Exam 11: Analysis of Variance
Exam 1: What Is Statistics78 Questions
Exam 2: Describing Data: Frequency Distributions and Graphic Presentation101 Questions
Exam 3: Describing Data: Numerical Measures186 Questions
Exam 4: A Survey of Probability Concepts121 Questions
Exam 5: Discrete Probability Distributions111 Questions
Exam 6: The Normal Probability Distribution129 Questions
Exam 7: Sampling Methods and the Central Limit Theorem78 Questions
Exam 8: Estimation and Confidence Intervals128 Questions
Exam 9: One-Sample Tests of a Hypothesis223 Questions
Exam 10: Two-Sample Tests of Hypothesis87 Questions
Exam 11: Analysis of Variance80 Questions
Exam 12: Linear Regression and Correlation150 Questions
Exam 13: Multiple Regression and Correlation Analysis98 Questions
Exam 14: Chi-Square Applications for Nominal Data113 Questions
Exam 15: Index Numbers65 Questions
Exam 16: Time Series and Forecasting86 Questions
Exam 17: An Introduction to Decision Theory37 Questions
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Given the following Analysis of Variance table for three treatments each with six observations.
What are the degrees of freedom for the numerator and denominator?

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D
i. To employ ANOVA, the populations should have approximately equal standard deviations.
ii. To employ ANOVA, the populations being studied must be approximately normally distributed.
iii. The least number of sources of variation in ANOVA is two.
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Two accounting professors decided to compare the variation of their grading procedures. To accomplish this they each graded the same 10 exams with the following results:
What are the degrees of freedom for the denominator of the F ratio?

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Correct Answer:
D
What distribution does the F distribution approach as the sample size increases?
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i. If the computed value of F is 4.01 and the critical value is 2.67, we would conclude that all the population means are equal.F5
Ii) Rejecting the null hypothesis in ANOVA indicates that the population means are equal.
Iii) The null hypothesis for an ANOVA is μ1 - μ2 ≠ μ3
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ii. The calculated F value must be equal to or greater than one (1) iii. The shape of the F distribution is symmetrical. i. The test statistic used in ANOVA is t
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Suppose that an automobile manufacturer designed a radically new lightweight engine and wants to recommend the grade of gasoline to use. The four grades are: below regular, regular, premium, and super premium. The test car made three trial runs on the test track using each of the four grades. Assuming any grade can be used at the 0.05 level, what is the critical value of F using 0.05 level of significance? 

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i. For the population means, the alternate hypothesis used in the analysis of variance test states that µ1 = µ2 = µ3.
Ii) For an ANOVA test, rejection of the null hypothesis does not identify which populations differ
Significantly.
Iii) If the computed value of F is 4.01 and the critical value is 2.67, we would conclude that all the population means are equal.
(Multiple Choice)
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i. The F distribution is positively skewed and its values may range from 0 to plus infinity.
ii. The F distribution's curve is positively skewed
Iii) Like Student's t distribution, a change in the degrees of freedom causes a change in the shape of the F distribution.
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i. The shape of the F distribution is determined by the degrees of freedom for the F-statistic, one for the numerator and one for the denominator.
Ii) Like Student's t distribution, a change in the degrees of freedom causes a change in the shape of the
F distribution.
Iii) The calculated F value must be equal to or greater than zero (0)
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A random sample of 30 executives from companies with assets over $1 million was selected and asked for their annual income and level of education. The ANOVA comparing the average income among three levels of education rejected the null hypothesis. The Mean Square Error (MSE) was 243.7. The following table summarized the results:
When comparing the mean annual incomes for executives with Undergraduate and Master's Degree or more, the following 95% confidence interval can be constructed:

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In ANOVA analysis, when the null hypothesis is rejected, we can find which means are different by:
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A manufacturer of automobile transmissions uses three different processes. The management ordered a study of the production costs to see if there is a difference among the three processes. A summary of the findings is shown below.
What is the mean square for error?

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Which of the following is NOT a characteristic of the F distribution?
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A random sample of 30 executives from companies with assets over $1 million was selected and asked for their annual income and level of education. The ANOVA comparing the average income among three levels of education rejected the null hypothesis. The Mean Square Error (MSE) was
243.7.
The following table summarized the results:
When comparing the mean salaries to test for differences between treatment means, the t statistic is based on:

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Given the following Analysis of Variance table for three treatments each with six observations.
What is the mean square for treatments?

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A manufacturer of automobile transmissions uses three different processes. The management ordered a study of the production costs to see if there is a difference among the three processes. A summary of the findings is shown below.
What are the total degrees of freedom?

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A manufacturer of automobile transmissions uses three different processes. The management ordered a study of the production costs to see if there is a difference among the three processes. A summary of the findings is shown below.
What are the degrees of freedom for the numerator of the F ratio?

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