Exam 10: Introduction to the Derivative

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Calculate the average rate of change of the given function over the interval [1,3][ 1,3 ] . 0 1 2 3 f(x) 5 1 1 -13 ​ ​

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Use a graph to determine whether the given function is continuous on its domain. If it is not continuous on its domain, list the points of discontinuity. f(x)=x4x+4f ( x ) = \frac { | x | } { 4 x } + 4

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If D(t)D ( t ) is the Dow Jones Average at time t and limt+D(t)=+\lim_ { t \rightarrow + \infty } D ( t ) = + \infty , is it possible that the Dow will fluctuate indefinitely into the future

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The chart shows the total annual support for the arts in the U.S. by federal, state, and local government in 1995-2003 as a function of time in years ( t=0t = 0 represents 1995) together with the regression line.  The chart shows the total annual support for the arts in the U.S. by federal, state, and local government in 1995-2003 as a function of time in years (  t = 0  represents 1995) together with the regression line.       Over the period  [ 0,4 ]  the average rate of change of government funding for the arts was _____ the rate predicted by the regression line.   Over the period [0,4][ 0,4 ] the average rate of change of government funding for the arts was _____ the rate predicted by the regression line.

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Compute f(3.2)f ^ { \prime } ( - 3.2 ) . ​ f(x)=5.9x+9.3f ( x ) = 5.9 x + 9.3

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Estimate the limit numerically. limx13ex13\lim _ { x \rightarrow 13 } e ^ { x - 13 }

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The function R(t)=1,120+79tt3R ( t ) = 1,120 + 79 t - t ^ { 3 } represents the value of the U.S. dollar in Indian rupees as a function of the time t in days. Find the average rates of change of R(t)R ( t ) over the time intervals [t,t+h][ t , t + h ] , where t is as indicated and h=1h = 1 , 0.10.1 , 0.010.01 , and 0.00010.0001 days. Hence, estimate (using h=0.0001h = 0.0001 ) the instantaneous rate of change of  R \text { R } at time t=2t = 2 . Select your answer rounded to the nearest whole number.

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The function given below gives the cost to manufacture x items. Estimate (using h=0.0001h = 0.0001 ) the instantaneous rate of change of the cost at the production level x=500x = 500 . ​ C(x)=9,500+5xx210,000C ( x ) = 9,500 + 5 x - \frac { x ^ { 2 } } { 10,000 } ​ Enter your answer as a number without the units rounded to the nearest tenth.

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Calculate the average rate of change of the given function over the interval [7,8][ 7,8 ] . f(x)=x27+15xf ( x ) = \frac { x ^ { 2 } } { 7 } + \frac { 15 } { x }

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Match each function with the corresponding graph.

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Compute f(a)f ^ { \prime } ( a ) algebraically for a=4a = - 4 . f(x)=8x+8f ( x ) = 8 x + 8

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Compute f(2.9)f ^ { \prime } ( - 2.9 ) . f(x)=4.4x+5.9f ( x ) = 4.4 x + 5.9

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Use the graph to compute limt2f(x)\lim_ { t \rightarrow -2 } f ( x ) . ​  Use the graph to compute  \lim_ { t \rightarrow -2 } f ( x )  . ​

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Calculate the limit algebraically. limx4(x+x)\lim _ { x \rightarrow 4 } ( x + \sqrt { x } )

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Calculate the limit algebraically. ​ limx0(x+3)\lim _ { x \rightarrow 0 } ( x + 3 )

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Estimate the limit numerically. limx0x2x+4\lim _ { x \rightarrow 0 } \frac { x ^ { 2 } } { x + 4 }

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Compute f(5)f ^ { \prime } ( 5 ) . ​ ​ f(x)=3.1xf ( x ) = \frac { 3.1 } { x } ​ Enter your answer rounded to the nearest thousandth.

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For the slope 2.2, determine at which of the labeled points on the graph the tangent line has that slope. ​ For the slope 2.2, determine at which of the labeled points on the graph the tangent line has that slope. ​   ​

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Compute f(3)f ^ { \prime } ( 3 ) . f(x)=3.3x2+xf ( x ) = 3.3 x ^ { 2 } + x

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Calculate the limit algebraically. limx0+11x26x\lim _ { x \rightarrow 0 ^ { + } } \frac { 11 } { x ^ { 2 } - 6 x }

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