Exam 10: Inference for Regression

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A random sample of 79 companies from the Forbes 500 list (which actually consists of nearly 800 companies)was selected,and the relationship between sales (in hundreds of thousands of dollars)and profits (in hundreds of thousands of dollars)was investigated by regression.The following results were obtained from statistical software. A random sample of 79 companies from the Forbes 500 list (which actually consists of nearly 800 companies)was selected,and the relationship between sales (in hundreds of thousands of dollars)and profits (in hundreds of thousands of dollars)was investigated by regression.The following results were obtained from statistical software.     Suppose the researchers conducting this study wish to estimate the profits (in hundreds of thousands of dollars)for companies that had sales (in hundreds of thousands of dollars)of 500.The following results were obtained from statistical software.   If the researchers wish to estimate the mean profits for all companies that had sales of 500,what would be a 95% confidence interval for the mean profits? A random sample of 79 companies from the Forbes 500 list (which actually consists of nearly 800 companies)was selected,and the relationship between sales (in hundreds of thousands of dollars)and profits (in hundreds of thousands of dollars)was investigated by regression.The following results were obtained from statistical software.     Suppose the researchers conducting this study wish to estimate the profits (in hundreds of thousands of dollars)for companies that had sales (in hundreds of thousands of dollars)of 500.The following results were obtained from statistical software.   If the researchers wish to estimate the mean profits for all companies that had sales of 500,what would be a 95% confidence interval for the mean profits? Suppose the researchers conducting this study wish to estimate the profits (in hundreds of thousands of dollars)for companies that had sales (in hundreds of thousands of dollars)of 500.The following results were obtained from statistical software. A random sample of 79 companies from the Forbes 500 list (which actually consists of nearly 800 companies)was selected,and the relationship between sales (in hundreds of thousands of dollars)and profits (in hundreds of thousands of dollars)was investigated by regression.The following results were obtained from statistical software.     Suppose the researchers conducting this study wish to estimate the profits (in hundreds of thousands of dollars)for companies that had sales (in hundreds of thousands of dollars)of 500.The following results were obtained from statistical software.   If the researchers wish to estimate the mean profits for all companies that had sales of 500,what would be a 95% confidence interval for the mean profits? If the researchers wish to estimate the mean profits for all companies that had sales of 500,what would be a 95% confidence interval for the mean profits?

(Multiple Choice)
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Do heavier cars use more gasoline? To answer this question,a researcher randomly selected 15 cars.He collected their weight (in hundreds of pounds)and the mileage (MPG)for each car.From a scatter plot made with the data,a linear model seemed appropriate.The following output was obtained from SPSS: Do heavier cars use more gasoline? To answer this question,a researcher randomly selected 15 cars.He collected their weight (in hundreds of pounds)and the mileage (MPG)for each car.From a scatter plot made with the data,a linear model seemed appropriate.The following output was obtained from SPSS:     Which of the following descriptions of the value of the slope is the correct description? Do heavier cars use more gasoline? To answer this question,a researcher randomly selected 15 cars.He collected their weight (in hundreds of pounds)and the mileage (MPG)for each car.From a scatter plot made with the data,a linear model seemed appropriate.The following output was obtained from SPSS:     Which of the following descriptions of the value of the slope is the correct description? Which of the following descriptions of the value of the slope is the correct description?

