Exam 4: Exponential and Logarithmic Functions

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Solve the problem. -Use the graph of y=2xy = 2 ^ { - x } to graph the function . Write the domain and range in interval notation f(x)=2xf ( x ) = 2 ^ { - x }

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Solve the problem. -The enrollment at one Midwestern college is approximated by the formula P=3000(1.08)tP = 3000 ( 1.08 ) ^ { t } where tt is the number of years after 2000 . What is the first year in which you would expect enrollment to surpass 3,700 ?

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Simplify the expression without using a calculator. - log5/4(256625)\log _ { 5 / 4 } \left( \frac { 256 } { 625 } \right)

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Determine if the statement is true or false. - log4(1p)=log4p\log _ { 4 } \left( \frac { 1 } { p } \right) = - \log _ { 4 } p

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Solve the problem. -Use logb30.319\log _ { b } 3 \approx 0.319 , use the properties of logarithms to approximate the following. Do not use a calcu logb81\log _ { b } 81

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Solve the equation. Write the solution set with the exact solutions. Also give approximate solutions to 4 decimal places if necessary. - log5(6x14)=1+log5(x2)\log _ { 5 } ( 6 x - 14 ) = 1 + \log _ { 5 } ( x - 2 )

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Choose the one alternative that best completes the statement or answers the question. A relation in x and y is given. Determine if the relation defines y as a one-to-one function of x. - {(6,8),5,8),(4,6),(1,3)}\{ ( - 6,8 ) , - 5 , - 8 ) , ( 4 , - 6 ) , ( 1,3 ) \}

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Solve the equation. Write the solution set with the exact values given in terms of natural or common logarithms. Also give approximate solutions to 4 decimal places, if necessary. - 55x+6=48x5 ^ { 5 x + 6 } = 4 ^ { 8 x } ; use natural logarithms

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Solve the equation. Write the solution set with the exact solutions. Also give approximate solutions to 4 decimal places if necessary. - 2log6(6p8)4=22 \log _ { 6 } ( 6 p - 8 ) - 4 = - 2

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Use transformations of the graph y=exy = e ^ { x } to graph the function. Write the domain and range in interval notation. - f(x)=ex+1f ( x ) = - e ^ { x } + 1

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Choose the one alternative that best completes the statement or answers the question. Evaluate the function at the given value of x. Round to 4 decimal places if necessary. - h(x)=(13)x;h(3)h ( x ) = \left( \frac { 1 } { 3 } \right) ^ { x } ; \quad h ( - 3 )

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Choose the one alternative that best completes the statement or answers the question. Solve for the indicated variable. - A=PertA = P e ^ { r t } for rr

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Write the equation in logarithmic form. - 105=100,00010 ^ { 5 } = 100,000

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Solve the problem. -Newton's law of cooling indicates that the temperature of a warm object will decrease exponentially with time and will approach the temperature of the surrounding air. The temperature T(t)T ( t ) is modeled by T(t)=Ta+(T0Ta)ektT ( t ) = T _ { a } + \left( T _ { 0 } - T _ { a } \right) e ^ { - k t } . In this model, TaT _ { a } represents the temperature of the surrounding air, T0T _ { 0 } represents the initial temperature of the object and tt is the time after the object starts cooling. The value of kk is the cooling rate and is a constant related to the physical properties of the object. A cake comes out of the oven at 335F335 ^ { \circ } \mathrm { F } and is placed on a cooling rack in a 70F70 ^ { \circ } \mathrm { F } kitchen. After checking the temperature several minutes later, it is determined that the cooling rate kk is 0.0500.050 . Write a function that models the temperature T(t)T ( t ) (in F{ } ^ { \circ } \mathrm { F } ) of the cake tt minutes after being removed from the oven.

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Approximate the value of the logarithm to four decimal places. - log512\log 512

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Write as the sum or difference of logarithms and fully simplify, if possible. Assume the variable represents a positive real number. - lne7x4+y8\ln \sqrt [ 8 ] { \frac { e ^ { 7 } } { x ^ { 4 } + y } }

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Solve the equation. Write the solution set with the exact solutions. Also give approximate solutions to 4 decimal places if necessary. - log(x22x)=log15\log \left( x ^ { 2 } - 2 x \right) = \log 15

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Solve the problem. -A pie comes out of the oven at 275F275 ^ { \circ } \mathrm { F } and is placed to cool in a 70F70 ^ { \circ } \mathrm { F } kitchen. The temperature of the pie TT (in F{ } ^ { \circ } \mathrm { F } ) after tt minutes is given by T=70+205e0.018tT = 70 + 205 e ^ { - 0.018 t } . The pie is cool enough to cut when the temperature reaches 130F130 ^ { \circ } \mathrm { F } . How long will this take? Round to the nearest minute.

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Determine whether the two functions are inverses. - f(x)=6x+6 and g(x)=6+x6f ( x ) = 6 x + 6 \text { and } g ( x ) = \frac { 6 + x } { 6 }

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Solve the problem. -Newton's law of cooling indicates that the temperature of a warm object will decrease exponentially with time and will approach the temperature of the surrounding air. The temperature T(t)T ( t ) is modeled by T(t)=Ta+(T0Ta)ektT ( t ) = T _ { a } + \left( T _ { 0 } - T _ { a } \right) e ^ { - k t } . In this model, TaT _ { a } represents the temperature of the surrounding air, T0T _ { 0 } represents the initial temperature of the object and tt is the time after the object starts cooling. The value of kk is the cooling rate and is a constant related to the physical properties of the object. Water in a water heater is originally 131F131 ^ { \circ } \mathrm { F } . The water heater is shut off and the water cools to the temperature of the surrounding air, which is 80F80 ^ { \circ } \mathrm { F } . The water cools slowly because of the insulation inside the heater, and the rate of cooling is 0.003480.00348 . Dominic does not like to shower with water less than 116F116 ^ { \circ } \mathrm { F } . If Dominic waits 24hr24 \mathrm { hr } after the heater is shut off, will the water still be warm enough for a shower? How warm will the water be?

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