Exam 11: Analytic Geometry In Three Dimensions

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Find the volume of the parallelepiped with the given vertices A(0,0,0),B(0,0,2),C(0,2,0),D(2,0,0),E(2,2,0),F(2,0,2),G(0,2,2),H(2,2,2)A ( 0,0,0 ) , B ( 0,0,2 ) , C ( 0,2,0 ) , D ( 2,0,0 ) , E ( 2,2,0 ) , F ( 2,0,2 ) , G ( 0,2,2 ) , H ( 2,2,2 )

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Use vectors to determine whether the points are collinear. (-9,5,7), (-12,7,5), (3,-3,15)

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Find the center and radius of the sphere. x2+y2+z2+18x+16y10z+89=0x ^ { 2 } + y ^ { 2 } + z ^ { 2 } + 18 x + 16 y - 10 z + 89 = 0

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Find the center and radius of the sphere. x2+y2+z25x=0x ^ { 2 } + y ^ { 2 } + z ^ { 2 } - 5 x = 0

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Determine whether the planes are parallel,orthogonal,or neither. 5x - 2y - 5z = -2 X - 3y + 6z = -6

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Find the angle between the two planes. x+y-z=3 4x-5y-4z=5

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Find a unit vector orthogonal to u and v. u=(9)i+(3)j+(6)k,v=(2)i+(8)j+(5)k\mathbf { u } = ( 9 ) \mathbf { i } + ( - 3 ) \mathbf { j } + ( - 6 ) \mathbf { k } , \quad \mathbf { v } = ( - 2 ) \mathbf { i } + ( 8 ) \mathbf { j } + ( - 5 ) \mathbf { k }

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Use the vectors u and v to find u × (2v). u=6ij+7kv=5i+5jk\mathbf { u } = 6 \mathbf { i } - \mathbf { j } + 7 \mathbf { k } \quad \mathbf { v } = 5 \mathbf { i } + 5 \mathbf { j } - \mathbf { k }

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Find u × v and show that it is orthogonal to both u and v. = =-49

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Find the vector z,given u=(1,3,4),v=(1,4,4),w=(20,0,20)\mathbf { u } = ( - 1,3,4 ) , \mathbf { v } = ( 1 , - 4 , - 4 ) , \mathbf { w } = ( 20,0,20 ) . z=7u+v120w\mathbf { z } = 7 \mathbf { u } + \mathbf { v } - \frac { 1 } { 20 } \mathbf { w }

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Find the angle between the vectors u and v.Express your answer in degrees and round to the nearest tenth of a degree. u = (4,6,9)( 4 , - 6,9 ) ,v = (9,2,2)( 9 , - 2,2 )

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Use the triple scalar product to find the volume of the parallelepiped having adjacent edges u,v,and w. =9+9 =9+9 =9+9  Use the triple scalar product to find the volume of the parallelepiped having adjacent edges u,v,and w.   \begin{array} { l }  \mathbf { u } = 9 \mathbf { i } + 9 \mathbf { j } \\ \mathbf { v } = 9 \mathbf { j } + 9 \mathbf { k } \\ \mathbf { w } = 9 \mathbf { i } + 9 \mathbf { k } \end{array}       \mathrm { a } = ( 9,9,0 ) , \mathrm { b } = ( 0,9,9 ) , \mathrm { c } = ( 9,0,9 )   a=(9,9,0),b=(0,9,9),c=(9,0,9)\mathrm { a } = ( 9,9,0 ) , \mathrm { b } = ( 0,9,9 ) , \mathrm { c } = ( 9,0,9 )

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Use the vectors u and v to find u × v. u=5ij+6k\mathbf { u } = 5 \mathbf { i } - \mathbf { j } + 6 \mathbf { k } v=4i+4jk\mathbf { v } = 4 \mathbf { i } + 4 \mathbf { j } - \mathbf { k }

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Find the general form of the equation of the plane passing through the point and perpendicular to the specified vector or line. Point: (2,0,7)( 2,0 , - 7 ) Perpendicular to: n=7k\mathbf { n } = - 7 \mathbf { k }

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Find the magnitude of the vector v described below. Initial point: (-4,-3,3) Terminal point: (8,2,-6)

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Find the magnitude of the vector v described below. Initial point: (3,-7,0) Terminal point: (-1,1,0)

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Find the midpoint of the line segment joining the points. (5,4,2),(5,3,2)( - 5,4 , - 2 ) , ( 5,3 , - 2 )

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Determine the octant(s)in which (x,y,z)is located so that the condition(s)is (are)satisfied. y<4y < - 4

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Determine whether the planes are parallel,orthogonal,or neither. 6x + y - z = 2 -18x - 3y + 3z = -4

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Find u × v and show that it is orthogonal to both u and v. u=(13,1,14)v=(12,12,1)\mathbf { u } = ( 13,1,14 ) \quad \mathbf { v } = ( 12 , - 12 , - 1 )

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