(Multiple Choice)
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Deborah's Dairy Market sells both cottage cheese and ice cream.The sales manager recently noticed that in months when the company soldmore cottage cheese,it seemed to sell more ice cream as well,on average.One of the store's aides was assigned to put this theory to the test.The aide's analysis of sales data for the past 12 months (in millions of pounds for both the cottage cheese and the ice cream)gave the following SPSS output. Deborah's Dairy Market sells both cottage cheese and ice cream.The sales manager recently noticed that in months when the company soldmore cottage cheese,it seemed to sell more ice cream as well,on average.One of the store's aides was assigned to put this theory to the test.The aide's analysis of sales data for the past 12 months (in millions of pounds for both the cottage cheese and the ice cream)gave the following SPSS output.       Suppose the aide wishes to test the hypotheses H<sub>0</sub>: <font face=symbol></font><sub>1</sub> = 0 versus H<sub>a</sub>: <font face=symbol></font><sub>1</sub>> 0.What is the value of the P-value for this test? Deborah's Dairy Market sells both cottage cheese and ice cream.The sales manager recently noticed that in months when the company soldmore cottage cheese,it seemed to sell more ice cream as well,on average.One of the store's aides was assigned to put this theory to the test.The aide's analysis of sales data for the past 12 months (in millions of pounds for both the cottage cheese and the ice cream)gave the following SPSS output.       Suppose the aide wishes to test the hypotheses H<sub>0</sub>: <font face=symbol></font><sub>1</sub> = 0 versus H<sub>a</sub>: <font face=symbol></font><sub>1</sub>> 0.What is the value of the P-value for this test? Deborah's Dairy Market sells both cottage cheese and ice cream.The sales manager recently noticed that in months when the company soldmore cottage cheese,it seemed to sell more ice cream as well,on average.One of the store's aides was assigned to put this theory to the test.The aide's analysis of sales data for the past 12 months (in millions of pounds for both the cottage cheese and the ice cream)gave the following SPSS output.       Suppose the aide wishes to test the hypotheses H<sub>0</sub>: <font face=symbol></font><sub>1</sub> = 0 versus H<sub>a</sub>: <font face=symbol></font><sub>1</sub>> 0.What is the value of the P-value for this test? Suppose the aide wishes to test the hypotheses H0: 1 = 0 versus Ha: 1> 0.What is the value of the P-value for this test?

(Short Answer)
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The moisture in a wet mix of cement was considered to have an effect on the denseness of the finished product.The moisture of the mix was controlled at various levels,and the denseness of the finished product was measured.The data were entered into SPSS,and the following output was generated. The moisture in a wet mix of cement was considered to have an effect on the denseness of the finished product.The moisture of the mix was controlled at various levels,and the denseness of the finished product was measured.The data were entered into SPSS,and the following output was generated.           The standard error for the slope is reported to be 0.90.Which of the following interpretations of this standard error is correct? The moisture in a wet mix of cement was considered to have an effect on the denseness of the finished product.The moisture of the mix was controlled at various levels,and the denseness of the finished product was measured.The data were entered into SPSS,and the following output was generated.           The standard error for the slope is reported to be 0.90.Which of the following interpretations of this standard error is correct? The moisture in a wet mix of cement was considered to have an effect on the denseness of the finished product.The moisture of the mix was controlled at various levels,and the denseness of the finished product was measured.The data were entered into SPSS,and the following output was generated.           The standard error for the slope is reported to be 0.90.Which of the following interpretations of this standard error is correct? The moisture in a wet mix of cement was considered to have an effect on the denseness of the finished product.The moisture of the mix was controlled at various levels,and the denseness of the finished product was measured.The data were entered into SPSS,and the following output was generated.           The standard error for the slope is reported to be 0.90.Which of the following interpretations of this standard error is correct? The moisture in a wet mix of cement was considered to have an effect on the denseness of the finished product.The moisture of the mix was controlled at various levels,and the denseness of the finished product was measured.The data were entered into SPSS,and the following output was generated.           The standard error for the slope is reported to be 0.90.Which of the following interpretations of this standard error is correct? The standard error for the slope is reported to be 0.90.Which of the following interpretations of this standard error is correct?

