Question 1

Draw a molecular orbital diagram and use it to determine which of the following is paramagnetic.

Accepted Answer

A)  B22⁺ 
B)  B22⁻ 
C)  N22⁺ 
D)  C22⁻ 
E)  B2 
A)  B22⁺ 
B)  B22⁻ 
C)  N22⁺ 
D)  C22⁻ 
E)  B2 E

Question 2

A molecule containing a central atom with sp2 hybridization has a ________ electron geometry.

Accepted Answer

A)  linear 
B)  trigonal bipyramidal 
C)  trigonal planar 
D)  tetrahedral 
E)  bent 
A)  linear 
B)  trigonal bipyramidal 
C)  trigonal planar 
D)  tetrahedral 
E)  bent C

Question 3

Match the following.
-sp3d

Accepted Answer

A) sp hybridized central atom 
B) octahedral electron geometry 
C) polar, but contains no polar bonds 
D) sp2 hybridized central atom 
E) linear
F)nonpolar, but contains a polar covalent bond
G)tetrahedral
H)trigonal planar
I)octahedral
J)polar
K)trigonal bipyramidal
L)seesaw molecular geometry 
A) sp hybridized central atom 
B) octahedral electron geometry 
C) polar, but contains no polar bonds 
D) sp2 hybridized central atom 
E) linear
F)nonpolar, but contains a polar covalent bond
G)tetrahedral
H)trigonal planar
I)octahedral
J)polar
K)trigonal bipyramidal
L)seesaw molecular geometry K

Question 4

Draw the Lewis structure for C2H2. What is the hybridization on the C atoms?

Accepted Answer

A)  sp 
B)  sp3d2 
C)  sp3d 
D)  sp3 
E)  sp2 
A)  sp 
B)  sp3d2 
C)  sp3d 
D)  sp3 
E)  sp2

Question 5

Determine the electron geometry (eg) and molecular geometry (mg) of ICl2⁻.

Accepted Answer

A)  eg = tetrahedral, mg = bent 
B)  eg = tetrahedral, mg = trigonal pyramidal 
C)  eg = trigonal bipyramidal, mg = linear 
D)  eg = trigonal bipyramidal, mg = trigonal planar 
E)  eg = octahedral, mg = linear 
A)  eg = tetrahedral, mg = bent 
B)  eg = tetrahedral, mg = trigonal pyramidal 
C)  eg = trigonal bipyramidal, mg = linear 
D)  eg = trigonal bipyramidal, mg = trigonal planar 
E)  eg = octahedral, mg = linear

Question 6

Place the following in order of increasing F-A-F bond angle, where A represents the central atom in each molecule. 
PF3 OF2 PF4⁺

Accepted Answer

A)  PF3 2 4⁺ 
B)  OF2 3 4⁺ 
C)  OF2 4⁺ 3 
D)  PF4⁺ 2 3 
E)  PF4⁺ 3 2 
A)  PF3 2 4⁺ 
B)  OF2 3 4⁺ 
C)  OF2 4⁺ 3 
D)  PF4⁺ 2 3 
E)  PF4⁺ 3 2

Question 7

Describe a sigma bond.

Accepted Answer

A)  p orbital overlapping with a d orbital 
B)  an attraction due to overlap of two orbitals along the internuclear axis 
C)  side by side overlap of d orbitals 
D)  overlap of two d orbitals 
E)  s orbital overlapping with the side of a p orbital 
A)  p orbital overlapping with a d orbital 
B)  an attraction due to overlap of two orbitals along the internuclear axis 
C)  side by side overlap of d orbitals 
D)  overlap of two d orbitals 
E)  s orbital overlapping with the side of a p orbital

Question 8

The VSEPR model predicts the H-O-H bond angle in H3O+ to be ________.

Accepted Answer

A)  60° 
B)  90° 
C)  less than 109.5° but greater than 90° 
D)  109.5° 
A)  60° 
B)  90° 
C)  less than 109.5° but greater than 90° 
D)  109.5°

Question 9

The hybrid orbital set used by the central atom in NF3 is ________.

