Exam 10: Parametric Equations; Polar Equations

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The rectangular equation of the conic section r=35+4cosθr = \frac { 3 } { 5 + 4 \cos \theta } is

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The length of the curve x(t)=9t3,y(t)=t2x ( t ) = 9 - t ^ { 3 } , y ( t ) = t ^ { 2 } with t[0,2]t \in [ 0,2 ] is

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The length of r=6cosθr = 6 \cos \theta with x[0,π2]x \in \left[ 0 , \frac { \pi } { 2 } \right] is

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The area of the surface generated by revolving the curve x(t)=3t,y=7t+1x ( t ) = 3 t , \quad y = \sqrt { 7 } t + 1 with t[0,1]t \in [ 0,1 ] about the x-axis is

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The conic section r=57+8sinθr = \frac { 5 } { 7 + 8 \sin \theta } is

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If A is the area of the intersection of the regions inside 6π166 \pi - 16 and outside r=3r = \sqrt { 3 } \text {, } then A is

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If A is the area of the intersection of the regions enclosed by the graphs of r=2(1cosθ)r = 2 ( 1 - \cos \theta ) and r=2(1+cosθ),r = 2 ( 1 + \cos \theta ), then A is

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The rectangular equation of the plane curve, with parametric equations x(t)=et,y(t)=3etx ( t ) = e ^ { - t } , y ( t ) = 3 e ^ { t } with t(,)t \in ( - \infty , \infty ) , is

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The polar equation that corresponds to the rectangular equation y=x2y = x ^ { 2 } is

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The rectangular equation that corresponds to the polar equation r2=θ\frac { r } { 2 } = \theta is

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For a \neq 0, the polar curve r2=asin2θr ^ { 2 } = a \sin 2 \theta is a

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For a \neq 0, the polar curve r=a(1+2cosθ)r = a ( 1 + 2 \cos \theta ) is a

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The area of the surface generated by revolving the curve x(t)=1t2,y=3+2tx ( t ) = 1 - t ^ { 2 } , y = 3 + 2 t with t[0,1]t \in [ 0,1 ] about the x-axis is

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If A is the area of the region bounded by one petal of the four-petal rose r=cos2θ,r = \cos 2 \theta, then A is

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Find the points on the curve x(t)=t31+t,y(t)=11+tx ( t ) = \frac { t ^ { 3 } } { 1 + t } , y ( t ) = \frac { 1 } { 1 + t } where the tangent line is vertical.

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If A is the area of the intersection of the regions enclosed by the graphs of r=2r = 2 and r=32cosθ,r = 3 - 2 \cos \theta, then A is

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The parametric equations of the line segment from (1,0) to (0,1) with t \in [0,1] are

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If A is the area of the region bounded by one leaf of the lemniscates r2=3sin2θ,r ^ { 2 } = 3 \sin 2 \theta, then A is

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The length of the curve x(t)=etcost,y(t)=etsintx ( t ) = e ^ { t } \cos t , y ( t ) = e ^ { t } \sin t with t[0,π]t \in [ 0 , \pi ] is

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Let x(t)=lnt,y(t)=1tx ( t ) = \ln t , y ( t ) = \frac { 1 } { t } be the parametric equations of a curve. Then dydx\frac { d y } { d x } is

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