Exam 8: Quadratic Equations

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A projectile is thrown upward so that its distance above the ground after tt sec is given by h(t)=15t2+600th(t)=-15 t^{2}+600 t . After how many seconds does it reach its maximum height?

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Solve the equation. - x8=9x\mathrm{x}-8=\frac{9}{\mathrm{x}}

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Solve by making a u-substitution - (3m+3)212(3m+3)+35=0(3 m+3)^{2}-12(3 m+3)+35=0

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Without graphing the function, state the shift(s) that are applied to the graph of f(x)=x2f(x)=x^{2} to graph the given function. If the graph of f(x)=x2f(x)=x^{2} must be rotated about the xx -axis, state this. - f(x)=(x+16)298f(x)=(x+16)^{2}-98

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Find the vertex - f(x)=(x+6)26f(x)=(x+6)^{2}-6

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Solve by factoring. - x281=0x^{2}-81=0

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Solve the equation. - 8x+24x2=8x24\frac{8}{x+2}-\frac{4}{x-2}=\frac{8}{x^{2}-4}

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Find the vertex of the parabola associated with the quadratic equation. - y=3x2+24x+51y=3 x^{2}+24 x+51

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Find the xx - and yy -intercepts. If no xx -intercepts exist, state so. - f(x)=x23x+8f(x)=x^{2}-3 x+8

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Find the xx - and yy -intercepts of the parabola associated with the quadratic equation. If the parabola does not have any xx -intercepts, state "no xx -intercepts." - y=x2+5x6y=-x^{2}+5 x-6

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State the domain and range of the given function - f(x)=(x+8)26f(x)=-(x+8)^{2}-6

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Approximate to the nearest tenth when necessary. -The area of a circle is 90 square meters. Find the radius of the circle.

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Solve the equation by completing the square - x2+90=19x\mathrm{x}^{2}+90=19 \mathrm{x}

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Solve the rational inequality. Express your solution on a number line using interval notation. - x8x+9>0\frac{x-8}{x+9}>0  Solve the rational inequality. Express your solution on a number line using interval notation. - \frac{x-8}{x+9}>0

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Solve the rational inequality. Express your solution on a number line using interval notation. - (x1)(3x)(x2)20\frac{(x-1)(3-x)}{(x-2)^{2}} \leq 0  Solve the rational inequality. Express your solution on a number line using interval notation. - \frac{(x-1)(3-x)}{(x-2)^{2}} \leq 0

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Graph the given parabola. - y=x24y=x^{2}-4  Graph the given parabola. - y=x^{2}-4

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Approximate to the nearest tenth when necessary. -The velocity v\mathrm{v} , in ft/s\mathrm{ft} / \mathrm{s} , of a free falling object after t\mathrm{t} seconds is given by the formula v 32t32 \mathrm{t} until the object reaches terminal velocity. The terminal velocity Vt\mathrm{V}_{\mathrm{t}} of a free-falling object is the highest velocity that the object can attain, and it depends on the mass of the object as well as its projected area. The distance dd , in feet, that a free-falling object falls in tt seconds is given by the formula de=16t2\mathrm{d} e=16 \mathrm{t}^{2} until it reaches terminal velocity. After that occurs, the distance that it falls is found by multiplying the terminal velocity Vt\mathrm{V}_{\mathrm{t}} by the amount of time after it reaches terminal velocity. Find the distance that a parachutist travels in t=45\mathrm{t}=45 seconds if she has the given terminal velocity Vt=16ft/s\mathrm{V}_{\mathrm{t}}=16 \mathrm{ft} / \mathrm{s} .

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Solve by factoring. - x2x42=0\mathrm{x}^{2}-\mathrm{x}-42=0

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Graph the function, and state its domain and range - f(x)=x34 f(x)=x^{3}-4  Graph the function, and state its domain and range -  f(x)=x^{3}-4

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Solve by making a u-substitution - x2/32x1/315=0x^{2 / 3}-2 x^{1 / 3}-15=0

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