Accepted Answer

A)  sp 
B)    
C)    
D)    d 
E)      
A)  sp 
B)    
C)    
D)    d 
E)

Question 10

A molecule containing a central atom with sp3 hybridization has a(n) ________ electron geometry.

Accepted Answer

A)  linear 
B)  trigonal bipyramidal 
C)  octahedral 
D)  tetrahedral 
E)  bent 
A)  linear 
B)  trigonal bipyramidal 
C)  octahedral 
D)  tetrahedral 
E)  bent

Question 11

The hybrid orbital set used by the central atom in NO3- is ________.

Accepted Answer

A)  sp 
B)    
C)    
D)    d 
E)      
A)  sp 
B)    
C)    
D)    d 
E)

Question 12

Give the approximate bond angle for a molecule with tetrahedral electron geometry and bent molecular geometry.

Accepted Answer

A)  180° 
B)  <180° 
C)  <109.5° 
D)  109.5° 
E)  <120° 
A)  180° 
B)  <180° 
C)  <109.5° 
D)  109.5° 
E)  <120°

Question 13

Give the approximate bond angle for a molecule with octahedral electron geometry and square planar molecular geometry.

Accepted Answer

A) 90° B) 180° C) >120° D) <90° E) <120° A) 90° B) 180° C) >120° D) <90° E) <120°

Question 14

Using the VSEPR model, the electron-domain geometry of the central atom in H2O is ________.

Accepted Answer

A)  linear 
B)  trigonal planar 
C)  tetrahedral 
D)  trigonal bipyramidal 
E)  octahedral 
A)  linear 
B)  trigonal planar 
C)  tetrahedral 
D)  trigonal bipyramidal 
E)  octahedral

Question 15

Draw the Lewis structure for the molecule CH2CHCH3. How many sigma and pi bonds does it contain?

Accepted Answer

A)  8 sigma, 1 pi 
B)  9 sigma, 0 pi 
C)  9 sigma, 1 pi 
D)  7 sigma, 2 pi 
E)  8 sigma, 2 pi 
A)  8 sigma, 1 pi 
B)  9 sigma, 0 pi 
C)  9 sigma, 1 pi 
D)  7 sigma, 2 pi 
E)  8 sigma, 2 pi

Question 16

How many of the following molecules have sp hybridization on the central atom? C2Cl2 CO2 O3 H2O

Accepted Answer

A)  0 
B)  1 
C)  2 
D)  3 
E)  4 
A)  0 
B)  1 
C)  2 
D)  3 
E)  4

Question 17

In molecular orbital theory the acronym HOMO stands for ________.

Accepted Answer

A)  homogenous orbital-molecular orientation 
B)  highly ordered molecular orbital 
C)  highest occupied molecular orbital 
D)  highest orbital-molecular orientation 
E)  It has no meaning. 
A)  homogenous orbital-molecular orientation 
B)  highly ordered molecular orbital 
C)  highest occupied molecular orbital 
D)  highest orbital-molecular orientation 
E)  It has no meaning.

Question 18

Place the following in order of decreasing X-A-X bond angle, where A represents the central atom and X represents the outer atoms in each molecule. CS2 CF4 SCl2

Accepted Answer

A)  CS2 > SCl2 > CF4 
B)  SCl2 > CF4 > CS2 
C)  CF4 > SCl2 > CS2 
D)  CS2 > CF4 > SCl2 
E)  CF4 > CS2 > SCl2 
A)  CS2 > SCl2 > CF4 
B)  SCl2 > CF4 > CS2 
C)  CF4 > SCl2 > CS2 
D)  CS2 > CF4 > SCl2 
E)  CF4 > CS2 > SCl2

Question 19

Using the VSEPR model, the molecular geometry of the central atom in XeCl4 is ________.

Accepted Answer

A)  tetrahedral 
B)  seasaw 
C)  trigonal bipyramidal 
D)  square pyramidal 
E)  square planar 
A)  tetrahedral 
B)  seasaw 
C)  trigonal bipyramidal 
D)  square pyramidal 
E)  square planar

Question 20

A molecule or ion with five electrons in bonding orbitals and two electrons in an antibonding orbital has a bond order of ________.

