Exam 12: Integration and Its Applications

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Use the Midpoint Rule n = 4 to approximate the area of the following region. f(y)=14y,[2,4]f ( y ) = \frac { 1 } { 4 } y , [ 2,4 ]  Use the Midpoint Rule n = 4 to approximate the area of the following region.  f ( y ) = \frac { 1 } { 4 } y , [ 2,4 ]

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Evaluate the integral (x6+7x43)dx\int \left( x ^ { 6 } + 7 x ^ { 4 } - 3 \right) d x .

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Find the indefinite integral of the following function and check the result by differentiation. 5x(x2+5)4dx\int \frac { 5 x } { \left( x ^ { 2 } + 5 \right) ^ { 4 } } d x

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Use the values 02f(x)dx=8\int _ { 0 } ^ { 2 } f ( x ) d x = 8 and 02g(x)dx=3\int _ { 0 } ^ { 2 } g ( x ) d x = 3 to evaluate the definite integral 02[f(x)2g(x)]dx\int _ { 0 } ^ { 2 } [ f ( x ) - 2 g ( x ) ] d x .

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Evaluate the integral (2x29x9)dx\int \left( - 2 x ^ { 2 } - 9 x - 9 \right) d x .

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A ball is thrown vertically upwards from a height of 10 ft with an initial velocity of 70 ft per second. How high will the ball go?

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Find the indefinite integral. x4x2+4dx\int \frac { x } { - 4 x ^ { 2 } + 4 } d x

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Find the indefinite integral 4dx\int 4 d x and check your result by differentiation.

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Find the average value of the function over the given interval. f(x)=7x3f ( x ) = 7 \sqrt [ 3 ] { x } on [0,8]

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Find the indefinite integral. 7x298x3dx\int \frac { 7 x ^ { 2 } } { 9 - 8 x ^ { 3 } } d x

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Two models, R1=7.21+0.58tR _ { 1 } = 7.21 + 0.58 t and R2=7.21+0.43tR _ { 2 } = 7.21 + 0.43 t , are given for revenue (in billions of dollars per year) for a large corporation. Both models are estimates of revenues for 2007 through 2011, with t = 7 corresponding to 2007. Which model is projecting the greater revenue? How much more total revenue does that model project over the five-year period?

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Use the rectangles to approximate the area of the region. Compare your result with the exact area obtained with a definite integral. f(x)=2x+3,[0,1]f ( x ) = - 2 x + 3 , [ 0,1 ]  Use the rectangles to approximate the area of the region. Compare your result with the exact area obtained with a definite integral.  f ( x ) = - 2 x + 3 , [ 0,1 ]

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Evaluate the integral 210e0.1xdx\int 210 e ^ { 0.1 x } d x

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Sketch the region whose area is given by the definite integral and then use a geometric formula to evaluate the integral. 339x2dx\int _ { - 3 } ^ { 3 } \sqrt { 9 - x ^ { 2 } } d x

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