Question 1

Part of an ANOVA table is shown below.   ​ The number of degrees of freedom corresponding to between-treatments is

Accepted Answer

A)  18. 
B)  2. 
C)  4. 
D)  3. 
A)  18. 
B)  2. 
C)  4. 
D)  3.

Question 2

When an analysis of variance is performed on samples drawn from k populations, the mean square due to treatments (MSTR) is

Accepted Answer

A)  SSTR/nT. 
B)  SSTR/(nT - 1). 
C)  SSTR/k. 
D)  SSTR/(k - 1). 
A)  SSTR/nT. 
B)  SSTR/(nT - 1). 
C)  SSTR/k. 
D)  SSTR/(k - 1).

Question 3

In the ANOVA, treatments refer to

Accepted Answer

A)  experimental units. 
B)  different levels of a factor. 
C)  the dependent variables. 
D)  statistical applications. 
A)  experimental units. 
B)  different levels of a factor. 
C)  the dependent variables. 
D)  statistical applications.

Question 4

In a completely randomized experimental design involving five treatments, 13 observations were recorded for each of the five treatments (a total of 65 observations). Also, the design provided the following information. ​
SSTR = 300 (Sum of Squares Due to Treatments)
SST = 800 (Total Sum of Squares)
​
The number of degrees of freedom corresponding to between-treatments is

Accepted Answer

A)  60. 
B)  59. 
C)  5. 
D)  4. 
A)  60. 
B)  59. 
C)  5. 
D)  4.

Question 5

Three universities in your state decided to administer the same comprehensive examination to the recipients of MBA degrees from the three institutions. From each institution, MBA recipients were randomly selected and were given the test. The following table shows the scores of the students tested by each university.   ​
At α = .01, test to see if there is any significant difference in the average scores of all the students who took the exam from the three universities. (Note that the sample sizes are not equal.) Use both the critical and p-value approaches.

Accepted Answer

@#IMG-DLM& ​
F = 5.40 < 6.93;

Question 6

Consider the following ANOVA table. ​   ​
The test statistic to test the null hypothesis equals

Accepted Answer

A)  .432. 
B)  1.8. 
C)  4.17. 
D)  28.8. 
A)  .432. 
B)  1.8. 
C)  4.17. 
D)  28.8.

Question 7

The required condition for using an ANOVA procedure on data from several populations is that the

Accepted Answer

A)  selected samples are dependent on each other. 
B)  response variables from samples are all uniform. 
C)  sampled populations have equal variances. 
D)  sampled populations have equal means. 
A)  selected samples are dependent on each other. 
B)  response variables from samples are all uniform. 
C)  sampled populations have equal variances. 
D)  sampled populations have equal means.

Question 8

An ANOVA procedure is used for data obtained from five populations. Five samples, each comprised of 25 observations, were taken from the five populations. The numerator and denominator (respectively) degrees of freedom for the critical value of F are

Accepted Answer

A)  5 and 25. 
B)  4 and 25. 
C)  4 and 124. 
D)  4 and 120. 
A)  5 and 25. 
B)  4 and 25. 
C)  4 and 124. 
D)  4 and 120.

Question 9

An ANOVA procedure is applied to data obtained from 6 samples where each sample contains 20 observations. The critical value of F occurs with

Accepted Answer

A)  6 numerator and 20 denominator degrees of freedom. 
B)  5 numerator and 20 denominator degrees of freedom. 
C)  5 numerator and 114 denominator degrees of freedom. 
D)  6 numerator and 114 denominator degrees of freedom. 
A)  6 numerator and 20 denominator degrees of freedom. 
B)  5 numerator and 20 denominator degrees of freedom. 
C)  5 numerator and 114 denominator degrees of freedom. 
D)  6 numerator and 114 denominator degrees of freedom.

Question 10

In an analysis of variance, one estimate of σ2 is based upon the differences between the treatment means and the

Accepted Answer

A)  means of each sample. 
B)  overall sample mean. 
C)  sum of observations. 
D)  population means. 
A)  means of each sample. 
B)  overall sample mean. 
C)  sum of observations. 
D)  population means.

Question 11

To test whether or not there is a difference between treatments A, B, and C, a sample of 12 observations has been randomly assigned to the 3 treatments. You are given the results below. ​   ​
The test statistic to test the null hypothesis equals

Accepted Answer

A)  .944. 
B)  1.06. 
C)  3.13. 
D)  19.231. 
A)  .944. 
B)  1.06. 
C)  3.13. 
D)  19.231.

Question 12

Which of the following is not a required assumption for the analysis of variance?