Accepted Answer

A)  0.5 
B)  1 
C)  1.5 
D)  2 
E)  3 
A)  0.5 
B)  1 
C)  1.5 
D)  2 
E)  3

Exam 10: Chemical Bonding Ii: Molecular Shapes, Valence Bond Theory, and Molecular Orbital Theory

Draw a molecular orbital diagram and use it to determine which of the following is paramagnetic.

A molecule containing a central atom with sp2 hybridization has a ________ electron geometry.

Match the following. -sp3d

Draw the Lewis structure for C2H2. What is the hybridization on the C atoms?

Determine the electron geometry (eg) and molecular geometry (mg) of ICl2⁻.

Place the following in order of increasing F-A-F bond angle, where A represents the central atom in each molecule. PF3 OF2 PF4⁺

Describe a sigma bond.

The VSEPR model predicts the H-O-H bond angle in H3O+ to be ________.

The hybrid orbital set used by the central atom in NF3 is ________.

A molecule containing a central atom with sp3 hybridization has a(n) ________ electron geometry.

The hybrid orbital set used by the central atom in NO3- is ________.

Give the approximate bond angle for a molecule with tetrahedral electron geometry and bent molecular geometry.

Give the approximate bond angle for a molecule with octahedral electron geometry and square planar molecular geometry.

Using the VSEPR model, the electron-domain geometry of the central atom in H2O is ________.

Draw the Lewis structure for the molecule CH2CHCH3. How many sigma and pi bonds does it contain?

How many of the following molecules have sp hybridization on the central atom? C2Cl2 CO2 O3 H2O

In molecular orbital theory the acronym HOMO stands for ________.

Place the following in order of decreasing X-A-X bond angle, where A represents the central atom and X represents the outer atoms in each molecule. CS2 CF4 SCl2

Using the VSEPR model, the molecular geometry of the central atom in XeCl4 is ________.

A molecule or ion with five electrons in bonding orbitals and two electrons in an antibonding orbital has a bond order of ________.

Units of Measurement for Physical and Chemical Change

Atoms and Elements

Molecules, Compounds, and Nomenclature

Chemical Reactions and Stoichiometry

Gases

Thermochemistry

The Quantum-Mechanical Model of the Atom

Periodic Properties of the Elements

Chemical Bonding I: Lewis Theory

Liquids, Solids, and Intermolecular Forces

Solutions

Chemical Kinetics

Chemical Equilibrium

Acids and Bases

Aqueous Ionic Equilibrium

Gibbs Energy and Thermodynamics

Electrochemistry

Radioactivity and Nuclear Chemistry

Organic Chemistry I: Structures

Organic Chemistry Ii: Reactions

Biochemistry

Chemistry of the Nonmetals

Metals and Metallurgy

Transition Metals and Coordination Compounds

Filters

A molecule containing a central atom with sp² hybridization has a ________ electron geometry.

Match the following. -sp³^d

Draw the Lewis structure for C₂H₂. What is the hybridization on the C atoms?

Determine the electron geometry (eg) and molecular geometry (mg) of ICl₂⁻.

Place the following in order of increasing F-A-F bond angle, where A represents the central atom in each molecule. PF₃ OF₂ PF₄⁺

The VSEPR model predicts the H-O-H bond angle in H₃O⁺ to be ________.

The hybrid orbital set used by the central atom in NF₃ is ________.

A molecule containing a central atom with sp³ hybridization has a(n) ________ electron geometry.

The hybrid orbital set used by the central atom in NO₃^- is ________.

Using the VSEPR model, the electron-domain geometry of the central atom in H₂Ois ________.

Draw the Lewis structure for the molecule CH₂CHCH₃. How many sigma and pi bonds does it contain?

How many of the following molecules have sp hybridization on the central atom? C₂Cl₂ CO₂ O₃ H₂O

Place the following in order of decreasing X-A-X bond angle, where A represents the central atom and X represents the outer atoms in each molecule. CS₂ CF₄ SCl₂

Using the VSEPR model, the molecular geometry of the central atom in XeCl₄ is ________.