Exam 10: Topics In Analytic Geometry

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Use a graphing utility to graph the conic.Determine the angle θ\theta through which the axes are rotated. x2+2xy+y2=25x ^ { 2 } + 2 x y + y ^ { 2 } = 25

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Find the standard form of the equation of the ellipse with the given characteristics. Foci: (5,1),(5,5)( - 5 , - 1 ) , ( - 5,5 ) , endpoints of the major axis: (5,5),(5,9)( - 5 , - 5 ) , ( - 5,9 )

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Select the graph of the following equation, showing both sets of axes. (x)28(y)28=1\frac { \left( x ^ { \prime } \right) ^ { 2 } } { 8 } - \frac { \left( y ^ { \prime } \right) ^ { 2 } } { 8 } = 1

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Select the graph of the equation as a circle, a parabola, an ellipse, or a hyperbola. y29y4x21=0y ^ { 2 } - 9 y - 4 x - 21 = 0

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Give the standard form of the equation of the parabola with the given characteristics. vertex: (-7, -9) directrix: x=9x = - 9

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Eliminate the parameter and write the corresponding rectangular equation whose graph represents the curve. x=1+3cosθx = 1 + 3 \cos \theta y=1+5sinθy = 1 + 5 \sin \theta

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Write the equation of the ellipse that has its center at the origin, focus at (1, 0) and vertex at (9, 0).

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Describe the graph of the polar equation and find the corresponding rectangular equation.Select the correct graph. r=2r = 2

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Select the graph of the equation. r=5sec(θπ2)r = 5 \sec \left( \theta - \frac { \pi } { 2 } \right)

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Find a polar equation of the conic with its focus at the pole. Conics \quad\quad Vertex or vertices Parabola \quad\quad ( 4,0 )

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Roads are often designed with parabolic surfaces to allow rain to drain off.A particular road that is 44 feet wide is 0.4 foot higher in the center than it is on the sides (see figure).  Roads are often designed with parabolic surfaces to allow rain to drain off.A particular road that is 44 feet wide is 0.4 foot higher in the center than it is on the sides (see figure).     Where  a = 44  ft,  b = 0.4 \mathrm { ft }  Find an equation of the parabola that models the road surface.(Assume that the origin is at the center of the road.)  Where a=44a = 44 ft, b=0.4ftb = 0.4 \mathrm { ft } Find an equation of the parabola that models the road surface.(Assume that the origin is at the center of the road.)

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Find the standard form of the equation of the hyperbola with the given characteristics. focies: (±4,0), asymptotes: y=±5xy = \pm 5 x

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Convert the polar equation to rectangular form. r=2sinθr = 2 \sin \theta

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Select the curve represented by the parametric equations. x=4(t+1) y=|t-4|

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Rotate the axes to eliminate the xy-term in the equation.Then write the equation in standard form. xy+3=0x y + 3 = 0

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Use the discriminant to classify the graph. x210xy8y218=0x ^ { 2 } - 10 x y - 8 y ^ { 2 } - 18 = 0

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Find the standard form of the equation of the ellipse with vertices (0,±8)( 0 , \pm 8 ) and eccentricity e=38e = \frac { 3 } { 8 } .

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Find the vertex and focus of the parabola from the given equation and select its graph. 2x+y2=02 x + y ^ { 2 } = 0

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Select the curve represented by the parametric equations. Cycloid: x=Θ+sinΘ,y=4cosΘx = \Theta + \sin \Theta , y = 4 - \cos \Theta

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Select the curve represented by the parametric equations.(indicate the orientation of the curve) x=3-4t y=4+3t

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