Exam 4: Number Theory and Cryptography

arrow
  • Select Tags
search iconSearch Question
  • Select Tags

Use the Euclidean algorithm to find (a) gcd(203,101)\operatorname { gcd } ( 203,101 ) . (b) gcd(34,21)\operatorname { gcd } ( 34,21 ) .

Free
(Essay)
4.9/5
(27)
Correct Answer:
Verified

(a) We have 203=2101+1203 = 2 \cdot 101 + 1 and 101=1011101 = 101 \cdot 1 . It follows that gcd(203,101)=1\operatorname { gcd } ( 203,101 ) = 1 .
(b) We have 34=121+13,21=113+8,13=18+5,8=15+3,5=13+2,3=12+134 = 1 \cdot 21 + 13,21 = 1 \cdot 13 + 8,13 = 1 \cdot 8 + 5,8 = 1 \cdot 5 + 3,5 = 1 \cdot 3 + 2,3 = 1 \cdot 2 + 1 , 2=212 = 2 \cdot 1 Hence gcd(34,21)=1\operatorname { gcd } ( 34,21 ) = 1 .

Prove or disprove that a positive integer congruent to 1 modulo 4 cannot have a prime factor congruent to

Free
(Short Answer)
4.9/5
(33)
Correct Answer:
Verified

This is false, since 9 = 4 · 2 + 1 = 3 · 3.

Find each of the following values. (a) 18mod718 \bmod 7 (b) 88mod13- 88 \bmod 13 (c) 289mod17289 \bmod 17

Free
(Essay)
4.8/5
(35)
Correct Answer:
Verified

(a) We have 18 = 2 · 7 + 4. Hence 18 mod 7 = 4. (b) We have −88 = −7 · 13 + 3. Hence −88 mod 13 = 3. (c) We have 289 = 17 · 17. Hence 289 mod 17 = 0.

What is the hexadecimal expansion of the (ABC)16+(2 F5)16?( \mathrm { ABC } ) _ { 16 } + ( 2 \mathrm {~F} 5 ) _ { 16 } ?

(Essay)
4.7/5
(28)

The binary expansion of an integer is (110101)2. What is the base 10 expansion of this integer?

(Essay)
4.9/5
(38)

Use the Euclidean algorithm to find (a) gcd(201,302)\operatorname { gcd } ( 201,302 ) . (b) gcd(144,233)\operatorname { gcd } ( 144,233 ) .

(Essay)
4.8/5
(46)

 Decide whether 17522(mod17)\text { Decide whether } 175 \equiv 22 ( \bmod 17 )

(Short Answer)
4.8/5
(30)

Find the prime factorization of 45617.

(Essay)
4.9/5
(35)

Prove or disprove that there are six consecutive composite integers.

(Essay)
4.9/5
(31)

Find the prime factorization of 111111.

(Essay)
4.9/5
(26)
close modal

Filters

  • Essay(0)
  • Multiple Choice(0)
  • Short Answer(0)
  • True False(0)
  • Matching(0)