Exam 13: Extensions of and Deviations From Mendelian Genetic Principles
Exam 1: Genetics: An Introduction42 Questions
Exam 2: DNA: The Genetic Material46 Questions
Exam 3: DNA Replication46 Questions
Exam 4: Gene Function46 Questions
Exam 5: Gene Expression: Transcription46 Questions
Exam 6: Gene Expression: Translation46 Questions
Exam 7: Dna Mutation, DNA Repair, and Transposable Elements46 Questions
Exam 8: Genomics: The Mapping and Sequencing of Genomes50 Questions
Exam 9: Functional and Comparative Genomics46 Questions
Exam 10: Recombinant DNA Technology42 Questions
Exam 11: Mendelian Genetics40 Questions
Exam 12: Chromosomal Basis of Inheritance46 Questions
Exam 13: Extensions of and Deviations From Mendelian Genetic Principles42 Questions
Exam 14: Genetic Mapping in Eukaryotes46 Questions
Exam 15: Genetics of Bacteria and Bacteriophages46 Questions
Exam 16: Variations in Chromosome Structure and Number42 Questions
Exam 17: Regulation of Gene Expression in Bacteria and Bacteriophages46 Questions
Exam 18: Regulation of Gene Expression in Eukaryotes46 Questions
Exam 19: Genetic Analysis of Development46 Questions
Exam 20: Genetics of Cancer46 Questions
Exam 21: Population Genetics42 Questions
Exam 22: Quantitative Genetics45 Questions
Exam 23: Molecular Evolution44 Questions
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In the human ABO blood system,the allele i is dominant to IA and IB.
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(True/False)
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False
Comb shape in chickens is controlled by
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Correct Answer:
D
Solid black,black with tan belly,and agouti coat color in mice are all caused by alleles of the agouti gene.All three colors can be true-breeding.When using mice from true-breeding strains: (1)Black × Agouti F1s are all agouti,(2)Black × Black with Tan belly F1s are all black and tan,and (3)Black with Tan belly × Agouti F1s are all agouti.If you were to cross the F1s from (1)with the F1s from (2),what proportion of the resulting offspring would you expect to be black with a tan belly?
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(Multiple Choice)
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Correct Answer:
B
Mutants that make up a complementation group complement each other.
(True/False)
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In chickens,there is a mutant gene called "frizzle" that results in weak,stringy,and easily broken feathers.When a frightfully frizzled fowl is bred to a normal chicken,the offspring are all mildly frizzled.If one breeds two mildly frizzled chickens to each other,the offspring have the phenotypic ratio of 1 normal: 2 mildly frizzled: 1 frightfully frizzled.What is the mode of inheritance of "frizzle"?
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Individuals with neurofibromatosis may have a range of phenotypes,from pigment spots on the skin to tumorlike growths.This is an example of
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Two true-breeding mutant strains of Drosophila have black body color instead of the wild-type gray yellow.When the two strains are crossed,all the F1 flies have wild-type body color.How can these data be interpreted?
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Why is it that human males and females who are both heterozygous for the pattern-baldness gene have different phenotypes (males are bald,females are not bald)?
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Dextral (D) and sinistral (d) shell coiling in the water snail Limnaea peregra is genetically determined. From a population of mixed sinistral and dextral snails, a sinistral female and a dextral male are chosen. All the offspring are dextral. When the female offspring are mated, 50% produce only sinistral snails and the other 50% produce only dextral snails.
-This form of inheritance is called
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The 9:6:1 F2 ratio found in fruit shape in summer squash is a deviation from an expected Mendelian ratio.What does this represent?
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Feather color in chickens is the result of an incompletely dominant gene. The gene responsible for black feathers (B) when homozygous results in a muted color called "Andalusian blue" if combined with an allele for white feathers (b). When the white allele occurs in homozygous conditions, a white phenotype results. A gene affecting comb shape (R), which results in a comb called a "rose" comb, is completely dominant over (r), which in homozygous conditions results in a comb called "single." A mating between a black single rooster and white rose hen results in a number of chicks, all of which have identical phenotypes.
-What is the phenotype and genotype of the chicks?
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Please select the best match for each term.
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Premises:
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In the multiple allelic system for eye color in Drosophila,the phenotypic expression of the alleles depends on
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Which of the following will result in modifications to the expected Mendelian ratios?
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For a gene with complete dominance,the recessive allele has no effect on the phenotype of a heterozygote.
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Familial hypercholesterolemia is a genetic disease that affects approximately one in 500 people worldwide.There is more than one genetic cause of the disease.Class I is often described as an autosomal dominant disease.Affected individuals have cholesterol levels >250 as children and often >300 as adults.However,homozygotes have cholesterol levels of >600 as children and can die of heart attacks in their 20s.These individuals entirely lack a functional LDL receptor.Which of the following would be the best description of the inheritance of this form of hypercholesterolemia?
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What is the number of possible genotypes in a multiple allele series with 6 alleles? How many of these are homozygous and how many are heterozygous?
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Please select the best match for each term.
Correct Answer:
Premises:
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Feather color in chickens is the result of an incompletely dominant gene. The gene responsible for black feathers (B) when homozygous results in a muted color called "Andalusian blue" if combined with an allele for white feathers (b). When the white allele occurs in homozygous conditions, a white phenotype results. A gene affecting comb shape (R), which results in a comb called a "rose" comb, is completely dominant over (r), which in homozygous conditions results in a comb called "single." A mating between a black single rooster and white rose hen results in a number of chicks, all of which have identical phenotypes.
-Use a Punnett square to demonstrate a cross between two of the F1 offspring.What are the phenotypes and ratios that occur?
(Essay)
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