Exam 13: The Integral

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The velocity of a particle moving in a straight line is given by v=t(t2+6)4+3tv = t \left( t ^ { 2 } + 6 \right) ^ { 4 } + 3 t . Find an expression for the position s after time t.

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Evaluate the integral. e0.05x1e0.05x dx\int \frac { e ^ { - 0.05 x } } { 1 - e ^ { - 0.05 x } } \mathrm {~d} x

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Evaluate the integral. 61042exdx\int _ { 6 } ^ { 10 } 42 e ^ { x } d x

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Evaluate the integral. 493x dx\int _ { 4 } ^ { 9 } 3 \sqrt { x } \mathrm {~d} x

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Calculate the Riemann Sum for the integral using n = 4. ​ 40x2dx\int _ { - 4 } ^ { 0 } x ^ { 2 } d x

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The normal distribution curve which models, distributions of data in a wide range of applications, is given by the function p(x)=12πe(xμ)2/2δ2p ( x ) = \frac { 1 } { \sqrt { 2 \pi } } e ^ { - ( x - \mu ) ^ { 2 } / 2 \delta ^ { 2 } } where π=3.14159265\pi = 3.14159265 \ldots and σ \sigma and μ \mu are constants called the standard deviation and the mean, respectively. Its graph is shown in the figure.  The normal distribution curve which models, distributions of data in a wide range of applications, is given by the function   p ( x ) = \frac { 1 } { \sqrt { 2 \pi } } e ^ { - ( x - \mu ) ^ { 2 } / 2 \delta ^ { 2 } }  where  \pi = 3.14159265 \ldots  and       \sigma     and       \mu     are constants called the standard deviation and the mean, respectively. Its graph is shown in the figure.    ? In a survey, consumers were asked to rate a new toothpaste on a scale of 1-10. The resulting data are modeled by a normal distribution with  \mu = 4.1  and  \sigma = 1.2  . The percentage of consumers who gave the toothpaste a score between a and b on the section is given by  \int _ { a } ^ { b } p ( x ) d x    Use a Riemann sum with n = 10 to estimate the percentage of customers who rated the toothpaste 5 or higher. (Use the range 4.5 to 10.5.) Round your answer to the nearest whole number.   ? In a survey, consumers were asked to rate a new toothpaste on a scale of 1-10. The resulting data are modeled by a normal distribution with μ=4.1\mu = 4.1 and σ=1.2\sigma = 1.2 . The percentage of consumers who gave the toothpaste a score between a and b on the section is given by abp(x)dx\int _ { a } ^ { b } p ( x ) d x Use a Riemann sum with n = 10 to estimate the percentage of customers who rated the toothpaste 5 or higher. (Use the range 4.5 to 10.5.) Round your answer to the nearest whole number.

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