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Solve the Problem z=12x2+y2z = \frac { 1 } { 2 } \sqrt { x ^ { 2 } + y ^ { 2 } }

Question 340

Multiple Choice

Solve the problem.
-Find the centroid of the region enclosed between the cone with equation z=12x2+y2z = \frac { 1 } { 2 } \sqrt { x ^ { 2 } + y ^ { 2 } } and the plane with equation z=3z = 3 .


A) (xˉ,yˉ,zˉ) =(0,0,125) ( \bar { x } , \bar { y } , \bar { z } ) = \left( 0,0 , \frac { 12 } { 5 } \right)
B) (x,y,z) =(0,0,2) ( \overline { \mathrm { x } } , \overline { \mathrm { y } } , \overline { \mathrm { z } } ) = ( 0,0,2 )
C) (xˉ,yˉ,zˉ) =(0,0,94) ( \bar { x } , \bar { y } , \bar { z } ) = \left( 0,0 , \frac { 9 } { 4 } \right)
D) (xˉ,yˉ,zˉ) =(0,0,158) ( \bar { x } , \bar { y } , \bar { z } ) = \left( 0,0 , \frac { 15 } { 8 } \right)

Correct Answer:

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