Exam 15: Chi-Squared Tests

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To address whether two variables are related in a contingency table,the null hypothesis,H0,says that

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Suppose that a random sample of 60 observations was drawn from a population.After calculating the mean and standard deviation,each observation was standardized and the number of observations in each of the intervals below was counted.Can we infer at the 10% significance level that the data were drawn from a normal population? Intervals Frequency Z\leq-1 -11 5

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A chi-squared test statistic in a test of a contingency table that is equal to zero means:

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A chi-squared test of a contingency table with 6 degrees of freedom results in a test statistic χ\chi 2 = 13.58.Using the χ\chi 2 tables,the most accurate statement that can be made about the p-value for this test is that:

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The rule of ____________________ states that in order to conduct the chi-squared goodness-of-fit test,the expected value for each cell must be ____________________ or more.

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A sports preference poll showed the following data for adults and children: Favorite Sport Cander Baseball Saccer Rugby Hackey Archery Adults 24 17 30 18 22 Children 21 20 22 12 28 Use the 5% level of significance and test to determine whether sports preferences depend on age group.

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If we want to conduct a two-tail test of a population proportion,we can employ:

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The human resources manager of a consumer product company asked a random sample of employees how they felt about the work they were doing.The following table gives a breakdown of their responses by whether the employee is part time or full time (aka work status).Do the data provide sufficient evidence to conclude that the level of job satisfaction is related to their work status? Use α\alpha = .10. Response Gander Very Interesting Fairly Interesting Nat Interesting Full tine 70 41 9 Part tine 35 34 11

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The alternative hypothesis in a chi-squared test of a contingency table is that the two nominal variables are ____________________.

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Consider a multinomial experiment with 200 trials,where the outcome of each trial is classified into one of 5 categories.The number of degrees of freedom associated with the chi-squared goodness-of-fit test equals:

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Which of the following statements regarding the chi-squared distribution is true?

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For a chi-squared distributed random variable with 10 degrees of freedom and a level of significance of .025,the chi-squared table value is 20.4831.Suppose the value of your test statistic is 16.857.This will lead you to reject the null hypothesis.

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A large value of a chi-squared test statistic in a test of a contingency table leads you to conclude the two variables are ____________________.

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Which of the following statements is true for chi-squared tests?

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The number of degrees of freedom associated with the chi-squared test statistic for normality is the number of ____________________ minus 1 minus the number of ____________________ estimated.

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In a goodness-of-fit test,all of the proportions specified in the null hypothesis must be equal to each other.

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A test for whether one proportion is higher than the other can be performed using the chi-squared distribution.

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Seat Belts A study was conducted to determine whether the use of seat belts in vehicles depends on whether or not a child was present in the car.A sample of 1,000 people treated for injuries sustained from vehicle accidents was obtained,and each person was classified according to (1)child present (yes/no)and (2)seat belt usage (worn or not worn)during the accident.The data are shown in the table below. \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad Child present in car Seat Belts NO YES Worm 83 200 Not Worn 337 380 -{Seat Belts Narrative} Which test would be used to properly analyze the data in this experiment?

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For a chi-squared distributed random variable with 12 degrees of freedom and a level of significance of .05,the test statistics is 25.168.The chi-squared value from the table is 21.0261.These results will lead us to reject the null hypothesis.

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The number of degrees of freedom for a contingency table with r rows and c columns is:

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