Exam 4: Linear Regression With One Regressor

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(Requires Appendix material)The sample average of the OLS residuals is

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In order to calculate the regression R2R ^ { 2 } you need the TSS and either the SSR or the ESS . The TSS is fairly straightforward to calculate, being just the variation of Y . However, if you had to calculate the SSR or ESS by hand (or in a spreadsheet), you would need all fitted values from the regression function and their deviations from the sample mean, or the residuals. Can you think of a quicker way to calculate the ESS simply using terms you have already used to calculate the slope coefficient?

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Assume that there is a change in the units of measurement on both Y and X . The new variables are Y=aYY ^ { * } = a Y and X=bXX ^ { * } = b X What effect will this change have on the regression slope?

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The OLS residuals, u^i,\hat { u } _ { i } , are defined as follows:

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To obtain the slope estimator using the least squares principle, you divide the a. sample variance of XX by the sample variance of YY . b. sample covariance of XX and YY by the sample variance of YY . c. sample covariance of XX and YY by the sample variance of XX . d. sample variance of XX by the sample covariance of XX and YY .

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In the simple linear regression model Yi=β0+β1Xi+uiY _ { i } = \beta _ { 0 } + \beta _ { 1 } X _ { i } + u _ { i }

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Consider the sample regression function Yi=β^0+β^1Xi+u^i.Y _ { i } = \hat { \beta } _ { 0 } + \hat { \beta } _ { 1 } X _ { i } + \hat { u } _ { i } . First, take averages on both sides of the equation. Second, subtract the resulting equation from the above equation to write the sample regression function in deviations from means. (For simplicity, you may want to use small letters to indicate deviations from the mean, i.e., zi=ZiZˉz _ { i } = Z _ { i } - \bar { Z } .) Finally, illustrate in a two-dimensional diagram with SSRS S R on the vertical axis and the regression slope on the horizontal axis how you could find the least squares estimator for the slope by varying its values through trial and error.

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Given the amount of money and effort that you have spent on your education, you wonder if it was (is) all worth it. You therefore collect data from the Current Population Survey (CPS) and estimate a linear relationship between earnings and the years of education of individuals. What would be the effect on your regression slope and intercept if you measured earnings in thousands of dollars rather than in dollars? Would the regression R2R ^ { 2 } be affected? Should statistical inference be dependent on the scale of variables? Discuss.

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If the three least squares assumptions hold, then the large sample normal distribution of β^1\widehat { \beta } _ { 1 } is

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Imagine that you had discovered a relationship that would generate a scatterplot very similar to the relationship Yi=Xi2Y _ { i } = X _ { i } ^ { 2 } , and that you would try to fit a linear regression through your data points. What do you expect the slope coefficient to be? What do you think the value of your regression R2 is in this situation? What are the implications from your answers in terms of fitting a linear regression through a non-linear relationship?

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The reason why estimators have a sampling distribution is that

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The following are all least squares assumptions with the exception of: a. The conditional distribution of uiu _ { i } given XiX _ { i } has a mean of zero. b. The explanatory variable in regression model is normally distributed. c. (Xi,Yi),i=1,,n\left( X _ { i } , Y _ { i } \right) , i = 1 , \ldots , n are independently and identically distributed. d. Large outliers are unlikely.

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In the simple linear regression model, the regression slope

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Your textbook presented you with the following regression output: TestScore =698.9-2.28\timesSTR n=420,=0.051,SER=18.6 (a)How would the slope coefficient change, if you decided one day to measure testscores in 100s, i.e., a testscore of 650 became 6.5? Would this have an effect on your interpretation?

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