Exam 8: Sampling Methods and the Central Umit Theorem

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Student's t is used when

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A survey of 144 retail stores revealed that the average price of a DVD was $375 with a standard Error of $20. If 90% and 95% confidence intervals were developed to estimate the true cost of the DVD, what similarities would they have?

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The following summarizes the amount of snowfall in Ontario over the past number of years. The following summarizes the amount of snowfall in Ontario over the past number of years.   Determine a 95% confidence interval for the average annual snowfall. Determine a 95% confidence interval for the average annual snowfall.

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College X is concerned about their employees making use of their email for non-business purposes. A random sample of 400 e-mails discovered 60 messages that were not business related. The 90% Confidence interval for the population proportion is:

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College X is concerned about their employees making use of their email for non-business purposes. A random sample of 400 e-mails discovered 70 messages that were not business related. The 95% Confidence interval for the population proportion is:

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A group of statistics students decided to conduct a survey at their university to find the average (mean) amount of time students spent studying per week. Assuming a standard deviation of 6 Hours, what is the required sample size if the error is to be less than ½ hour with a 95% level of Confidence?

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A student wanted to quickly construct a 95% confidence interval for the average age of students in Her statistics class. She randomly selected 9 students. Their average age was 19.1 years with a Standard deviation of 1.5 years. What is the best point estimate for the population mean?

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(i. Reasoning from a sample or small group to the entire group or population is called statistical Inference. (ii. A 95 percent confidence interval implies that about 95 out of 100 similarly constructed intervals Will include the parameter being estimated. (iii) For a sampling distribution of the means, 95% percent of the means would be between ± 1.96 Standard deviations.

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A confidence interval for a population mean

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When using Student's t to compute an interval estimate,

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The Kennel Club wants to estimate the proportion of children that have a dog as a pet. Assume a 95% level of confidence and that the club estimates that 30% of the children have a dog as a pet. If The club wants the estimate to be within 3% of the population proportion, how many children would They need to contact?

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i. The test statistic t has n-1 degrees of freedom. ii. All t distributions have the same mean of zero and a standard deviation of 1. iii. The t distribution is more spread out and flatter at the center than is the standard normal Distribution. However, as the sample size increases, the t distribution curve approaches the Standard normal distribution.

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The manager of the college cafeteria wants to estimate the mean amount spent per customer per Purchase. A sample of 10 customers revealed the following amounts spent: The manager of the college cafeteria wants to estimate the mean amount spent per customer per Purchase. A sample of 10 customers revealed the following amounts spent:   Find the 99 percent confidence limits for the mean amount spent. Sample mean = $4.53, s = $1.00 Find the 99 percent confidence limits for the mean amount spent. Sample mean = $4.53, s = $1.00

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The following summarizes the amount of snowfall in Ontario over the past number of years. The following summarizes the amount of snowfall in Ontario over the past number of years.   Determine a 98% confidence interval for the average annual snowfall. Determine a 98% confidence interval for the average annual snowfall.

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The mean weight of trucks traveling on a particular section of Highway 401 is not known. A Provincial highway inspector needs an estimate of the mean. He selects a random sample of 49 Trucks passing the weighing station and finds the mean is 15.8 tons, with a standard deviation of the Sample of 3.8 tons. What is the 95 percent interval for the population mean?

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Recently, a university surveyed recent graduates of the English Department for their starting Salaries. Four hundred graduates returned the survey. The average salary was $55,000 with a Standard deviation of $2,500. What is the best point estimate of the population mean?

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A statistics professor wishes to estimate the average mark on a term test for a course that has Multiple sections and many students. A survey of some of the students registered for the course Reveals the following results: A statistics professor wishes to estimate the average mark on a term test for a course that has Multiple sections and many students. A survey of some of the students registered for the course Reveals the following results:   The student from the course wonders whether the population mean could have been 75 or 80. The student from the course wonders whether the population mean could have been 75 or 80.

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College X is concerned about their employees making use of their email for non-business purposes. You have been approached to assist in this matter. College X decides on a 99% confidence level And state that the estimation proportion must be within 2 percent of the population proportion. A Pilot survey reveals that 8 out of 50 emails sampled were not for business purposes. How many Emails should be surveyed to meet your requirements?

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If 2,000 card-carrying members of a political party were randomly sampled, and 1,600 said they Wanted a change in leadership, what is the 95% confidence interval for the true population Percentage for all of the card-carrying members of the party who wanted a change in leadership?

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A statistics professor wishes to estimate the average mark on a term test for a course that has Multiple sections and many students. A survey of some of the students registered for the course Reveals the following results: A statistics professor wishes to estimate the average mark on a term test for a course that has Multiple sections and many students. A survey of some of the students registered for the course Reveals the following results:   Determine a 98% confidence interval for the term test results. Determine a 98% confidence interval for the term test results.

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