Question 1

Use VSEPR theory to match the molecule with its shape.
-PH3

Accepted Answer

A)  square planar 
B)  angular 
C)  pyramidal 
D)  tetrahedral 
A)  square planar 
B)  angular 
C)  pyramidal 
D)  tetrahedral C

Question 2

Use VSEPR theory to match the molecule with its shape.
-CCl2(CH3)2

Accepted Answer

A)  square planar 
B)  angular 
C)  pyramidal 
D)  tetrahedral 
A)  square planar 
B)  angular 
C)  pyramidal 
D)  tetrahedral D

Question 3

The process of an atom changing the energy and shape of its atomic orbitals to increase the opportunities for bonding with other atoms is called __________

Accepted Answer

hybridization

Question 4

For each of the atoms highlighted in bold, determine the type of hybridization present.
-CH3CH2OH

Accepted Answer

A)  sp 
B)  sp2 
C)  sp3 
A)  sp 
B)  sp2 
C)  sp3

Question 5

The linear molecule COS is non polar.

Accepted Answer

A) True 
 B)False

Question 6

The shape predicted by VSEPR theory for [BrF4]+ is trigonal pyramidal.

Accepted Answer

A) True 
 B)False

Question 7

The total number of electrons surrounding Xe in XeF4 as predicted by VSEPR theory is 12. Valence bond theory would suggest that this arrangement would require d2sp3 hybridization.

Accepted Answer

A) True 
 B)False

Question 8

Using VSEPR theory, a molecule having 5 electron pairs divided between 3 bonding pairs and 2 lone pairs will be trigonal planar true-false

Accepted Answer

A) True 
 B)False

Question 9

Which of the following geometries are predicted for molecules in which all the electron pairs are bonding in VSEPR theory? Please select all that apply.

Accepted Answer

A)  linear 
B)  tetrahedral 
C)  square pyramidal 
D)  pentagonal bipyramidal 
A)  linear 
B)  tetrahedral 
C)  square pyramidal 
D)  pentagonal bipyramidal

Question 10

SF6 is a hypervalent compound of sulfur which lies in the third period of the Periodic Table. Charge separation can be use to account for the exceptional valence of SF6.

Accepted Answer

A) True 
 B)False

Question 11

A double bond takes up less room than a single bond. true-false

Accepted Answer

A) True 
 B)False

Question 12

Which of the following factors affect the shape at the central atom in VSEPR theory? Please select all that apply.

Accepted Answer

A)  The charge. 
B)  The F1F1F1S1F1F1F10 bonded electron pairs. 
C)  The F1F1F1S1F1F1F10 bonded electron pairs. 
D)  The electronic contribution of the ligands. 
A)  The charge. 
B)  The F1F1F1S1F1F1F10 bonded electron pairs. 
C)  The F1F1F1S1F1F1F10 bonded electron pairs. 
D)  The electronic contribution of the ligands.

Question 13

VSEPR predicts that shape of the ion TeBr62- is octahedral.

Accepted Answer

A) True 
 B)False

Question 14

For each of the atoms highlighted in bold, determine the type of hybridization present.
-C6H5CO2H (benzoic acid)

Accepted Answer

A)  sp 
B)  sp2 
C)  sp3 
A)  sp 
B)  sp2 
C)  sp3

Question 15

When negative charges are present in a structure where formal charges can be assigned, the lowest energy structure is the one with the negative charge on the most ____________ atom.

Accepted Answer

The answer of When negative charges are present in a...

Question 16

In BeH2, the 2F1F1F1S1F1F1F10g orbital is closer in energy and properties to the atomic orbitals of _______

Accepted Answer

Question 17

Use VSEPR theory to match the molecule with its shape.
-[ClF4]-

Accepted Answer

A)  square planar 
B)  angular 
C)  pyramidal 
D)  tetrahedral 
A)  square planar 
B)  angular 
C)  pyramidal 
D)  tetrahedral

Question 18

COS adopts a structure with a central carbon atom.

Accepted Answer

A) True 
 B)False

Question 19

Use VSEPR theory to determine the structure of the borate anion, [BO4]5-.

Accepted Answer

A)  Trigonal bipyramidal with one lone pair and four bond pairs. 
B)  Trigonal bipyramidal with two lone pairs and three bond pairs. 
C)  Tetrahedral 
D)  Square planar 
A)  Trigonal bipyramidal with one lone pair and four bond pairs. 
B)  Trigonal bipyramidal with two lone pairs and three bond pairs. 
C)  Tetrahedral 
D)  Square planar

Question 20

One way of describing the bonding in XeF2 which avoids hypervalency for xenon is using the 3 centre 4 electron bond. Which combination of orbitals generate a non-bonding combination for the XeF2 molecule?

