Exam 5: Inverse, Exponential, and Logarithmic Functions

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solve each equation. Give the solution set (a) with an exact value and then (b) with an approximation to the nearest thousandth. - ln(log3x)=1\ln (\log 3 x)=-1

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(a) {13101/e}\left\{\frac{1}{3} 10^{1 / e}\right\}
(b) {.778}\{.778\}

Consider the equation log2x+log2(x4)=5\log _{2} x+\log _{2}(x-4)=5 . (a) Solve the equation analytically. If there is an extraneous value, what is it? (b) To support the solution in part (a), we may graph y1=log2x+log2(x4)5y_{1}=\log _{2} x+\log _{2}(x-4)-5 and find the xx -intercept. Write an expression for y1y_{1} using the change-of-base rule with base 10 , and graph the function to support the solution from part (a). (c) Use the graph to solve the inequality log2x+log2(x4)<5\log _{2} x+\log _{2}(x-4)<5 .

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(a) x=8x=8 ; the extraneous value is x=4x=-4 .
(b) y1=logxlog2+log(x4)log25y_{1}=\frac{\log x}{\log 2}+\frac{\log (x-4)}{\log 2}-5
 (a)  x=8 ; the extraneous value is  x=-4 . (b)  y_{1}=\frac{\log x}{\log 2}+\frac{\log (x-4)}{\log 2}-5      (c)  (4,8)
(c) (4,8)(4,8)

The concentration of pollutants in a stream is given by y=.06e3xy=.06 e^{-3 x} , where yy is the amount of pollutant in grams per liter and xx is the distance, in kilometers, downstream from the source of the pollution. Match each question with one of the solutions A, B, C, or D. -How far downstream is the pollutant level equal to .02gm/L.02 \mathrm{gm} / \mathrm{L} ?

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A

An unstable radioactive isotope decays according to the equation y=2.53(.97)ty=2.53(.97)^{t} where yy is the number of grams remaining and tt is the time measured in minutes. Match each question with one of the solutions A, B, C, or D. -How long will it take for the material to decay to half its initial amount?

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Consider the equation log6x+log6(x5)=1\log _{6} x+\log _{6}(x-5)=1 . (a) Solve the equation analytically. If there is an extraneous value, what is it? (b) To support the solution in part (a), we may graph y1=log6x+log6(x5)1y_{1}=\log _{6} x+\log _{6}(x-5)-1 and find the xx -intercept. Write an expression for y1y_{1} using the change-of-base rule with base 10, and graph the function to support the solution from part (a). (c) Use the graph to solve the inequality log6x+log6(x5)<1\log _{6} x+\log _{6}(x-5)<1 .

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solve each equation. Give the solution set (a) with an exact value and then (b) with an approximation to the nearest thousandth. - log(lnx)=0\log (\ln x)=0

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Use the power, quotient, and product properties of logarithms to write logp3q2r4\log \frac{p^{3} q^{2}}{\sqrt[4]{r}} as an equivalent expression.

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solve each equation. Give the solution set (a) with an exact value and then (b) with an approximation to the nearest thousandth. - 52x+1=34x15^{2 x+1}=3^{4 x-1}

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Solve A=PertA=P e^{r t} for rr .

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Use the power, quotient, and product properties of logarithms to write logabc3\log \frac{a}{\sqrt{b c^{3}}} as an equivalent expression.

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A sample of radioactive material has a half-life of about 1250 years. An initial sample weighs 12 grams. (a) Find a formula for the decay function for this material. (b) Find the amount left after 5000 years. (c) Find the time for the initial amount to decay to 3 grams.

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Use a calculator to find an approximation of each logarithm to the nearest thousandth. (a) log17.6\log 17.6 (b) log9750\log _{9} 750 (c) ln901\ln 901

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Suppose that $25,000\$ 25,000 is invested at 5.7%5.7 \% for 12 years. Find the total amount present at the end of thime period if the interest is compounded (a) quarterly and (b) continuously.

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Match each equation with its graph. - y=exy=e^{x}

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Match each equation with its graph. - y=lnxy=\ln x

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Match each equation with its graph. - y=exy=e^{x}

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One of your friends is taking another mathematics course and tells you, "I have no idea what an expression like log712\log _{7} 12 really means." Write an explanation of what it means, and tell how you can find an approximation for it with a calculator.

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Solve the equation 9x+3=(13)x79^{x+3}=\left(\frac{1}{3}\right)^{x-7} analytically.

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Match each equation with its graph. - y=lnxy=\ln x

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Match each equation with its graph - y=exy=e^{x}

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