Exam 41: Linear and Nonlinear Systems of Equations

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Use a graphing utility to solve the system of equations.Find the solution(s)accurate to two decimal places.​ {y=ex+4xy+5=0\left\{ \begin{aligned}y & = e ^ { x + 4 } \\x - y + 5 & = 0\end{aligned} \right.

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E

Find the dimensions of the rectangle meeting the specified condition. ​ The perimeter is 36 meters and the length is 4 meters greater than the width. ​

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C

Solve the system by the method of substitution.​ {1.3x+0.6y=5.70.9x0.2y=2.1\left\{ \begin{array} { l } 1.3 x + 0.6 y = 5.7 \\0.9 x - 0.2 y = 2.1\end{array} \right.

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B

The sales of various types of lawn and garden tools vary according to the season.At a certain home improvement store,the monthly sales H of garden hoes (hoes sold per month)decline from July to October whereas the monthly sales of lawn rakes R (rakes sold per month)increase during this same interval.The sales of these two items during the calendar months July-October are modeled by the equations:​ H(t)=64-6t R(t)=17t-143 ​ where t is the month (t = 7 corresponds to July).In which month does the number of rakes sold equal the number of hoes sold? ​

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Solve the system by substitution,if possible.​ {6x+7y=5012x+14y=124\left\{ \begin{array} { l } - 6 x + 7 y = 50 \\12 x + 14 y = 124\end{array} \right.

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Select the ordered pair that is a solution of the system of equations.​ {2xy=38x+y=18\left\{ \begin{array} { l } 2 x - y = 3 \\8 x + y = - 18\end{array} \right.

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Solve the system graphically.​ {xy=16x3y=24\left\{ \begin{aligned}x - y & = 1 \\6 x - 3 y & = 24\end{aligned} \right. ​ ​

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Find the sales necessary to break even (R = C)for the cost C of producing x units and the revenue R obtained by selling x units.(Round to the nearest whole unit. )​ C=6.5x+9,674,R=3.2xC = 6.5 \sqrt { x } + 9,674 , R = 3.2 x

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Solve the system by the method of substitution.​ {y=x36x2+4y=x210x+4\left\{ \begin{array} { l } y = x ^ { 3 } - 6 x ^ { 2 } + 4 \\y = x ^ { 2 } - 10 x + 4\end{array} \right.

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Solve the system graphically.​ {x3y=75x+3y=8\left\{ \begin{aligned}x - 3 y & = - 7 \\5 x + 3 y & = - 8\end{aligned} \right.

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Solve the system by the method of substitution.Check your solution(s)graphically.​ {2x+y=9x+y=0\left\{ \begin{array} { r } 2 x + y = 9 \\- x + y = 0\end{array} \right. Solve the system by the method of substitution.Check your solution(s)graphically.​  \left\{ \begin{array} { r }  2 x + y = 9 \\ - x + y = 0 \end{array} \right.  ​

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Find the dimensions of the rectangle meeting the specified conditions. The perimeter is 48 meters and the length is 2 meters more than the width.

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Solve the system by the method of substitution.​ {2xy+2=04x+y5=0\left\{ \begin{array} { l } 2 x - y + 2 = 0 \\4 x + y - 5 = 0\end{array} \right. ​ ​

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Solve the system by the method of substitution.Check your solution(s)graphically.​ {x2y=9x+3y=1\left\{ \begin{array} { l } x - 2 y = - 9 \\x + 3 y = 1\end{array} \right. Solve the system by the method of substitution.Check your solution(s)graphically.​  \left\{ \begin{array} { l }  x - 2 y = - 9 \\ x + 3 y = 1 \end{array} \right.  ​   ​

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Solve the system by the method of substitution.​ {xy=47x4y=37\left\{ \begin{aligned}x - y & = 4 \\7 x - 4 y & = 37\end{aligned} \right.

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Solve the system by substitution,if possible.​ {y=7x219xy=29\left\{ \begin{array} { l } y = 7 x - 21 \\9 x - y = 29\end{array} \right.

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Solve the system by the method of substitution.​ {0.5x+3.2y=5.30.3x1.4y=1.8\left\{ \begin{array} { l } 0.5 x + 3.2 y = 5.3 \\0.3 x - 1.4 y = - 1.8\end{array} \right.

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Solve the system by the method of substitution.Check your solution(s)graphically.​ {x2+2y=0x26xy=0\left\{ \begin{array} { r } x ^ { 2 } + 2 y = 0 \\x ^ { 2 } - 6 x - y = 0\end{array} \right. Solve the system by the method of substitution.Check your solution(s)graphically.​  \left\{ \begin{array} { r }  x ^ { 2 } + 2 y = 0 \\ x ^ { 2 } - 6 x - y = 0 \end{array} \right.  ​   ​

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Find the dimensions of the rectangle meeting the specified condition. ​ The perimeter is 30.6 millimeters and the length is 2.4 times the width. ​

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Solve the system by the method of substitution. ​​ {9x4y2=0x+9y4=0\left\{ \begin{array} { r } 9 x - 4 y - 2 = 0 \\x + 9 y - 4 = 0\end{array} \right.

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