Accepted Answer

A)  In phase combination of the two F pz orbitals and the pz orbital on the Xe. 
B)  Out of phase combination of the two F pz orbitals and the pz orbital on the Xe. 
C)  In phase combination of the two F pz orbitals and the px orbital on the Xe. 
D)  In phase combination of the two F px orbitals and the pz orbital on the Xe. 
A)  In phase combination of the two F pz orbitals and the pz orbital on the Xe. 
B)  Out of phase combination of the two F pz orbitals and the pz orbital on the Xe. 
C)  In phase combination of the two F pz orbitals and the px orbital on the Xe. 
D)  In phase combination of the two F px orbitals and the pz orbital on the Xe.

Exam 5: Polyatomic Molecules

Use VSEPR theory to match the molecule with its shape. -PH3

Use VSEPR theory to match the molecule with its shape. -CCl2(CH3)2

The process of an atom changing the energy and shape of its atomic orbitals to increase the opportunities for bonding with other atoms is called __________

For each of the atoms highlighted in bold, determine the type of hybridization present. -CH3CH2OH

The linear molecule COS is non polar.

The shape predicted by VSEPR theory for [BrF4]+ is trigonal pyramidal.

The total number of electrons surrounding Xe in XeF4 as predicted by VSEPR theory is 12. Valence bond theory would suggest that this arrangement would require d2sp3 hybridization.

Using VSEPR theory, a molecule having 5 electron pairs divided between 3 bonding pairs and 2 lone pairs will be trigonal planar true-false

Which of the following geometries are predicted for molecules in which all the electron pairs are bonding in VSEPR theory? Please select all that apply.

SF6 is a hypervalent compound of sulfur which lies in the third period of the Periodic Table. Charge separation can be use to account for the exceptional valence of SF6.

A double bond takes up less room than a single bond. true-false

Which of the following factors affect the shape at the central atom in VSEPR theory? Please select all that apply.

VSEPR predicts that shape of the ion TeBr62- is octahedral.

For each of the atoms highlighted in bold, determine the type of hybridization present. -C6H5CO2H (benzoic acid)

When negative charges are present in a structure where formal charges can be assigned, the lowest energy structure is the one with the negative charge on the most ____________ atom.

In BeH2, the 2g orbital is closer in energy and properties to the atomic orbitals of _______

Use VSEPR theory to match the molecule with its shape. -[ClF4]-

COS adopts a structure with a central carbon atom.

Use VSEPR theory to determine the structure of the borate anion, [BO4]5-.

One way of describing the bonding in XeF2 which avoids hypervalency for xenon is using the 3 centre 4 electron bond. Which combination of orbitals generate a non-bonding combination for the XeF2 molecule?

Fundamentals

The Language of Organic Chemistry

Atomic Structure and Properties

Diatomic Molecules

Solids

Acids and Bases

Gases

Reaction Kinetics

Molecular Spectroscopy

Analytical Chemistry

Molecular Characterisation

Energy and Thermochemistry

Entropy and Gibbs Energy

Electrochemistry

Phase Equilibrium and Solutions

Isomerism and Stereochemistry

Organic Reaction Mechanisms

Halogenoalkanes: Substitution and Elimination Reactions

Alkenes and Alkynes: Electrophilic Addition and Pericyclic Reactions

Benzene and Other Aromatic Compounds: Electrophilic Substitution Reactions

Aldehydes and Ketones: Nucleophilic Addition and Α-Substitution Reactions

Carboxylic Acids and Derivatives: Nucleophilic Acyl Substitution and Α-Substitution Reactions

Hydrogen

S-Block Chemistry

P-Block Chemistry

D-Block Chemistry

Filters

Use VSEPR theory to match the molecule with its shape. -PH₃

Use VSEPR theory to match the molecule with its shape. -CCl₂(CH₃)₂

For each of the atoms highlighted in bold, determine the type of hybridization present. -CH₃CH₂OH

The shape predicted by VSEPR theory for [BrF₄]⁺ is trigonal pyramidal.

The total number of electrons surrounding Xe in XeF₄ as predicted by VSEPR theory is 12. Valence bond theory would suggest that this arrangement would require d²sp³ hybridization.

SF₆ is a hypervalent compound of sulfur which lies in the third period of the Periodic Table. Charge separation can be use to account for the exceptional valence of SF₆.

VSEPR predicts that shape of the ion TeBr₆^2- is octahedral.

For each of the atoms highlighted in bold, determine the type of hybridization present. -C₆H₅CO₂H (benzoic acid)

In BeH₂, the 2_g orbital is closer in energy and properties to the atomic orbitals of _______

Use VSEPR theory to match the molecule with its shape. -[ClF₄]^-

Use VSEPR theory to determine the structure of the borate anion, [BO₄]^5-.

One way of describing the bonding in XeF₂ which avoids hypervalency for xenon is using the 3 centre 4 electron bond. Which combination of orbitals generate a non-bonding combination for the XeF₂ molecule?