(Multiple Choice)
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Deborah's Dairy Market sells both cottage cheese and ice cream.The sales manager recently noticed that in months when the company soldmore cottage cheese,it seemed to sell more ice cream as well,on average.One of the store's aides was assigned to put this theory to the test.The aide's analysis of sales data for the past 12 months (in millions of pounds for both the cottage cheese and the ice cream)gave the following SPSS output. Deborah's Dairy Market sells both cottage cheese and ice cream.The sales manager recently noticed that in months when the company soldmore cottage cheese,it seemed to sell more ice cream as well,on average.One of the store's aides was assigned to put this theory to the test.The aide's analysis of sales data for the past 12 months (in millions of pounds for both the cottage cheese and the ice cream)gave the following SPSS output.       What is the equation of the least-squares regression line? Deborah's Dairy Market sells both cottage cheese and ice cream.The sales manager recently noticed that in months when the company soldmore cottage cheese,it seemed to sell more ice cream as well,on average.One of the store's aides was assigned to put this theory to the test.The aide's analysis of sales data for the past 12 months (in millions of pounds for both the cottage cheese and the ice cream)gave the following SPSS output.       What is the equation of the least-squares regression line? Deborah's Dairy Market sells both cottage cheese and ice cream.The sales manager recently noticed that in months when the company soldmore cottage cheese,it seemed to sell more ice cream as well,on average.One of the store's aides was assigned to put this theory to the test.The aide's analysis of sales data for the past 12 months (in millions of pounds for both the cottage cheese and the ice cream)gave the following SPSS output.       What is the equation of the least-squares regression line? What is the equation of the least-squares regression line?

(Short Answer)
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The statistical model for simple linear regression is written as The statistical model for simple linear regression is written as   ,where   represents the mean of a Normally distributed response variable and x represents the explanatory variable.The parameters   and   are estimated,giving the linear regression model defined by   ,with standard deviation <font face=symbol></font> = 5. What is the range of values for 68% of the observed responses when x = 20 using the 68-95-99.7 rule? ,where The statistical model for simple linear regression is written as   ,where   represents the mean of a Normally distributed response variable and x represents the explanatory variable.The parameters   and   are estimated,giving the linear regression model defined by   ,with standard deviation <font face=symbol></font> = 5. What is the range of values for 68% of the observed responses when x = 20 using the 68-95-99.7 rule? represents the mean of a Normally distributed response variable and x represents the explanatory variable.The parameters The statistical model for simple linear regression is written as   ,where   represents the mean of a Normally distributed response variable and x represents the explanatory variable.The parameters   and   are estimated,giving the linear regression model defined by   ,with standard deviation <font face=symbol></font> = 5. What is the range of values for 68% of the observed responses when x = 20 using the 68-95-99.7 rule? and The statistical model for simple linear regression is written as   ,where   represents the mean of a Normally distributed response variable and x represents the explanatory variable.The parameters   and   are estimated,giving the linear regression model defined by   ,with standard deviation <font face=symbol></font> = 5. What is the range of values for 68% of the observed responses when x = 20 using the 68-95-99.7 rule? are estimated,giving the linear regression model defined by The statistical model for simple linear regression is written as   ,where   represents the mean of a Normally distributed response variable and x represents the explanatory variable.The parameters   and   are estimated,giving the linear regression model defined by   ,with standard deviation <font face=symbol></font> = 5. What is the range of values for 68% of the observed responses when x = 20 using the 68-95-99.7 rule? ,with standard deviation = 5. What is the range of values for 68% of the observed responses when x = 20 using the 68-95-99.7 rule?

