Exam 8: Confidence Intervals

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In determining the sample size to estimate a population proportion,as p approaches .5,the calculated value of the sample size ______________.

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A botanist measures the heights of 16 seedlings and obtains a mean and standard deviation of 72.5 cm and 4.5 cm,respectively.Find the 95% confidence interval for the mean height of seedlings in the population form which the sample was selected.

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When the population is normally distributed,population standard deviation σ\sigma is unknown,and the sample size is n = 15;the confidence interval for the population mean µ is based on:

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What is a 95 percent confidence interval for µ when n = 10, What is a 95 percent confidence interval for µ when n = 10,   35.6,and s = 13.0? Assume population normality. 35.6,and s = 13.0? Assume population normality.

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When the level of confidence and sample proportion When the level of confidence and sample proportion   remain the same,a confidence interval for a population proportion p based on a sample of n = 100 will be ______________ a confidence interval for p based on a sample of n = 400. remain the same,a confidence interval for a population proportion p based on a sample of n = 100 will be ______________ a confidence interval for p based on a sample of n = 400.

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When the population is normally distributed and the population standard deviation σ\sigma is unknown,then for any sample size n,the sampling distribution of  When the population is normally distributed and the population standard deviation   \sigma  is unknown,then for any sample size n,the sampling distribution of   is based on the z distribution. is based on the z distribution.

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The state highway department is studying traffic patterns on one of the busiest highways in the state.As part of the study,the department needs to estimate the average number of vehicles that pass an intersection each day.A random sample of 64 days gives us a sample mean of 14,205 cars and a sample standard deviation of 1,010 cars.What is the 92% confidence interval estimate of μ\mu ,the mean number of cars passing the intersection?

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As the sample size n increases,the width of the confidence interval _______________.

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A manufacturer of dodge balls uses a machine to inflate its new balls to a pressure of 13.5 pounds ( A manufacturer of dodge balls uses a machine to inflate its new balls to a pressure of 13.5 pounds (   = 0.1).When the machine is properly calibrated,the mean inflation pressure s 13.5 pounds,but uncontrollable factors can cause the pressure of individual dodge balls to vary.For quality control purposes,the manufacturer wishes to estimate the mean inflation pressure to within 0.025 pounds of its true value with a 99% confidence.What sample size should be used? = 0.1).When the machine is properly calibrated,the mean inflation pressure s 13.5 pounds,but uncontrollable factors can cause the pressure of individual dodge balls to vary.For quality control purposes,the manufacturer wishes to estimate the mean inflation pressure to within 0.025 pounds of its true value with a 99% confidence.What sample size should be used?

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A confidence interval for the population mean is an interval constructed around the _____.

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In a study of 265 subjects,the average score on the examination was 63.8 and s = 3.08.What is a 95 percent confidence for µ?

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Health insurers and the federal government are both putting pressure on hospitals to shorten the average length of stay (LOS)of their patients.In 1996,the average LOS for non-heart patient was 4.6 days.A random sample of 20 hospitals in one state had a mean LOS for non-heart patients in 2000 of 3.8 days and a standard deviation of 1.2 days.How large a sample of hospitals would we need to be 99% confident that the sample mean is within 0.5 days of the population mean?

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A sample of 100 items has a population standard deviation of 5.1 and a mean of 21.6.Construct a 95 percent confidence interval for A sample of 100 items has a population standard deviation of 5.1 and a mean of 21.6.Construct a 95 percent confidence interval for   . .

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A random sample of size 15 is taken from a population assumed to be normal,and A random sample of size 15 is taken from a population assumed to be normal,and   = 1.2 and s = 0.6.Calculate a 90 percent confidence interval for   . = 1.2 and s = 0.6.Calculate a 90 percent confidence interval for A random sample of size 15 is taken from a population assumed to be normal,and   = 1.2 and s = 0.6.Calculate a 90 percent confidence interval for   . .

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A company is interested in estimating  A company is interested in estimating   ,the mean number of days of sick leave taken by its employees.The firm's statistician randomly selects 100 personnel files and notes the number of sick days taken by each employee.The sample mean is 12.2 days and the sample standard deviation is 10 days.How many personnel files would the director have to select in order to estimate  \mu  to within 2 days with a 99% confidence interval? ,the mean number of days of sick leave taken by its employees.The firm's statistician randomly selects 100 personnel files and notes the number of sick days taken by each employee.The sample mean is 12.2 days and the sample standard deviation is 10 days.How many personnel files would the director have to select in order to estimate μ\mu to within 2 days with a 99% confidence interval?

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As the stated confidence level decreases,the width of the confidence interval _______________.

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When the margin of error is added to and subtracted from the sample mean an interval is formed that will contain μ\mu with probability of (1 - α\alpha ).

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When the sample size and sample standard deviation remain the same,a 99% confidence interval for a population mean,µ will be narrower than the 95% confidence interval for µ.

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In a random sample of 651 computer scientists who subscribed to a web-based daily news update,it was found that the average salary was $46,816 with a standard deviation of $12,557.Calculate a 91% confidence interval for the mean salary of computer scientists.

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If the 95% confidence interval for a mean is from .771 to 1.629,can we conclude that If the 95% confidence interval for a mean is from .771 to 1.629,can we conclude that   = .5,using a 95 percent confidence interval? = .5,using a 95 percent confidence interval?

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