Exam 10: Topics In Analytic Geometry

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Find the standard form of the equation of the parabola with the given characteristic and vertex at the origin. Vertical axis and passes through the point (-8,-8)

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A projectile is launched at a height of h feet above the ground at an angle of θ\theta with the horizontal.The initial velocity is v0v _ { 0 } feet per second, and the path of the projectile is modeled by the parametric equations x=(v0cosθ)t and y=h+(v0sinθ)t16t2x = \left( v _ { 0 } \cos \theta \right) t \text { and } y = h + \left( v _ { 0 } \sin \theta \right) t - 16 t ^ { 2 } . Select the correct graph of the path of a projectile launched from ground level at the value of θ\theta and v0v _ { 0 } . θ=45,v0=114\theta = 45 ^ { \circ } , v _ { 0 } = 114 feet per second

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Eliminate the parameter and write the corresponding rectangular equation whose graph represents the curve. x=3(t+1)x = 3 ( t + 1 ) y=t3y = | t - 3 |

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Find the inclination (in degrees) of the line with a slope of m.Round your answer to one decimal places. m=3m = - 3

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Use the following results the polar equation of the ellipse x2a2+y2b2=1\frac { x ^ { 2 } } { a ^ { 2 } } + \frac { y ^ { 2 } } { b ^ { 2 } } = 1 is r2=b21e2cos2θr ^ { 2 } = \frac { b ^ { 2 } } { 1 - e ^ { 2 } \cos ^ { 2 } \theta } to write the polar form of the equation of the conic x225+y216=1\frac { x ^ { 2 } } { 25 } + \frac { y ^ { 2 } } { 16 } = 1 .

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Consider the equation r=sinkθr = \sin k \theta .Select the correct graph of the equation for k=2.5k = 2.5 .

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Find the standard form of the equation of the ellipse with the given characteristics. Center: (0,4)( 0,4 ) ; a = 2c; Vertices: (8,8),(8,8)( - 8,8 ) , ( 8,8 ) , where a - thr semimajor axis, b - semiminor axis and c2=a2b2c ^ { 2 } = a ^ { 2 } - b ^ { 2 } .

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Find the standard form of the equation of the hyperbola with the given characteristics. vertices: (1, -2), (5, -2) Asymptotes: y=52x,y=52xy = \frac { 5 } { 2 } x , y = - \frac { 5 } { 2 } x

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Find the standard form of the equation of the hyperbola with the given characteristics. foci: (±4,0)( \pm 4,0 ) asymptotes: y=±2xy = \pm 2 x

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Convert the polar equation to rectangular form. r2=7sinθr ^ { 2 } = 7 \sin \theta

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Find the standard form of the equation of the ellipse with the given characteristics. Vertices: (0,4),(8,4)( 0,4 ) , ( 8,4 ) ; minor axis of length 10.

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A projectile is launched at a height of h feet above the ground at an angle of θ\theta with the horizontal.The initial velocity is v0v _ { 0 } feet per second, and the path of the projectile is modeled by the parametric equations x=(v0cosθ)t and y=h+(v0sinθ)t16t2x = \left( v _ { 0 } \cos \theta \right) t \text { and } y = h + \left( v _ { 0 } \sin \theta \right) t - 16 t ^ { 2 } . Select the correct graph of the path of a projectile launched from ground level at the value of θ\theta and v0v _ { 0 } . θ=60\theta = 60 ^ { \circ } , v0=93v _ { 0 } = 93 feet per second

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Select the correct graph of the following equations of the hyperbola and find the center of the hyperbola. (y+3)21/81(x2)21/64=1\frac { ( y + 3 ) ^ { 2 } } { 1 / 81 } - \frac { ( x - 2 ) ^ { 2 } } { 1 / 64 } = 1

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The xyx ^ { \prime } y ^ { \prime } -coordinate system has been rotated θ\theta degrees from the xyx y -coordinate system.The coordinates of a point in the xyx y -coordinate system are given.Find the coordinates of the point in the rotated coordinate system. θ=90\theta = 90 ^ { \circ } , (2,2)( 2,2 )

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Find the vertex and focus of the parabola. x2+12y=0x ^ { 2 } + 12 y = 0

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Find the rectangular coordinates of the point given in polar coordinates.Round your results to two decimal places. (5.8,2.62)( 5.8,2.62 )

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Find the standard form of the equation of the ellipse with the given characteristics and center at the origin. Vertices: (0,±7); focies: (0,±4)

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Find the center and vertices which located on the major axis of the ellipse from given equation and select its graph. x29+y21/9=1\frac { x ^ { 2 } } { 9 } + \frac { y ^ { 2 } } { 1 / 9 } = 1

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Select the correct graph of the polar equation.Find an interval for θ\theta for which the graph is traced only once. r=48cosθr = 4 - 8 \cos \theta

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Find the standard form of the equation of the parabola with the given characteristics. Vertex: (1,2)( 1,2 ) ; directrix: y=2y = - 2

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