(Multiple Choice)
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There is an old saying in golf: "You drive for show and you putt for dough." The point is that good putting is more important than long driving for shooting low scores and hence winning money.To see if this is the case,data on the top 69 money winners on the PGA tour in 1993 are examined.The average number of putts per hole for each player is used to predict the total winnings (in thousands of dollars)using the simple linear regression model (1993 winnings)i = 0 + 1(average number of putts per hole)i + i, Where the deviations i are assumed to be independent and Normally distributed with a mean of 0 and a standard deviation of .This model was fit to the data using the method of least squares.The following results were obtained from statistical software. There is an old saying in golf: You drive for show and you putt for dough. The point is that good putting is more important than long driving for shooting low scores and hence winning money.To see if this is the case,data on the top 69 money winners on the PGA tour in 1993 are examined.The average number of putts per hole for each player is used to predict the total winnings (in thousands of dollars)using the simple linear regression model (1993 winnings)<sub>i</sub> = <font face=symbol></font><sub>0</sub> + <font face=symbol></font><sub>1</sub>(average number of putts per hole)<sub>i</sub> + <font face=symbol></font><sub>i</sub>, Where the deviations <font face=symbol></font><sub>i</sub><sub> </sub>are assumed to be independent and Normally distributed with a mean of 0 and a standard deviation of <font face=symbol></font>.This model was fit to the data using the method of least squares.The following results were obtained from statistical software.     Suppose the researchers conducting this study wish to estimate the 1993 winnings when the average number of putts per hole is 1.75.The following results were obtained from statistical software.   If the researchers wish to estimate the winnings for a particular tour pro whose average number of putts per hole is 1.75,what would be a 95% prediction interval for the winnings? There is an old saying in golf: You drive for show and you putt for dough. The point is that good putting is more important than long driving for shooting low scores and hence winning money.To see if this is the case,data on the top 69 money winners on the PGA tour in 1993 are examined.The average number of putts per hole for each player is used to predict the total winnings (in thousands of dollars)using the simple linear regression model (1993 winnings)<sub>i</sub> = <font face=symbol></font><sub>0</sub> + <font face=symbol></font><sub>1</sub>(average number of putts per hole)<sub>i</sub> + <font face=symbol></font><sub>i</sub>, Where the deviations <font face=symbol></font><sub>i</sub><sub> </sub>are assumed to be independent and Normally distributed with a mean of 0 and a standard deviation of <font face=symbol></font>.This model was fit to the data using the method of least squares.The following results were obtained from statistical software.     Suppose the researchers conducting this study wish to estimate the 1993 winnings when the average number of putts per hole is 1.75.The following results were obtained from statistical software.   If the researchers wish to estimate the winnings for a particular tour pro whose average number of putts per hole is 1.75,what would be a 95% prediction interval for the winnings? Suppose the researchers conducting this study wish to estimate the 1993 winnings when the average number of putts per hole is 1.75.The following results were obtained from statistical software. There is an old saying in golf: You drive for show and you putt for dough. The point is that good putting is more important than long driving for shooting low scores and hence winning money.To see if this is the case,data on the top 69 money winners on the PGA tour in 1993 are examined.The average number of putts per hole for each player is used to predict the total winnings (in thousands of dollars)using the simple linear regression model (1993 winnings)<sub>i</sub> = <font face=symbol></font><sub>0</sub> + <font face=symbol></font><sub>1</sub>(average number of putts per hole)<sub>i</sub> + <font face=symbol></font><sub>i</sub>, Where the deviations <font face=symbol></font><sub>i</sub><sub> </sub>are assumed to be independent and Normally distributed with a mean of 0 and a standard deviation of <font face=symbol></font>.This model was fit to the data using the method of least squares.The following results were obtained from statistical software.     Suppose the researchers conducting this study wish to estimate the 1993 winnings when the average number of putts per hole is 1.75.The following results were obtained from statistical software.   If the researchers wish to estimate the winnings for a particular tour pro whose average number of putts per hole is 1.75,what would be a 95% prediction interval for the winnings? If the researchers wish to estimate the winnings for a particular tour pro whose average number of putts per hole is 1.75,what would be a 95% prediction interval for the winnings?

(Multiple Choice)
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A random sample of 79 companies from the Forbes 500 list (which actually consists of nearly 800 companies)was selected,and the relationship between sales (in hundreds of thousands of dollars)and profits (in hundreds of thousands of dollars)was investigated by regression.The following results were obtained from statistical software. A random sample of 79 companies from the Forbes 500 list (which actually consists of nearly 800 companies)was selected,and the relationship between sales (in hundreds of thousands of dollars)and profits (in hundreds of thousands of dollars)was investigated by regression.The following results were obtained from statistical software.     What is an approximate 90% confidence interval for the slope <font face=symbol></font><sub>1</sub>? A random sample of 79 companies from the Forbes 500 list (which actually consists of nearly 800 companies)was selected,and the relationship between sales (in hundreds of thousands of dollars)and profits (in hundreds of thousands of dollars)was investigated by regression.The following results were obtained from statistical software.     What is an approximate 90% confidence interval for the slope <font face=symbol></font><sub>1</sub>? What is an approximate 90% confidence interval for the slope 1?

