Exam 14: Genetic Mapping in Eukaryotes

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A red,round,true-breeding tomato is bred with a yellow,oval,true-breeding tomato,and the F1s are testcrossed to a homozygous-recessive tester.This results in the offspring below.Calculate the chi-squared value to test the likelihood of linkage. yellow oval 11 red round 14 yellow round 7 red oval 8

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A testcross of trihybrid Drosophila produced the following phenotypes and number of offspring. A table showing phenotype and the number of offspring with each phenotype is below. A plus sign is used for wild-type phenotype; a letter indicates the mutant phenotype for that gene. +++ 669 abc 653 ++c 121 ab+ 139 +b+ 2280 a+c 2215 +bc 3 a++ 2 -Which gene pair is closer together; i.e.there are fewer map units between them?

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If an AABB strain is mated with an aabb strain,an AB gamete produced by the resulting F1 is

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A linkage map illustrates the exact physical locations of genes on a chromosome.

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What does the chi-square test tell us about the linkage of two genes?

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What is the difference in the likelihood of linkage between two genes with a lod score of 2 and two genes with a lod score of 3?

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The closer together two genes are on a chromosome,

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Why does the recombination frequency often lead to an underestimation of the true map distance between linked genes?

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If genes are linked and an F1 is testcrossed,

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X, Y, and Z are linked genes. Based on testcross data, the frequency of recombination between genes X and Y was determined to be 33.1 map units. Between genes X and Z, the distance was 11.8 mu; between genes Y and Z, the distance was 21.3 mu. -What is the order of these three genes on the chromosome?

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A testcross of trihybrid Drosophila produced the following phenotypes and number of offspring. A table showing phenotype and the number of offspring with each phenotype is below. A plus sign is used for wild-type phenotype; a letter indicates the mutant phenotype for that gene. +++ 669 abc 653 ++c 121 ab+ 139 +b+ 2280 a+c 2215 +bc 3 a++ 2 -The cross represented by a+b+c+/abc × abc/abc is

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T.H.Morgan and his colleagues found that among the offspring of genetic crosses,parental phenotypic classes were the most frequent,while recombinant classes occurred less frequently.This observation led Morgan to conclude that

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Testcrosses may be used to determine if two genes are linked.

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A chi-square analysis of linkage between genes k and f produces a P value of 0.99.What is the likelihood that these two genes are linked?

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Explain how Curt Stern showed,using evidence from Drosophila,that genetic recombination is associated with the physical exchange of parts between homologous chromosomes.

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A coefficient of coincidence of zero is the same as an interference value of zero.

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If in calculating the distance between two genes using data from a testcrossed dihybrid you arrive at a genetic distance of 70 map units,there is likely to be something wrong with your calculations,the experimental data,or with the experiment itself.

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Genes may show 50% recombination either when the genes are on different chromosomes or when the genes are far apart on the same chromosome.

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Please select the best match for each term.
Gene linkage
Wild-type red eyes and normal bristles.
Testcross
F1 to mahogany eyes and stubble bristles
Parental type
Recombinants divided by the total × 100
Correct Answer:
Verified
Premises:
Responses:
Gene linkage
Wild-type red eyes and normal bristles.
Testcross
F1 to mahogany eyes and stubble bristles
Parental type
Recombinants divided by the total × 100
Recombinant type
Mahogany eyes and normal bristles
Map unit
Genes that do not segregate independently
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X, Y, and Z are linked genes. Based on testcross data, the frequency of recombination between genes X and Y was determined to be 33.1 map units. Between genes X and Z, the distance was 11.8 mu; between genes Y and Z, the distance was 21.3 mu. -Of the three pairs of genes,which ones are closest to each other and which ones are farthest apart?

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