Exam 10: Parametric Equations and Polar Coordinates

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Eliminate the parameter to find a Cartesian equation of the curve. x=e4t5,y=e8tx = e ^ { 4 t } - 5 , \quad y = e ^ { 8 t }

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y=(x+5)2y = ( x + 5 ) ^ { 2 }

Find d2ydx2\frac { d ^ { 2 } y } { d x ^ { 2 } } x=5+t2,y=tt3x = 5 + t ^ { 2 } , y = t - t ^ { 3 }

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3t2+14t3- \frac { 3 t ^ { 2 } + 1 } { 4 t ^ { 3 } }

Find an equation for the conic that satisfies the given conditions. ellipse, foci (±1,6)( \pm 1,6 ) , length of major axis 8

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Find the eccentricity of the conic. r=585sinθr = \frac { 5 } { 8 - 5 \sin \theta }

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Find an equation of the tangent to the curve at the point corresponding to the given value of the parameter. x=tcost,y=tsint,t=5πx = t \cos t , \quad y = t \sin t , \quad t = 5 \pi

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Set up an integral that represents the length of the curve.Then use your calculator to find the length correct to four decimal places. x=t2sint,y=12cost,0t5πx = t - 2 \sin t , \quad y = 1 - 2 \cos t , \quad 0 \leq t \leq 5 \pi

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Find an equation of the tangent to the curve at the point corresponding to the given value of the parameter. x=4tcost,y=4tsint,t=πx = 4 t \cos t , y = 4 t \sin t , t = - \pi

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Write a polar equation of the conic that has a focus at the origin, eccentricity 72\frac { 7 } { 2 } , and directrix y=7y = - 7 . Identify the conic.

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The point in a lunar orbit nearest the surface of the moon is called perilune and the point farthest from the surface is called apolune. The Apollo 11 spacecraft was placed in an elliptical lunar orbit with perilune altitude 106 km106 \mathrm {~km} and apolune altitude 318 km318 \mathrm {~km} (above the moon). Find an equation of this ellipse if the radius of the moon is 1728 km1728 \mathrm {~km} and the center of the moon is at one focus.

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A cross-section of a parabolic reflector is shown in the figure. The bulb is located at the focus and the opening at the focus is 18 cm18 \mathrm {~cm} . Find an equation of the parabola. Let VV be the origin. Find the diameter of the opening CD,19 cm| C D | , 19 \mathrm {~cm} from the vertex.  A cross-section of a parabolic reflector is shown in the figure. The bulb is located at the focus and the opening at the focus is  18 \mathrm {~cm} . Find an equation of the parabola. Let  V  be the origin. Find the diameter of the opening  | C D | , 19 \mathrm {~cm}  from the vertex.

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The orbit of Hale-Bopp comet, discovered in 1995, is an ellipse with eccentricity 0.9950.995 and one focus at the Sun. The length of its major axis is 366.5AU366.5 \mathrm { AU } . [An astronomical unit (AU) is the mean distance between Earth and the Sun, about 93 million miles.] Find the maximum distance from the comet to the Sun. (The perihelion distance from a planet to the Sun is a(1e)a ( 1 - e ) and the aphelion distance is a(1+e)a ( 1 + e ) .) Find the answer in AU\mathrm { AU } and round to the nearest hundredth.

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Use a graph to estimate the values of θ\theta for which the curves r=9+3sin5θr = 9 + 3 \sin 5 \theta and r=18sinθr = 18 \sin \theta intersect. Round your answer to two decimal places.

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Find the exact area of the surface obtained by rotating the given curve about the x-axis. x=2cos3θ,y=2sin3θ,0θπ/2x = 2 \cos ^ { 3 } \theta , \quad y = 2 \sin ^ { 3 } \theta , \quad 0 \leq \theta \leq \pi / 2

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Find the point(s) of intersection of the curves r=2r = 2 and r=4cosθr = 4 \cos \theta .

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Find the area of the region that lies inside the first curve and outside the second curve. r=3cosθ,r=1+cosθr = 3 \cos \theta , \quad r = 1 + \cos \theta

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Set up, but do not evaluate, an integral that represents the length of the parametric curve. x=tt10,y=109t9/8,8t18x = t - t ^ { 10 } , y = \frac { 10 } { 9 } t ^ { 9 / 8 } , \quad 8 \leq \mathrm { t } \leq 18

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Using the arc length formula, set up, but do not evaluate, an integral equal to the total arc length of the ellipse. x=4sinθ,y=2cosθx = 4 \sin \theta , \quad y = 2 \cos \theta

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 Find the area bounded by the curve x=t1t,y=t+1t and the line y=2.5\text { Find the area bounded by the curve } x = t - \frac { 1 } { t } , y = t + \frac { 1 } { t } \text { and the line } y = 2.5 \text {. }

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Find an equation of the hyperbola centered at the origin that satisfies the given condition. Vertices: (±4,0)( \pm 4,0 ) , asymptotes: y=±74xy = \pm \frac { 7 } { 4 } x

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Find the point(s) on the curve where the tangent is horizontal. x=t33t+2,y=t33t2+2x = t ^ { 3 } - 3 t + 2 , \quad y = t ^ { 3 } - 3 t ^ { 2 } + 2

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