(Multiple Choice)
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A recent study was done to assess factors that put Hispanic populations more at risk for obesity and related chronic diseases,such as diabetes and heart disease,than non-Hispanic populations.Data were collected on several factors,such as the crude morality rate of Hispanics,obesity prevalence,percent of adults diagnosed with diabetes,and median income at the state level.Pearson's Correlations were used to examine the strength of the relationship between obesity and the other variables,as a way of observing which characteristics were associated with high prevalence of obesity.In addition,a simple linear regression was used to model the relationship between diabetes and obesity.The results from SPSS are shown below. A recent study was done to assess factors that put Hispanic populations more at risk for obesity and related chronic diseases,such as diabetes and heart disease,than non-Hispanic populations.Data were collected on several factors,such as the crude morality rate of Hispanics,obesity prevalence,percent of adults diagnosed with diabetes,and median income at the state level.Pearson's Correlations were used to examine the strength of the relationship between obesity and the other variables,as a way of observing which characteristics were associated with high prevalence of obesity.In addition,a simple linear regression was used to model the relationship between diabetes and obesity.The results from SPSS are shown below.         The largest diabetes rate is 14%.What is the predicted obesity rate? A recent study was done to assess factors that put Hispanic populations more at risk for obesity and related chronic diseases,such as diabetes and heart disease,than non-Hispanic populations.Data were collected on several factors,such as the crude morality rate of Hispanics,obesity prevalence,percent of adults diagnosed with diabetes,and median income at the state level.Pearson's Correlations were used to examine the strength of the relationship between obesity and the other variables,as a way of observing which characteristics were associated with high prevalence of obesity.In addition,a simple linear regression was used to model the relationship between diabetes and obesity.The results from SPSS are shown below.         The largest diabetes rate is 14%.What is the predicted obesity rate? A recent study was done to assess factors that put Hispanic populations more at risk for obesity and related chronic diseases,such as diabetes and heart disease,than non-Hispanic populations.Data were collected on several factors,such as the crude morality rate of Hispanics,obesity prevalence,percent of adults diagnosed with diabetes,and median income at the state level.Pearson's Correlations were used to examine the strength of the relationship between obesity and the other variables,as a way of observing which characteristics were associated with high prevalence of obesity.In addition,a simple linear regression was used to model the relationship between diabetes and obesity.The results from SPSS are shown below.         The largest diabetes rate is 14%.What is the predicted obesity rate? A recent study was done to assess factors that put Hispanic populations more at risk for obesity and related chronic diseases,such as diabetes and heart disease,than non-Hispanic populations.Data were collected on several factors,such as the crude morality rate of Hispanics,obesity prevalence,percent of adults diagnosed with diabetes,and median income at the state level.Pearson's Correlations were used to examine the strength of the relationship between obesity and the other variables,as a way of observing which characteristics were associated with high prevalence of obesity.In addition,a simple linear regression was used to model the relationship between diabetes and obesity.The results from SPSS are shown below.         The largest diabetes rate is 14%.What is the predicted obesity rate? The largest diabetes rate is 14%.What is the predicted obesity rate?

(Multiple Choice)
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The following scatter plot and SPSS output represent data collected on 89 middle-aged people.The relationship between body weight and percent body fat is to be studied. The following scatter plot and SPSS output represent data collected on 89 middle-aged people.The relationship between body weight and percent body fat is to be studied.           What is the value of the correlation between body fat and body weight? The following scatter plot and SPSS output represent data collected on 89 middle-aged people.The relationship between body weight and percent body fat is to be studied.           What is the value of the correlation between body fat and body weight? The following scatter plot and SPSS output represent data collected on 89 middle-aged people.The relationship between body weight and percent body fat is to be studied.           What is the value of the correlation between body fat and body weight? The following scatter plot and SPSS output represent data collected on 89 middle-aged people.The relationship between body weight and percent body fat is to be studied.           What is the value of the correlation between body fat and body weight? The following scatter plot and SPSS output represent data collected on 89 middle-aged people.The relationship between body weight and percent body fat is to be studied.           What is the value of the correlation between body fat and body weight? What is the value of the correlation between body fat and body weight?

