Exam 2: Graphs, Lines, and Inequalities

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Give the x-intercepts and y-intercepts of the graph. -Give the x-intercepts and y-intercepts of the graph. -

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Solve the problem. -Solve the problem. -  What were the total sales for the first 6 months of 1990 ? What were the total sales for the first 6 months of 1990 ?

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Solve the problem. -The value, vv , in hundreds of dollars, of Juan's computer is approximated by v=12t+8v=-\frac{1}{2} t+8 , where tt is the number of years since he first bought the computer. Graph the equation and use the graph to estimate the value of the computer 4 years after it was purchased.  Solve the problem. -The value,  v , in hundreds of dollars, of Juan's computer is approximated by  v=-\frac{1}{2} t+8 , where  t  is the number of years since he first bought the computer. Graph the equation and use the graph to estimate the value of the computer 4 years after it was purchased.

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Find an equation of the the line satisfying the given conditions. -Through (4,3); perpendicular to 9x+5y=519 x+5 y=51

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Solve and graph the inequality and graph the solution. - 8x+43<52\frac{8 x+4}{3}<\frac{5}{2}  Solve and graph the inequality and graph the solution. - \frac{8 x+4}{3}<\frac{5}{2}

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Find the xx - and yy -intercepts for the equation. Then graph the equation. - 16y4x=816 y-4 x=-8  Find the  x  - and  y -intercepts for the equation. Then graph the equation. - 16 y-4 x=-8

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Write an equation in standard form for a line passing through the pair of points. - (3,0)(-3,0) and (7,7)(-7,7)

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Solve the inequality. -Behemoth Back Packs, Inc., finds that the cost to make xx back packs is C=75x+7059C=75 x+7059 , while the revenue produced from them is R=108x\mathrm{R}=108 \mathrm{x} ( C\mathrm{C} and R\mathrm{R} are in dollars). What is the smallest whole number of back packs, xx , that must be sold for the company to show a profit?

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Choose one of the four lines graphed which most closely resembles the graph of the given equation. - y=4x5y=-4 x-5

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Find the x-intercepts and y-intercepts of the graph of the equation. - 2x+y=62 x+y=6

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Determine whether the given ordered pair is a solution of the given equation. - x2+y24x+8y=12;(4,2)x^{2}+y^{2}-4 x+8 y=-12 ;(4,-2)

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Graph the linear equation. - x=8y8-\mathrm{x}=8 \mathrm{y}-8  Graph the linear equation. - -\mathrm{x}=8 \mathrm{y}-8

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Decide whether the pair of lines is parallel, perpendicular, or neither. -The line through (20,5)(-20,5) and (4,7)(-4,7) and the line through (5,5)(-5,5) and (7,4)(7,4)

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Solve the problem. -In order for a chemical reaction to take place, the Fahrenheit temperature of the reagents must be at least 131.16F131.16^{\circ} \mathrm{F} . Find the Celsius temperatures at which the reaction may occur. (F=95C+32)\left(\mathrm{F}=\frac{9}{5} \mathrm{C}+32\right)

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Choose one of the four lines graphed which most closely resembles the graph of the given equation. - y=3x6y=3 x-6

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Choose one of the four lines graphed which most closely resembles the graph of the given equation. - y=2x+5y=-2 x+5

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sketch the graph of the equation. - y=12x2y=\frac{1}{2} x^{2}  sketch the graph of the equation. - y=\frac{1}{2} x^{2}

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Find the xx - and yy -intercepts for the equation. Then graph the equation. - 5x10y=10-5 x-10 y=10  Find the  x  - and  y -intercepts for the equation. Then graph the equation. - -5 x-10 y=10

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Solve the problem. -A biologist recorded 17 snakes on 17 acres in one area and 20 snakes on 43 acres in another area. Let yy be the number of snakes in xx acres. Write an equation for the number of snakes.

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Solve the problem. -Ten students in a graduate program were randomly selected. Their grade point averages (GPAs) when they entered the program were between 3.5 and 4.0. The following data were obtained regarding their GPAs on entering the program versus their current GPAs. By using linear regression, the following equation is obtained: y=3.67+0.0313xy=3.67+0.0313 x where xx is entering GPA and yy is current GPA. Use this equation to predict current GPA of a student whose entering GPA is 3.6.  Solve the problem. -Ten students in a graduate program were randomly selected. Their grade point averages (GPAs) when they entered the program were between 3.5 and 4.0. The following data were obtained regarding their GPAs on entering the program versus their current GPAs. By using linear regression, the following equation is obtained:  y=3.67+0.0313 x  where  x  is entering GPA and  y  is current GPA. Use this equation to predict current GPA of a student whose entering GPA is 3.6.

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