 1 - \sqrt { 3 } i

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