Exam 7: Estimating Parameters and Determining Sample Sizes

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Fill in the blank: The critical value zα/2z _ { \alpha / 2 } that corresponds to a ______% confidence level is 2.33 .

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In a Gallup poll of 557 randomly selected adults, 284 said that they were underpaid. Identify the best point estimate of the percentage of adults who say they are underpaid. Construct a 95% confidence interval estimate of the percentage of adults who say that that they are underpaid. Can we safely conclude that the majority of adults say that they are underpaid?

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51.0%;46.8%<p<55.1%51.0 \% ; 46.8 \% < p < 55.1 \% .
No, the confidence interval shows that the population percentage might be 50%50 \% or less, so we cannot safely conclude that the majority of adults say that they are underpaid.

The following is a 95 % confidence interval of the proportion of female medical school students: 0.449<p<0.5110.449 < p < 0.511 based on data from the American Medical Association. What is the point estimate of the proportion of females in the population of medical school students? Write a brief statement that correctly interprets the confidence interval given.

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point estimate of proportion: 0.480. We have 95% confidence that the limits of 0.449 and 0.511 contain the true
value of the proportion of females in the population of medical school students.

Describe the process for finding the confidence interval for a population proportion

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You want to be 95% confident that the sample variance is within 40% of the population variance. Find the appropriate minimum sample size.

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Find the critical value χR2\chi _ { \mathrm { R } } ^ { 2 } corresponding to a sample size of 19 and a confidence level of 99 percent.

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Use the given data to find the minimum sample size required to estimate the population proportion. Margin of error: 0.028; confidence level: 99%; p and q unknown

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Do one of the following, as appropriate: (a) Find the critical value =α/2,= \alpha / 2 , (b) find the critical value tα/2t _ { \alpha / 2 } { } ^ { \circ } 99 % ; n=17 ; α\alpha is unknown; population appears to be normally distributed.

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How do you determine whether to use the z or t distribution in computing the margin of error, E=zα/2σn or E=tα/2sn?E = z _ { \alpha / 2 } \cdot \frac { \sigma } { \sqrt { n } } \text { or } E = t _ { \alpha / 2 } \cdot \frac { s } { \sqrt { n } } ?

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Identify the distribution that applies to the following situation: In constructing a confidence interval of μ\mu , you have 50 sample values and they appear to be from a population with a skewed distribution. The population standard deviation is not known.

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Of 380 randomly selected medical students, 21 said that they planned to work in a rural community. Find a 95 % confidence interval for the true proportion of all medical students who plan to work in a rural community.

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Use the given degree of confidence and sample data to construct a confidence interval for the population proportion p . n=195, x=162 ; 95 % confidence

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Use the given degree of confidence and sample data to construct a confidence interval for the population mean μ\mu Assume that the population has a normal distribution. n=30 , xˉ=84.6\bar { x } = 84.6 s=10.5,90 % confidence

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Define in as clear language as possible how a 95% confidence interval can be used for hypothesis tests.

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A group of 59 randomly selected students have a mean score of 29.5 with a standard deviation of 5.2 on a placement test. What is the 90 % confidence interval for the mean score, μ\mu , of all students taking the test?

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Do one of the following, as appropriate: (a) Find the critical value zα/2z _ { \alpha / 2 } (b) find the critical value tα/2t _ { \alpha / 2 } (c) state that neither the normal nor the t distribution applies. 90% confidence interval for μ\mu n=9 ; σ=4.2\sigma = 4.2 population appears to be very skewed.

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Express the confidence interval (0.432,0.52) in the form of p^±E\hat { p } \pm \mathrm { E }

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Use the given degree of confidence and sample data to construct a confidence interval for the population proportion p. n=56, x=30 ; 95% confidence

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Find the critical value χR2\chi _ { \mathrm { R } } ^ { 2 } corresponding to a sample size of 19 and a confidence level of 99 percent.

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Fifty people are selected randomly from a certain population and it is found that 12 people in the sample are over six feet tall. What is the best point estimate of the proportion of people in the population who are over 6 feet tall?

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