(Essay)
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There is an old saying in golf: "You drive for show and you putt for dough." The point is that good putting is more important than long driving for shooting low scores and hence winning money.To see if this is the case,data on the top 69 money winners on the PGA tour in 1993 are examined.The average number of putts per hole for each player is used to predict the total winnings (in thousands of dollars)using the simple linear regression model (1993 winnings)i = 0 + 1(average number of putts per hole)i + i, Where the deviations i are assumed to be independent and Normally distributed with a mean of 0 and a standard deviation of .This model was fit to the data using the method of least squares.The following results were obtained from statistical software. There is an old saying in golf: You drive for show and you putt for dough. The point is that good putting is more important than long driving for shooting low scores and hence winning money.To see if this is the case,data on the top 69 money winners on the PGA tour in 1993 are examined.The average number of putts per hole for each player is used to predict the total winnings (in thousands of dollars)using the simple linear regression model (1993 winnings)<sub>i</sub> = <font face=symbol></font><sub>0</sub> + <font face=symbol></font><sub>1</sub>(average number of putts per hole)<sub>i</sub> + <font face=symbol></font><sub>i</sub>, Where the deviations <font face=symbol></font><sub>i</sub><sub> </sub>are assumed to be independent and Normally distributed with a mean of 0 and a standard deviation of <font face=symbol></font>.This model was fit to the data using the method of least squares.The following results were obtained from statistical software.     The following (partial)ANOVA table was obtained from statistical software.   What is the value of the F statistic for testing the hypotheses H<sub>0</sub>: <font face=symbol></font><sub>1</sub> = 0 versus H<sub>a</sub>: <font face=symbol></font><sub>1 </sub><font face=symbol></font> 0? There is an old saying in golf: You drive for show and you putt for dough. The point is that good putting is more important than long driving for shooting low scores and hence winning money.To see if this is the case,data on the top 69 money winners on the PGA tour in 1993 are examined.The average number of putts per hole for each player is used to predict the total winnings (in thousands of dollars)using the simple linear regression model (1993 winnings)<sub>i</sub> = <font face=symbol></font><sub>0</sub> + <font face=symbol></font><sub>1</sub>(average number of putts per hole)<sub>i</sub> + <font face=symbol></font><sub>i</sub>, Where the deviations <font face=symbol></font><sub>i</sub><sub> </sub>are assumed to be independent and Normally distributed with a mean of 0 and a standard deviation of <font face=symbol></font>.This model was fit to the data using the method of least squares.The following results were obtained from statistical software.     The following (partial)ANOVA table was obtained from statistical software.   What is the value of the F statistic for testing the hypotheses H<sub>0</sub>: <font face=symbol></font><sub>1</sub> = 0 versus H<sub>a</sub>: <font face=symbol></font><sub>1 </sub><font face=symbol></font> 0? The following (partial)ANOVA table was obtained from statistical software. There is an old saying in golf: You drive for show and you putt for dough. The point is that good putting is more important than long driving for shooting low scores and hence winning money.To see if this is the case,data on the top 69 money winners on the PGA tour in 1993 are examined.The average number of putts per hole for each player is used to predict the total winnings (in thousands of dollars)using the simple linear regression model (1993 winnings)<sub>i</sub> = <font face=symbol></font><sub>0</sub> + <font face=symbol></font><sub>1</sub>(average number of putts per hole)<sub>i</sub> + <font face=symbol></font><sub>i</sub>, Where the deviations <font face=symbol></font><sub>i</sub><sub> </sub>are assumed to be independent and Normally distributed with a mean of 0 and a standard deviation of <font face=symbol></font>.This model was fit to the data using the method of least squares.The following results were obtained from statistical software.     The following (partial)ANOVA table was obtained from statistical software.   What is the value of the F statistic for testing the hypotheses H<sub>0</sub>: <font face=symbol></font><sub>1</sub> = 0 versus H<sub>a</sub>: <font face=symbol></font><sub>1 </sub><font face=symbol></font> 0? What is the value of the F statistic for testing the hypotheses H0: 1 = 0 versus Ha: 1 0?

(Multiple Choice)
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