Accepted Answer

A)  The random variable of interest for each population has a normal probability distribution. 
B)  The variance associated with the random variable must be the same for all populations. 
C)  At least 2 populations are under consideration. 
D)  Populations under consideration have equal means. 
A)  The random variable of interest for each population has a normal probability distribution. 
B)  The variance associated with the random variable must be the same for all populations. 
C)  At least 2 populations are under consideration. 
D)  Populations under consideration have equal means.

Question 13

In a factorial experiment, if there are x levels of factor A and y levels of factor B, there is a total of​

Accepted Answer

A)  ​x + y treatment combinations​. 
B)  ​(x + y)/2 treatment combinations​. 
C)  ​2(x + y) treatment combinations. 
D)  ​xy treatment combinations​. 
A)  ​x + y treatment combinations​. 
B)  ​(x + y)/2 treatment combinations​. 
C)  ​2(x + y) treatment combinations. 
D)  ​xy treatment combinations​.

Question 14

The process of using the same or similar experimental units for all treatments is called

Accepted Answer

A)  factoring. 
B)  blocking. 
C)  replicating. 
D)  partitioning. 
A)  factoring. 
B)  blocking. 
C)  replicating. 
D)  partitioning.

Question 15

For four populations, the population variances are assumed to be equal. Random samples from each population provide the following data.   ​
Using a .05 level of significance, test to see if the means for all four populations are the same.

Accepted Answer

F = 2.28; p-value is

Question 16

To test whether or not there is a difference between treatments A, B, and C, a sample of 12 observations has been randomly assigned to the 3 treatments. You are given the results below.   ​ The mean square due to error (MSE) equals

Accepted Answer

A)  1.872. 
B)  5.86. 
C)  34. 
D)  36. 
A)  1.872. 
B)  5.86. 
C)  34. 
D)  36.

Question 17

The process of allocating the total sum of squares and degrees of freedom to the various components is called

Accepted Answer

A)  factoring. 
B)  blocking. 
C)  replicating. 
D)  partitioning. 
A)  factoring. 
B)  blocking. 
C)  replicating. 
D)  partitioning.

Question 18

Part of an ANOVA table is shown below.   ​ The mean square due to treatments (MSTR) is

Accepted Answer

A)  20. 
B)  60. 
C)  18. 
D)  15. 
A)  20. 
B)  60. 
C)  18. 
D)  15.

Question 19

In an analysis of variance problem involving 3 treatments and 10 observations per treatment, SSE = 399.6. The MSE for this situation is

Accepted Answer

A)  133.2. 
B)  33.32. 
C)  12.1. 
D)  11.1. 
A)  133.2. 
B)  33.32. 
C)  12.1. 
D)  11.1.

Question 20

Consider the following information. ​
SSTR = 6750
H0: μ1 = μ2 = μ3 = μ4 =μ5
SSE = 8000
Ha: At least one mean is different
​
The null hypothesis is to be tested at the 5% level of significance. The null hypothesis

Accepted Answer

A)  should be rejected. 
B)  should not be rejected. 
C)  was designed incorrectly. 
D)  cannot be tested. 
A)  should be rejected. 
B)  should not be rejected. 
C)  was designed incorrectly. 
D)  cannot be tested.

Part of an ANOVA table is shown below. The number of degrees of freedom corresponding to between-treatments is

When an analysis of variance is performed on samples drawn from k populations, the mean square due to treatments (MSTR) is

In the ANOVA, treatments refer to

Consider the following ANOVA table. The test statistic to test the null hypothesis equals

The required condition for using an ANOVA procedure on data from several populations is that the

An ANOVA procedure is used for data obtained from five populations. Five samples, each comprised of 25 observations, were taken from the five populations. The numerator and denominator (respectively) degrees of freedom for the critical value of F are

An ANOVA procedure is applied to data obtained from 6 samples where each sample contains 20 observations. The critical value of F occurs with

In an analysis of variance, one estimate of σ² is based upon the differences between the treatment means and the

To test whether or not there is a difference between treatments A, B, and C, a sample of 12 observations has been randomly assigned to the 3 treatments. You are given the results below. The test statistic to test the null hypothesis equals

Which of the following is not a required assumption for the analysis of variance?

In a factorial experiment, if there are x levels of factor A and y levels of factor B, there is a total of

The process of using the same or similar experimental units for all treatments is called

For four populations, the population variances are assumed to be equal. Random samples from each population provide the following data. Using a .05 level of significance, test to see if the means for all four populations are the same.

