Exam 10: Topics In Analytic Geometry

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Find the standard form of the equation of the hyperbola with the given characteristics and center at the origin. Foci: (±10,0)( \pm 10,0 ) ; asymptotes: y=±34xy = \pm \frac { 3 } { 4 } x

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Determine the angle θ\theta through which the axes are rotated.Round your answer to two decimal places. 24x2+66xy+13y2=3224 x ^ { 2 } + 66 x y + 13 y ^ { 2 } = 32

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Find the center and vertices of the ellipse. x281+y236=1\frac { x ^ { 2 } } { 81 } + \frac { y ^ { 2 } } { 36 } = 1

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Select the graph of the polar equation using symmetry, zeros, maximum r-values, and any other additional points. r=4sin(2θ)r = 4 \sin ( 2 \theta )

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Find the standard form of the equation of the hyperbola with the given characteristics. vertices: (-10, -2), (0, -2) Asymptotes: y = ± 45\frac { 4 } { 5 } x

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Find the rectangular coordinates of the point given in polar coordinates.Round your results to two decimal places. (5,1.5)( 5,1.5 )

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Select the graph of the equation as a circle, a parabola, an ellipse, or a hyperbola. y2+8x+5y+26=0y ^ { 2 } + 8 x + 5 y + 26 = 0

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Find the standard form of the equation of the ellipse with the given characteristics. Foci: (0,0),(0,6)( 0,0 ) , ( 0,6 ) ; major axis of length 12.

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Find the center and foci of the ellipse. (x+1)27+(y5)216=1\frac { ( x + 1 ) ^ { 2 } } { 7 } + \frac { ( y - 5 ) ^ { 2 } } { 16 } = 1

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A straight road rises with an inclination of 0.22 radian from the horizontal.Find the slope of the road and the change in elevation over a one-mile stretch of the road.Round your answer to four decimal places for the m round your answers to nearest whole number for change in elevation.

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Eliminate the parameter and write the corresponding rectangular equation whose graph represents the curve. x=t+2x = t + 2 y=t2y = t ^ { 2 }

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Find the equation of the parabola with vertex at (1, 5) and focus at (-5, 5).

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Find a set of parametric equations for the rectangular equation. t=2xt = 2 - x y=4x2y = 4 x - 2

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Select the graph for following equation. (x2)216+(y+1)2=1\frac { ( x - 2 ) ^ { 2 } } { 16 } + ( y + 1 ) ^ { 2 } = 1

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Select the polar equation of graph. Select the polar equation of graph.

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Select the correct graph of the polar equation.Find an interval for θ\theta for which the graph is traced only once. r=cos(3θ2)r = \cos \left( \frac { 3 \theta } { 2 } \right)

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Find the rectangular coordinates of the point given in polar coordinates.Round your results to two decimal places. (8,7π5)\left( 8 , \frac { 7 \pi } { 5 } \right)

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A simply supported beam is 12 meters long and has a load at the center (see figure). 1 aa Where, a=12,b=2a = 12 , b = 2 The deflection of the beam at its center is 2 centimeters.Assume that the shape of the deflected beam is parabolic.Write an equation of the parabola.(Assume that the origin is at the center of the deflected beam.)

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An elliptical stained-glass insert is to be fitted in a 4ft by 6ft rectangular opening (see figure). An elliptical stained-glass insert is to be fitted in a 4ft by 6ft rectangular opening (see figure).   Using the coordinate system shown, find an equation for the ellipse. Using the coordinate system shown, find an equation for the ellipse.

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Use the following results the polar equation of the hyperbolla x2a2y2b2=1\frac { x ^ { 2 } } { a ^ { 2 } } - \frac { y ^ { 2 } } { b ^ { 2 } } = 1 is r2=b21e2cos2θr ^ { 2 } = \frac { - b ^ { 2 } } { 1 - e ^ { 2 } \cos ^ { 2 } \theta } to write the polar form of the equation of the conic x216y29=1\frac { x ^ { 2 } } { 16 } - \frac { y ^ { 2 } } { 9 } = 1 .

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