To test whether or not there is a difference between treatments A, B, and C, a sample of 12 observations has been randomly assigned to the 3 treatments. You are given the results below. The mean square due to error (MSE) equals

The process of allocating the total sum of squares and degrees of freedom to the various components is called

Part of an ANOVA table is shown below. The mean square due to treatments (MSTR) is

In an analysis of variance problem involving 3 treatments and 10 observations per treatment, SSE = 399.6. The MSE for this situation is

Consider the following information. SSTR = 6750 H₀: μ₁ =μ₂ =μ₃ =μ₄=μ₅ SSE = 8000 H_a: At least one mean is different The null hypothesis is to be tested at the 5% level of significance. The null hypothesis

Data and Statistics

Descriptive Statistics: Tabular and Graphical Displays

Descriptive Statistics: Numerical Measures

Introduction to Probability

Discrete Probability Distributions

Continuous Probability Distributions

Sampling and Sampling Distributions

Interval Estimation

Hypothesis Tests

Inference About Means and Proportions With Two Populations

Inferences About Population Variances

Comparing Multiple Proportions, Tests of Independence and Goodness of Fit

Simple Linear Regression

Multiple Regression

Regression Analysis: Model Building

Time Series Analysis and Forecasting

Nonparametric Methods

Decision Analysis

Index Numbers

Statistical Methods for Quality Control

Sample Survey

Filters

Exam 13: Experimental Design and Analysis of Variance

Part of an ANOVA table is shown below. ​ The number of degrees of freedom corresponding to between-treatments is

When an analysis of variance is performed on samples drawn from k populations, the mean square due to treatments (MSTR) is

In the ANOVA, treatments refer to

Consider the following ANOVA table. ​ ​ The test statistic to test the null hypothesis equals

The required condition for using an ANOVA procedure on data from several populations is that the

An ANOVA procedure is used for data obtained from five populations. Five samples, each comprised of 25 observations, were taken from the five populations. The numerator and denominator (respectively) degrees of freedom for the critical value of F are

An ANOVA procedure is applied to data obtained from 6 samples where each sample contains 20 observations. The critical value of F occurs with

In an analysis of variance, one estimate of σ2 is based upon the differences between the treatment means and the

To test whether or not there is a difference between treatments A, B, and C, a sample of 12 observations has been randomly assigned to the 3 treatments. You are given the results below. ​ ​ The test statistic to test the null hypothesis equals

Which of the following is not a required assumption for the analysis of variance?

In a factorial experiment, if there are x levels of factor A and y levels of factor B, there is a total of​

The process of using the same or similar experimental units for all treatments is called

For four populations, the population variances are assumed to be equal. Random samples from each population provide the following data. ​ Using a .05 level of significance, test to see if the means for all four populations are the same.

To test whether or not there is a difference between treatments A, B, and C, a sample of 12 observations has been randomly assigned to the 3 treatments. You are given the results below. ​ The mean square due to error (MSE) equals

The process of allocating the total sum of squares and degrees of freedom to the various components is called

Part of an ANOVA table is shown below. ​ The mean square due to treatments (MSTR) is

In an analysis of variance problem involving 3 treatments and 10 observations per treatment, SSE = 399.6. The MSE for this situation is

Consider the following information. ​ SSTR = 6750 H0: μ1 = μ2 = μ3 = μ4 =μ5 SSE = 8000 Ha: At least one mean is different ​ The null hypothesis is to be tested at the 5% level of significance. The null hypothesis

Data and Statistics

Descriptive Statistics: Tabular and Graphical Displays

Descriptive Statistics: Numerical Measures

Introduction to Probability

Discrete Probability Distributions

Continuous Probability Distributions

Sampling and Sampling Distributions

Interval Estimation

Hypothesis Tests

Inference About Means and Proportions With Two Populations

Inferences About Population Variances

Comparing Multiple Proportions, Tests of Independence and Goodness of Fit

Simple Linear Regression

Multiple Regression

Regression Analysis: Model Building

Time Series Analysis and Forecasting

Nonparametric Methods

Decision Analysis

Index Numbers

Statistical Methods for Quality Control

Sample Survey

Filters

Part of an ANOVA table is shown below. The number of degrees of freedom corresponding to between-treatments is

Consider the following ANOVA table. The test statistic to test the null hypothesis equals

In an analysis of variance, one estimate of σ² is based upon the differences between the treatment means and the

To test whether or not there is a difference between treatments A, B, and C, a sample of 12 observations has been randomly assigned to the 3 treatments. You are given the results below. The test statistic to test the null hypothesis equals

In a factorial experiment, if there are x levels of factor A and y levels of factor B, there is a total of

For four populations, the population variances are assumed to be equal. Random samples from each population provide the following data. Using a .05 level of significance, test to see if the means for all four populations are the same.

To test whether or not there is a difference between treatments A, B, and C, a sample of 12 observations has been randomly assigned to the 3 treatments. You are given the results below. The mean square due to error (MSE) equals

Part of an ANOVA table is shown below. The mean square due to treatments (MSTR) is

Consider the following information. SSTR = 6750 H₀: μ₁ =μ₂ =μ₃ =μ₄=μ₅ SSE = 8000 H_a: At least one mean is different The null hypothesis is to be tested at the 5% level of significance. The null hypothesis